Tích phân \(\int\limits^2_0\left|1-x\right|\text{d}x\) bằng
\(\dfrac{1}{2}\).\(1\).\(\dfrac{3}{2}\).\(2\).Hướng dẫn giải:\(\int\limits^2_0\left|1-x\right|\text{d}x=\int\limits^1_0\left|1-x\right|\text{d}x+\int\limits^2_1\left|1-x\right|\text{d}x\)
\(=\int\limits^1_0\left(1-x\right)\text{d}x+\int\limits^2_1\left(x-1\right)\text{d}x\)
\(=-\int\limits^1_0\left(1-x\right)\text{d}\left(1-x\right)+\int\limits^2_1\left(x-1\right)\text{d}\left(x-1\right)\)
\(=-\dfrac{1}{2}\left(1-x\right)^2|^1_0+\dfrac{1}{2}\left(x-1\right)^2|^2_1\)
\(=1\).