HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
Diện tích :
\(12\times8=96\left(m^2\right)\)
Diện tích trung bình dành cho mỗi hs là :
\(96:96=1\left(m^2\right)\)
\(\dfrac{4}{15}\times\left(\dfrac{5}{3}-\dfrac{1}{4}\right).=..\dfrac{4}{15}\times\dfrac{5}{3}-\dfrac{4}{15}\times\dfrac{1}{4}\)
\(\dfrac{4}{15}\times\left(\dfrac{5}{3}-\dfrac{1}{4}\right)..>..\dfrac{4}{15}\times\dfrac{5}{3}-\dfrac{1}{4}\)
biết r hỏi làm j nửa hả bạn, định buff à:)?
\(\left|2x+1\right|=3\)
\(2x+1=3\)
\(2x+1=-3\)
\(x=1\)
\(x=-2\)
\(x_1=-2,x_2=1\)
\(-\dfrac{5}{6}x< 20\)
\(-\dfrac{6}{5}\times\left(-\dfrac{5}{6}\right)x>-\dfrac{6}{5}\times20\)
\(x>-6\times4\)
\(x>-24\)
\(a,=17+16=33\)
\(b,6.3=18\)
\(c,36-18:6+8=36-3+8=33+8=41\)
\(d,=121-108=13\)
\(A=\dfrac{\sin\left(3\pi-x\right)-\cos\left(\dfrac{3\pi}{2}-3x\right)+\sin4x}{\cos3x-\cos\left(5\pi+x\right)+1+\cos4x}\)
\(A=\dfrac{\sin\left(x\right)-\left(-\sin\left(3x\right)\right)+\sin\left(4x\right)}{\cos\left(3x\right)-\left(-\cos\left(x\right)\right)+1+\cos\left(4x\right)}\)
\(A=\dfrac{\sin\left(x\right)+\sin\left(3x\right)+\sin\left(4x\right)}{\cos\left(3x\right)+\left(-\cos x\right)+1+\cos\left(4x\right)}\)
\(A=\dfrac{\sin\left(x\right)+\sin\left(3x\right)+\sin\left(4x\right)}{\cos\left(3x\right)+\cos\left(x\right)+1+\cos\left(4x\right)}\)
\(^{a,4^6:4^2=4^{6-2}=4^4=256}\)
\(^{b,5^3:125=5^3:5^3=5^{3-3}=0}\)
\(a,\sqrt{\left(2,5\right)^2}=^2\sqrt[]{2,5^2}=2,5=\dfrac{5}{2}\)
\(b,\sqrt{\dfrac{64}{25}}=\dfrac{\sqrt{64}}{\sqrt{25}}=\dfrac{\sqrt{8^2}}{\sqrt{5^2}}=\dfrac{8}{5}=1,6\)
\(A=\dfrac{41580-23100+16170-12474+10164-8580+7425-6545+5852-5292+4830}{27720}\)
\(A=\dfrac{30030}{27720}=\dfrac{13}{12}\)