Giải hệ phương trình \(\left\{{}\begin{matrix}-x+2y-3z=2\\2x+y+2z=-3\\-2x-3y+z=5\end{matrix}\right.\) ta được nghiệm
\(\left(x;y;z\right)=\left(-4;\dfrac{11}{7};\dfrac{12}{7}\right)\).\(\left(x;y;z\right)=\left(-4;-\dfrac{11}{7};\dfrac{12}{7}\right)\).\(\left(x;y;z\right)=\left(-4;-\dfrac{11}{7};-\dfrac{12}{7}\right)\).\(\left(x;y;z\right)=\left(4;\dfrac{11}{7};\dfrac{12}{7}\right)\).