4P+5O₂------>2P₂O₅(1)

nP=\(\frac{6,2}{31}=0,2\left(mol\right)\)

theo (1)nP2o5=0,5.0,2=0,1(mol)

mP2O5=0,1.142=14,2(g)

b)nO2=1,25.0,2=0,25(mol)

VO2(đktc)=0,25.22,4=5,6(l)

4P+5O₂------>2P₂O₅

Áp dụng đlbtkl,ta có:

mP+mO₂=mP₂O₅

_{<=>46,5+O2=106,5}

_=>mO2=60g