A

Giả sử \(\left(d'\right):y=ax+b\)

\(\left(d'\right)//\left(d\right)\)

\(\Rightarrow\) phương trình : \(\Leftrightarrow\left\{{}\begin{matrix}a=-1\\b\ne-1\end{matrix}\right.\)

\(\Rightarrow y=-x+b\)

cắt (P)tại diểm có hoành độ =4

\(A=\left(\dfrac{x+8}{\left(\sqrt{x}\right)^3+8}-\dfrac{2}{x-2\sqrt{x}+4}\right):\dfrac{1}{\sqrt{x}-1}\\ =\dfrac{x+8-2.\left(\sqrt{x}+2\right)}{\left(\sqrt{x}+2\right)\left(x-2\sqrt{x}+4\right)}\times\dfrac{\sqrt{x}-1}{1}\\ =\dfrac{x+8-2\sqrt{x}-4}{\left(\sqrt{x}+2\right)\left(x-2\sqrt{x}+4\right)}.\dfrac{\sqrt{x}-1}{1}\\ =\dfrac{x-2\sqrt{x}+4}{\left(\sqrt{x}+2\right)\left(x-2\sqrt{x}+4\right)}.\left(\sqrt{x}-1\right)\\ =\dfrac{\sqrt{x}-1}{\sqrt{x}+2}\)

come back roi a

=> bận thi á :< 

1- My house is bigger than your house

2- is more beautiful than

3- the most interesting

4- longer than 

5- the most dangerous

6- better than 

7- more expensive than 

8- the richest 

9- worse than

10- the cleverest 

1- was

2- weren't

3- were

\(A=\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{9}=\dfrac{2.15+2.9-2.5}{45}=\dfrac{30+18-10}{45}=\dfrac{38}{45}\\ B=\dfrac{4}{3}+\dfrac{4}{5}-\dfrac{4}{9}=\dfrac{4.15+4.9-4.5}{45}=\dfrac{60+36-20}{45}=\dfrac{76}{45}\\ \Rightarrow A:B=\dfrac{38}{45}:\dfrac{76}{45}=\dfrac{38}{76}=\dfrac{1}{2}\)

\(a,35x^2-37x+2=0\\ a+b+c=35+\left(-37\right)+2=0\\ \Rightarrow\left\{{}\begin{matrix}x_1=1\\x_2=\dfrac{c}{a}=\dfrac{2}{35}\end{matrix}\right.\)

\(b,7x^2+500x-507=0\\ \Rightarrow\Delta=500^2-4.7.\left(-507\right)=264196\\ \Rightarrow\left\{{}\begin{matrix}x_1=\dfrac{-500+\sqrt{246196}}{2.7}=1\\x_2=\dfrac{-500-\sqrt{246196}}{2.7}=-\dfrac{507}{7}\end{matrix}\right.\)

\(c,x^2-49x-50=0\\ \Rightarrow a-b+c=0\\ \Rightarrow1-\left(-49\right)+\left(-50\right)=0\\ \Rightarrow\left\{{}\begin{matrix}x_1=-1\\x_2=50\end{matrix}\right.\\ d,4321x^2+21x-4300=0\\ \Rightarrow a-b+c=0\\ \Rightarrow4321-21+\left(-4300\right)=0\\ \Rightarrow\left\{{}\begin{matrix}x_1=-1\\x_2=4300\end{matrix}\right.\)

Sửa nhé mình viết thiếu dấu trừ :C

\(x=\left\{0;-3;1\right\}\)