\(A=2+2^2+2^3+2^4+...+2^{99}+2^{100}\\ =\left(2+2^2\right)+\left(2^3+2^4\right)+...+\left(2^{99}+2^{100}\right)\\ =\left(2+2^2\right)+2^2\left(2+2^2\right)+...+2^{98}\left(2+2^2\right)\\ =6+2^2.6+...+2^{98}.6\\ =\left(1+2^2+...+2^{98}\right).6⋮6\left(đpcm\right)\)

\(A=2+2^2+2^3+2^4+...+2^{99}+2^{100}\)

\(=\left(2+2^2\right)+\left(2^3+2^4\right)+...+\left(2^{99}+2^{100}\right)\)

\(=6+2^2\left(2+2^2\right)+...+2^{98}\left(2+2^2\right)\)

\(=6\left(1+2^2+....+2^{98}\right)⋮6\)

15B

16A

1. does => doesn't

2. isn't => doesn't

3. go => going

4. spending => spend

1. B

2. C

3. C

4. B

5. A

6. D

7. C

8. C

9. A

10. B

1. B 2. C 3. C 4. B 5. A 6. D 7. C 8. C 9. A 10. B

bn đăng 1 câu 1 lần đăng thôi, dài quá mn ngại ko muốn lm đâu

Câu 1: C

Câu 2: A
Cau 3: C

Câu 8: C

Câu 7: A

Vì `10^n` là số chẵn

`=>10^n-1` là số lẻ 

Mà `2` là số chẵn

`=>(10^n-1)/2` không là số nguyên với `n in NN^{**}` 

1 have played

2 was

3 has Nam watched

4 got - went