Giải
a) \(x+\dfrac{1}{4}=\dfrac{3}{4}\)
=> \(x=\dfrac{3}{4}-\dfrac{1}{4}\)=>\(x=\dfrac{1}{2}\)
b)\(\dfrac{3}{4}-\dfrac{2}{5}x=\dfrac{29}{60}\)
=>\(\dfrac{2}{5}x=\dfrac{3}{4}-\dfrac{29}{60}\)=>\(\dfrac{2}{5}x=\dfrac{4}{15}\)
=>\(x=\dfrac{4}{15}:\dfrac{2}{5}=\dfrac{2}{3}\)
c)\(2x-\dfrac{1}{3}=\dfrac{-5}{6}\)=>\(2x=\dfrac{-5}{6}+\dfrac{1}{3}\)=\(\dfrac{-1}{2}\)
=>\(x=\dfrac{-1}{2}:2=\dfrac{-1}{4}\)
d)\(2-x:\dfrac{3}{4}=\dfrac{1}{2}\)=>\(x:\dfrac{3}{4}=2-\dfrac{1}{2}\)=\(\dfrac{3}{2}\)
=>\(x=\dfrac{3}{2}.\dfrac{3}{4}=\dfrac{9}{8}\)
e)\(\dfrac{11}{12}-\dfrac{2}{3}.\left|x\right|=\dfrac{3}{8}\)=>\(\dfrac{2}{3}.\left|x\right|=\dfrac{11}{12}-\dfrac{3}{8}\)=\(\dfrac{13}{24}\)
=>\(\left|x\right|=\dfrac{13}{24}:\dfrac{2}{3}=\dfrac{13}{16}\)
Vậy: \(x=\dfrac{13}{16}\)hoặc\(x=\dfrac{-13}{16}\)
f)\(\left|2x-1\right|=5\)
*2x-1=5 =>2x=5+1=6 =>x=6:2=3
*2x-1=-5 =>2x=(-5)+1=-4 =>x=-4:2=-2
Vậy: x=3 hoặc x=-2
Tick cho Phong nhé:>
Yêu nhiều>3
#Phong_419