29.31.169.\(13^2=25676339=13^4.29.31\)

\(2018^0\left\{15^2:\left[175+2^3.5^2\right]\right\}\\ =1\left\{225:\left[175+8.25\right]\right\}\\ =225:\left[175+200\right]\\ =225:375\\ =\dfrac{3}{5}\)

B

B

Mình trả lời câu này rồi mà!

\(12-\left\{800:\left[537-\left(2^5+15.7\right)\right]\right\}.1^{2021}\\ 12-\left\{800:\left[537-\left(32+105\right)\right]\right\}.1\\ =12-\left\{800:\left[537-137\right]\right\}\\ =12-\left\{800:400\right\}\\ ==12-2\\ =10\)

\(A=1+2+2^2+...+2^{119}\\ =\left(1+2\right)+\left(2^2+2^3\right)+...+\left(2^{118}+2^{119}\right)\\ =\left(1+2\right)+2^2\left(1+2\right)+...+2^{118}\left(1+2\right)\\ =\left(1+2\right)\left(1+2^2+...+2^{118}\right)\\ =3\left(1+2^2+...+2^{118}\right)⋮3\\ \\ A=1+2+2^2+...+2^{119}\\ A=\left(1+2+2^2\right)+...+\left(2^{117}+2^{118}+2^{119}\right)\\ A=\left(1+2+2^2\right)+...+2^{117}\left(1+2+2^2\right)\\ =\left(1+2+2^2\right)\left(1+...+2^{117}\right)\\ =7.\left(1+...+2^{117}\right)⋮7\)

Còn các ý sau bạn tự làm theo cách này tiếp nha!