Hệ phương trình \(\left\{{}\begin{matrix}3x+4y=12\\5x-2y=7\end{matrix}\right.\) có nghiệm là
\(\left(x;y\right)=\left(2;\dfrac{3}{2}\right)\).\(\left(x;y\right)=\left(-2;\dfrac{3}{2}\right)\).\(\left(x;y\right)=\left(-2;-\dfrac{3}{2}\right)\).\(\left(x;y\right)=\left(\dfrac{3}{2};2\right)\).