= 4x²-y²+8y-16

= 4x²- (y²-8y+16)

= 4x²- (y-4)²

=(4x-y+4) (4x+y-4)

\(1,=x\left(x^2-2x+1-y^2\right)=x\left[\left(x-1\right)^2-y^2\right]=x\left(x-y-1\right)\left(x+y-1\right)\\ 2,=\left(x+y\right)^3\\ 3,=\left(2y-z\right)\left(4x+7y\right)\\ 4,=\left(x+2\right)^2\\ 5,Sửa:x\left(x-2\right)-x+2=0\\ \Leftrightarrow\left(x-2\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)

\(4x^2+4x-3\)

\(4x^2+4x+1-4\)

\(\left(2x+1\right)^2-2^2\)

\(\left(2x+1-2\right)\left(2x+1+2\right)\)

\(\left(2x-1\right)\left(2x+3\right)\)

Trả lời:

4x² + 4x - 3

= [ ( 2x )² + 2.2x.1 + 1 ] - 4

= ( 2x + 1 )² - 4

= ( 2x + 1 - 2 ) ( 2x + 1 + 2 )

= ( 2x - 1 ) ( 2x + 3 )

Giúp mjnh vs mn ơi

\(=4x^2y\left(y^2+1\right)\)

\(4x^4-8x^3+4x^3-8x^2+x^2-2x-2x+4\\ =4x^3\left(x-2\right)+4x^2\left(x-2\right)+x\left(x-2\right)-2\left(x-2\right)\\ =\left(x-2\right)\left(4x^3+4x^2+x-2\right)\\ =\left(x-2\right)\left(4x^3-2x^2+6x^2-3x+4x-2\right)\\ =\left(x-2\right)\left[2x^2\left(2x-1\right)+3x\left(2x-1\right)+2\left(2x-1\right)\right]\\ =\left(x-2\right)\left(2x-1\right)\left(2x^2+3x-2\right)\)

\(4x^2-4x+1=\left(2x\right)^2-2.2x.1+1^2=\left(2x-1\right)^2\\ ---\\ 4x^2-4x-3\\ =4x^2-4x+1-4\\ =\left(2x-1\right)^2-2^2=\left(2x-1-2\right)\left(2x-1+2\right)\\ =\left(2x-3\right)\left(2x+1\right)\)

1: =(2x)^2-2*2x*1+1^2

=(2x-1)^2

2: =4x^2-6x+2x-3

=2x(2x-3)+(2x-3)

=(2x-3)(2x+1)

x(1-2x)(1+2x)

\(=x\left(1-4x^2\right)=x\left(1-2x\right)\left(1+2x\right)\)

\(x^3-4x=x\left(x^2-4\right)=x\left(x+2\right)\left(x-2\right)\)

4x²+4x-3

= 4x²+4x+1-4

=(2x+1)²-2²

=(2x+1-2)(2x+1+2)

=(2x-1)(2x+3)

    \(4x^2+4x-3\)

\(= 4x^2 + 4x + 1 -4\)

\(= ( 2x+1)^2 -2^2\)

\(= (2x+1-2)(2x+1+2)\)

\(= (2x-1)(2x+3)\)

\(x^3+4x^2+4x+1\)

\(=x^3+3x^2+x+x^2+3x+1\)

\(=x\left(x^2+3x+1\right)+\left(x^2+3x+1\right)\)

\(=\left(x+1\right)\left(x^2+3x+1\right)\)