giúp ạaa
Giúp ạaa
giúp ạaa
Giúp với ạaa
Giúp với ạaa
SĐL:
P : AaBb (cao,tròn) x AaBb(cao, tròn)
G AB, Ab,aB, ab AB, Ab, aB, ab
F1: 1AABB : 2 AaBB: 2 AABb : 4 AaBb
1 AAbb : 2 Aabb
1 aaBB : 2 aaBb
1 aabb
TLKG: 9A_B_ : 3A_bb: 3aaB_ : 1 aabb
TLKH : 9 cao, tròn : 3 cao, bầu dục : 3 thấp, tròn : 1 thấp, bầu dục
- Tỉ lệ thân cao, bầu dục dị hợp trong tổng số thân cao, bầu dục là 2/3
- Tỉ lệ thấp, tròn dị hợp trong tổng số thấp, tròn là 2/3
Giúp tớ ạaa
1 ........will be rebuilt next year
2 .......met each other for ten years
3 ..... of Liberty was presented to the United State by France in 1876
4 ........ too high for the children to reach
5 ...... on animals should be stopped
6 ..... her child not to cry
7 .......mind if I turn on the television?
8 ......... rather you didn't use the office phone
9.........asked the students not to throw things away
10 ........ suggest that we go to the movie now
11 ....goes to Ho Chi Minh City in order to visit his friend
12 smoked
13 ..... interesting to learn ENglish
14She shows me where to get the tickets
15 The boy who is talking to Lan is my classmate
16 The wall has been painted white
17 .......told to go away
18 ...... will be looked after carefully
19 She asked me if I was good at Maths
20 They said that they had attended course of cooking
---------------------------------------------------------------------------------
1 without
2 for
-Tham khảo c2 bV
3 at - on
4 of - from
-Tham khảo c4 bV
5 to - on
6 of
7 among
8 of
9 into
10 for
giúp vs ạaa
Bài 1:
\(A=3+3^2+...+3^{100}\)
=>\(3\cdot A=3^2+3^3+...+3^{101}\)
=>\(3A-A=3^2+3^3+...+3^{101}-3-3^2-...-3^{100}\)
=>\(2A=3^{101}-3\)
=>\(2A+3=3^{101}\)
mà \(2A+3=3^n\)
nên n=101
Bài 2:
a: \(M=3+3^2+3^3+3^4+...+3^{100}\)
\(=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^{99}+3^{100}\right)\)
\(=\left(3+3^2\right)+3^2\left(3+3^2\right)+...+3^{98}\left(3+3^2\right)\)
\(=12\left(1+3^2+...+3^{98}\right)⋮12\)
=>\(M=4\cdot3\cdot\left(1+3^2+...+3^{98}\right)⋮4\)
b: \(M=3+3^2+...+3^{100}\)
=>\(3M=3^2+3^3+...+3^{101}\)
=>\(3M-M=3^2+3^3+...+3^{101}-3-3^2-...-3^{100}\)
=>\(2M=3^{101}-3\)
=>\(2M+3=3^{101}\)
=>n=101
giúp gấp ạaa
Bài 4:
a) 2x + 7 ⋮ x + 2
⇒ 2x + 4 + 3 ⋮ x + 2
⇒ 2(x + 2) + 3 ⋮ x + 2
⇒ 3 ⋮ x + 2
⇒ x + 2 ∈ Ư(3) = {1; -1; 3; -3}
⇒ x ∈ {-1; -3; 1; -5}
b) 2x + 7 ⋮ x - 3
⇒ 2x - 6 + 13 ⋮ x - 3
⇒ 2(x - 3) + 13 ⋮ x - 3
⇒ 13 ⋮ x - 3
⇒ x - 3 ∈ Ư(13) = {1; -1; 13; -13}
⇒ x ∈ {4; 2; 16; -10}
Bài 6:
a: \(3x-13⋮x+3\)
=>\(3x+9-22⋮x+3\)
=>\(-22⋮x+3\)
=>\(x+3\in\left\{1;-1;2;-2;11;-11;22;-22\right\}\)
=>\(x\in\left\{-2;-4;-1;-5;8;-14;19;-25\right\}\)
b: \(2x+24⋮x-4\)
=>\(2x-8+32⋮x-4\)
=>\(32⋮x-4\)
=>\(x-4\in\left\{1;-1;2;-2;4;-4;8;-8;16;-16;32;-32\right\}\)
=>\(x\in\left\{5;3;6;2;8;0;12;-4;20;-12;36;-28\right\}\)
Bài 5:
a: \(4x+3⋮x-2\)
=>\(4x-8+11⋮x-2\)
=>\(11⋮x-2\)
=>\(x-2\in\left\{1;-1;11;-11\right\}\)
=>\(x\in\left\{3;1;13;-9\right\}\)
b: \(2x+7⋮x-3\)
=>\(2x-6+13⋮x-3\)
=>\(13⋮x-3\)
=>\(x-3\in\left\{1;-1;13;-13\right\}\)
=>\(x\in\left\{4;2;16;-10\right\}\)
Bài 4:
a: \(2x+7⋮x+2\)
=>\(2x+4+3⋮x+2\)
=>\(3⋮x+2\)
=>\(x+2\in\left\{1;-1;3;-3\right\}\)
=>\(x\in\left\{-1;-3;1;-5\right\}\)
b: \(2x+7⋮x-3\)
=>\(2x-6+13⋮x-3\)
=>\(13⋮x-3\)
=>\(x-3\in\left\{1;-1;13;-13\right\}\)
=>\(x\in\left\{4;2;16;-10\right\}\)
a) 2x + 7 ⋮ x + 2
⇒ 2x + 4 + 3 ⋮ x + 2
⇒ 2(x + 2) + 3 ⋮ x + 2
⇒ 3 ⋮ x + 2
⇒ x + 2 ∈ Ư(3) = {1; -1; 3; -3}
⇒ x ∈ {-1; -3; 1; -5}
b) 2x + 7 ⋮ x - 3
⇒ 2x - 6 + 13 ⋮ x - 3
⇒ 2(x - 3) + 13 ⋮ x - 3
⇒ 13 ⋮ x - 3
⇒ x - 3 ∈ Ư(13) = {1; -1; 13; -13}
⇒ x ∈ {4; 2; 16; -10}
giúp em voi ạaa
Giúp em với ạaa
1 relaxed
2 disastrous
3 inquiry
4 applications
5 shaped
6 examined
7 Careful
8 impressed
25. relaxed
26. disastrous
27. inquiry
28. applications
29. shaped
30. examined
31. Careful
32. impressed