\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\Rightarrow\dfrac{10}{3}x+\dfrac{67}{4}=-\dfrac{53}{4}\)
\(\Rightarrow\dfrac{10}{3}x=-\dfrac{53}{4}-\dfrac{67}{4}\)
\(\Rightarrow\dfrac{10}{3}x=\dfrac{-120}{4}\)
\(\Rightarrow\dfrac{10}{3}x=-30\)
\(\Rightarrow x=-30:\dfrac{10}{3}\)
\(\Rightarrow x=-9\)
Vậy: ...
\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\Leftrightarrow\dfrac{10}{3}x+\dfrac{67}{4}=\dfrac{-53}{4}\)
\(\dfrac{10}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}\)
\(\dfrac{10}{3}x=\dfrac{-120}{4}=-30\)
\(x=-30.\dfrac{3}{10}\)
\(x=\dfrac{-90}{10}=-9\)
\(\dfrac{31}{3}x+16\dfrac{3}{4}=-13,25\)
\(\dfrac{31}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}\)
\(\dfrac{31}{3}x=-30\)
\(\Rightarrow x=-30:\dfrac{31}{3}\)
\(\Rightarrow x=\dfrac{-90}{31}\)