Kết quả của phép nhân \(\Big(\dfrac{-1}{2}\Big)^3 . \Big(\dfrac{-1}{2}\Big)^2\) là
\(\dfrac{1}{16}\).\(\dfrac{1}{32}\).\(\dfrac{-1}{16}\).\(\dfrac{-1}{32}\).Hướng dẫn giải:\(\Big(\dfrac{-1}{2}\Big)^3 . \Big(\dfrac{-1}{2}\Big)^2=\Big(\dfrac{-1}{2}\Big)^{3+2}=\Big(\dfrac{-1}{2}\Big)^5=\dfrac{-1}{32}\)
