HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
\(\dfrac{2}{5}-\dfrac{8}{9}\cdot\dfrac{-27}{40}\)
\(=\dfrac{2}{5}-\left(-\dfrac{216}{360}\right)\)
\(=\dfrac{2}{5}+\dfrac{216}{360}\)
\(=\dfrac{2}{5}+\dfrac{3}{5}\)
\(=\dfrac{5}{5}=1\)
\(2\sqrt{5}-3\sqrt{125}+\sqrt{52}-2\sqrt{8}\)
\(=2\sqrt{5}-15\sqrt{5}+2\sqrt{13}-4\sqrt{2}\)
\(=-13\sqrt{5}+2\sqrt{13}-4\sqrt{2}\)
\(\dfrac{1}{2}-\left(40\%-0,75\right)\)
\(=\dfrac{1}{2}-\left(\dfrac{40}{100}-\dfrac{3}{4}\right)\)
\(=\dfrac{1}{2}-\left(\dfrac{2}{5}-\dfrac{3}{4}\right)\)
\(=\dfrac{1}{2}-\left(\dfrac{8}{20}-\dfrac{15}{20}\right)\)
\(=\dfrac{1}{2}-\left(-\dfrac{7}{20}\right)\)
\(=\dfrac{1}{2}+\dfrac{7}{20}\)
\(=\dfrac{10}{20}+\dfrac{7}{20}\)
\(=\dfrac{17}{20}\)
\(3\left(x-1\right)+3=12\)
\(3\left(x-1\right)=12-3=9\)
\(x-1=9:3=3\)
\(x=3+1=4\)