Bài 2:
\(A=\left(\frac{x - \sqrt{x}}{x - 1}+\frac{2}{\sqrt{x} + 1}\right):\frac{3}{\sqrt{x} + 2}\quad\) ( Với \(x>0;x\neq1)\)
\(\frac{x - \sqrt{x}}{x - 1} = \frac{\sqrt{x}(\sqrt{x} - 1)}{(\sqrt{x} - 1)(\sqrt{x} + 1)} = \frac{\sqrt{x}}{\sqrt{x} + 1}\)
\(\frac{x - \sqrt{x}}{x - 1} + \frac{2}{\sqrt{x} + 1} = \frac{\sqrt{x} + 2}{\sqrt{x} + 1}\)
\(A = \frac{\sqrt{x} + 2}{\sqrt{x} + 1} \cdot \frac{\sqrt{x} + 2}{3} = \frac{(\sqrt{x} + 2)^2}{3(\sqrt{x} + 1)} = \frac{x + 4\sqrt{x} + 4}{3\sqrt{x} + 3}\)
\(B=\left(\frac{x - 2\sqrt{x}}{x - 4}+\frac{5}{\sqrt{x} + 2}\right):\frac{2}{\sqrt{x} + 5}\quad\) ( Với \(x>0;x\neq1)\)
\(\frac{x - 2\sqrt{x}}{x - 4} = \frac{\sqrt{x}(\sqrt{x} - 2)}{(\sqrt{x} - 2)(\sqrt{x} + 2)} = \frac{\sqrt{x}}{\sqrt{x} + 2}\)
\(\frac{x - 2\sqrt{x}}{x - 4} + \frac{5}{\sqrt{x} + 2} = \frac{\sqrt{x} + 5}{\sqrt{x} + 2}\)
\(B = \frac{\sqrt{x} + 5}{\sqrt{x} + 2} \cdot \frac{\sqrt{x} + 5}{2} = \frac{(\sqrt{x} + 5)^2}{2(\sqrt{x} + 2)} = \frac{x + 10\sqrt{x} + 25}{2\sqrt{x} + 4}\)
\(B=\left(\frac{x - 2\sqrt{x}}{x - 3\sqrt{x}}+\frac{5}{\sqrt{x} - 3}\right):\frac{\sqrt{x} + 2}{\sqrt{x} - 3}\quad\) ( Với \(x>0;x\neq1)\)
\(\frac{x - 2\sqrt{x}}{x - 3\sqrt{x}} = \frac{\sqrt{x}(\sqrt{x} - 2)}{\sqrt{x}(\sqrt{x} - 3)} = \frac{\sqrt{x} - 2}{\sqrt{x} - 3}\)
\(\frac{x - 2\sqrt{x}}{x - 3\sqrt{x}} + \frac{5}{\sqrt{x} - 3} = \frac{\sqrt{x} - 2 + 5}{\sqrt{x} - 3} = \frac{\sqrt{x} + 3}{\sqrt{x} - 3}\)
\(B = \frac{\sqrt{x} + 3}{\sqrt{x} - 3} \cdot \frac{\sqrt{x} - 3}{\sqrt{x} + 2} = \frac{\sqrt{x} + 3}{\sqrt{x} + 2}\)