\(\left\{{}\begin{matrix}\dfrac{2}{x-1}+\dfrac{3}{y+2}=\dfrac{1}{2}\\\dfrac{2}{x-1}-\dfrac{1}{y+2}=\dfrac{1}{18}\end{matrix}\right.\) Làm chi tiết giúp ạ! 

\(\left\{{}\begin{matrix}\dfrac{2}{x-1}+\dfrac{3}{y+2}=\dfrac{1}{2}\\\dfrac{2}{x-1}-\dfrac{1}{y+2}=\dfrac{1}{18}\end{matrix}\right.\)

\(\left\{{}\begin{matrix}2.\left(x+y\right)+3.\left(x-y\right)=4\\\left(x+y\right)+2.\left(x-y\right)=5\end{matrix}\right.\)