54x(-48)-43x48
bài 48; phân tích các đa thức sau thành nhân tử
5, x mũ 2 - y mũ 2 + 4x + 4
6, x mũ 2 + 2x - 4y mũ 2 - 4y
7, 3x mũ 2 - 4y + 4x - 3y mũ 2
8, x mũ 4 - 6x mũ 3 + 54x - 81
Trả lời:
5, x2 - y2 + 4x + 4
= ( x2 + 4x + 4 ) - y2
= ( x + 2 )2 - y2
= ( x + 2 - y ) ( x + 2 + y )
6, x2 + 2x - 4y2 - 4y
= ( x2 - 4y2 ) + ( 2x - 4y )
= ( x - 2y ) ( x + 2y ) + 2 ( x - 2y )
= ( x - 2y ) ( x + 2y + 2 )
7, 3x2 - 4y + 4x - 3y2
= ( 3x2 - 3y2 ) + ( 4x - 4y )
= 3 ( x2 - y2 ) + 4 ( x - y )
= 3 ( x - y ) ( x + y ) + 4 ( x - y )
= ( x - y ) [ 3 ( x + y ) + 4 ]
= ( x - y ) ( 3x + 3y + 4 )
8, x4 - 6x3 + 54x - 81
= ( x4 - 81 ) - ( 6x3 - 54x )
= ( x2 - 9 ) ( x2 + 9 ) - 6x ( x2 - 9 )
= ( x2 - 9 ) ( x2 + 9 - 6x )
= ( x - 3 ) ( x + 3 ) ( x - 3 )2
= ( x - 3 )3 ( x + 3 )
a, \(x^2-y^2+4x+4=\left(x+2\right)^2-y^2=\left(x+2-y\right)\left(x+2+y\right)\)
b, \(x^2+2x-4y^2-4y=\left(x-2y\right)\left(x+2y\right)+2\left(x-2y\right)=\left(x-2y\right)\left(x+2+2y\right)\)
c, \(3x^2-4y+4x-3y^2=3\left(x-y\right)\left(x+y\right)-4\left(y-x\right)=\left(x-y\right)\left(3x+3y+4\right)\)
d, \(x^4-6x^3+54x-81=\left(x^2+9\right)\left(x-3\right)\left(x+3\right)-6x\left(x^2-9\right)\)
\(=\left(x-3\right)\left(x+3\right)\left(x^2-6x+9\right)=\left(x-3\right)^3\left(x+3\right)\)
5, x2-y2+4x+4
=(x2+4x+4)-y2
=(x+2)2-y2
=(x+2-y)(x+2+y)
6, x2+2x-4y2-4y
=(x2-4y2)+(2x-4y)
=(x-2y)(x+2y)+2(x-2y)
=(x-2y)(x+2y+2)
7, 3x2-4y+4x-3y2
=(3x2-3y2)+(4x-4y)
=3(x2-y2)+4(x-y)
=3(x-y)(x+y)+4(x-y)
=(x-y)[3(x+y)+4]
=(x-y)(3x+3y+4)
8, x4-6x3+54x-81
=(x4-81)-(6x3-54x)
=(x2-9)(x2+9)-6x(x2-9)
=(x2-9)(x2+9-6x)
=(x+3)(x-3)(x-3)2
=(x+3)(x-3)3
#H
Tính nhẩm:
54x 10
54x100
54x1000
108x10
108x100
108x1000
690x10
690x100
690x1000
54x 10 = 540
54x100 = 5400
54x1000 = 540 00
108x10 = 1080
108x100 = 10800
108x1000 = 108000
690x10 = 6900
690x100 = 69000
690x1000 = 690 000
54 x 10 = 540
54 x 100 = 5400
54 x 1000 = 54000
108 x 10 = 1080
108 x 100 = 10800
108 x 1000 = 108000
690 x 10 = 6900
690 x 100 = 69000
690 x 1000 = 690000
`54xx 10 = 540`
`54xx100 = 5400`
`54xx1000 = 540 00`
`108xx10 = 1080`
`108xx100 = 10800`
`108xx1000 = 108000`
`690xx10 = 6900`
`690xx100 = 69000`
`690xx1000 = 690 000`
24xy-54x-28y=718
a)0,8 : (
5
4
x 1,25 + ( 108% -
25
2
) :
3
1
)
0,8 : (54x 1,25 + ( 108% -252) :31)
=0,8 : (67.5 + ( -250,92) :31)
=0,8 : ( 67.5 -250,92 :31)
=0,8 : ( 67.5 -8.09)
=0,8:59.41
=0.0134
Giải hpt:
2x + y = 5
4x - y = 7
\(\left\{{}\begin{matrix}2x+y=5\\4x-y=7\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}4x+2y=10\\4x-y=7\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x+y=5\\\left(4x-4x\right)+\left(2y+y\right)=10-7\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x+y=5\\3y=3\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x+y=5\\y=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x+1=5\\y=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x=4\\y=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\)
Vậy hệ pt có nghiệm duy nhất \(\left(x;y\right)=\left(2;1\right)\)
Viết thành các bình phương
a= x^2 + 54x = 81
b+ 9x^2 +54x + 81
c= y^2 - y + 1/4
d= 16x^6 - 24x^3 +9
b: \(9x^2+54+81=\left(3x+9\right)^2\)
c: \(=\left(y-\dfrac{1}{2}\right)^2\)
d: \(=\left(4x^3-3\right)^2\)
Giải bất phương trình 5 4 x - 6 > 3 3 x - 4
A. x < 6 - 4 log 5 3 4 + 3 log 5 3
B. x < 6 - 4 log 5 3 4 - 3 log 5 3
C. x > 6 - 4 log 5 3 4 - 3 log 5 3
D. x > 6 - 4 log 5 3 4 + 3 log 5 3
Lấy lôgarit theo cơ số 5 hai vế của bất phương trình, ta được:
Chọn C
X x 2+5=54
x bằng bao nhiêu
\(2x+5=54\Leftrightarrow2x=49x=\dfrac{49}{2}\)
\(x\times2+5=54\)
\(x\times2=54-5\)
\(x\times2=49\)
\(x=\dfrac{49}{2}\)
Giải hệ phương trình 2 x + 3 y = 5 4 x - 6 y = - 2
A. ( x ;y) = (1;2).
B. ( x; y) = (2;1).
C. ( x ;y) = (1;1).
D. ( x ; y) = (−1; −1).