tìm x biết
1 1/3 . x + 16 3/4 = 13,25
Câu 4: Tìm x biết :
a, x-\(\dfrac{5}{6}\)=\(\dfrac{1}{2}\) b,3\(\dfrac{1}{3}\)x+16\(\dfrac{3}{4}\)= -13,25
a) \(x-\dfrac{5}{6}=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+\dfrac{5}{6}\)
\(x=\dfrac{4}{3}\)
vậy x = ....
b) \(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\dfrac{10}{3}\)\(x+\dfrac{67}{4}=-13,25\)
\(\dfrac{10}{3}x=\left(-13,25\right)-\dfrac{67}{4}\)
\(\dfrac{10}{3}x=-30\)
\(x=\left(-30\right):\dfrac{10}{3}\)
\(x=-9\)
vậy x =...
sai mog bn thông cảm!!!
Bài 8 : Tìm x , biết :
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
\(\Leftrightarrow\frac{3\times3+1}{3}x+\frac{16\times4+3}{4}=-13,25\)
\(\Leftrightarrow\frac{9+1}{3}x+\frac{64+3}{4}=-13,25\)
\(\Leftrightarrow\frac{10}{3}x+\frac{67}{4}=-13,25\)
\(\Leftrightarrow\frac{10}{3}x+16,75=-13,25\)
\(\Leftrightarrow\frac{10}{3}x=-13,25-16,75\)
\(\Leftrightarrow\frac{10}{3}x=-30\)
\(\Leftrightarrow x=-30\div\frac{10}{3}\)
\(\Leftrightarrow x=\frac{-30}{1}\times\frac{3}{10}\)
\(\Leftrightarrow x=\frac{-90}{10}\)
\(\Leftrightarrow x=-9\)
Tìm x \(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
<=> \(\frac{10}{3}x+\frac{67}{4}=-\frac{53}{4}\)\(\frac{10}{3}x=-\frac{53}{4}-\frac{67}{4}\)=> \(\frac{10}{3}x=-\frac{120}{4}=-30\)
<=> X=(-3)*3 => X=-9
Đáp số: x=-9
giải giúp mik bt này nha,sáng mai mik phải nộp rùi.Thanks các bạn nhìu
Tìm x biết:
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
\(\frac{10}{3}x+\frac{67}{4}=-\frac{53}{4}\)
<=> \(\frac{10}{3}x=-30\)
=> x = -9
Tìm x biết
a)\(\left(7x-11\right)^3=2^5\times5^2+200\)
b)\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
a) (7x - 11)3 = 25 x 52 + 200
(7x - 11)3 = 800 + 200
(7x - 11)3 = 1000
(7x - 11)3 = 103
=> 7x - 11 = 10
=> 7x = 10 + 11
=> 7x = 21
=> x = 3
b) \(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
\(3\frac{1}{3}x=-13,25-16\frac{3}{4}\)
\(\frac{10}{3}x=-30\)
\(x=-9\)
3 1/3 x + 16 3/4 = -13,25
\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\Rightarrow\dfrac{10}{3}x+\dfrac{67}{4}=-\dfrac{53}{4}\)
\(\Rightarrow\dfrac{10}{3}x=-\dfrac{53}{4}-\dfrac{67}{4}\)
\(\Rightarrow\dfrac{10}{3}x=\dfrac{-120}{4}\)
\(\Rightarrow\dfrac{10}{3}x=-30\)
\(\Rightarrow x=-30:\dfrac{10}{3}\)
\(\Rightarrow x=-9\)
Vậy: ...
\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\Leftrightarrow\dfrac{10}{3}x+\dfrac{67}{4}=\dfrac{-53}{4}\)
\(\dfrac{10}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}\)
\(\dfrac{10}{3}x=\dfrac{-120}{4}=-30\)
\(x=-30.\dfrac{3}{10}\)
\(x=\dfrac{-90}{10}=-9\)
\(\dfrac{31}{3}x+16\dfrac{3}{4}=-13,25\)
\(\dfrac{31}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}\)
\(\dfrac{31}{3}x=-30\)
\(\Rightarrow x=-30:\dfrac{31}{3}\)
\(\Rightarrow x=\dfrac{-90}{31}\)
3\(\dfrac{1}{3}\) x- 16\(\dfrac{3}{4}\) = -13,25
Tìm x
A)3 và 1/3 x +16 và 3/4 =- 13,25
B)x/3 - 10/21 =-1/7
C)x-25%x =1/2
D)x:3/4 +1/4= -2/3
Giúp mình với,làm ơn.🙏
Tìm x
A)3 và 1/3 x +16 và 3/4 =- 13,25
B)x/3 - 10/21 =-1/7
C)x-25%x =1/2
D)x:3/4 +1/4= -2/3
Giúp mình với,làm ơn.🙏