Question

giúp tớ vs ạ. thanks

Answer 1

a: 3x+21=57

=>3x=57-21

=>3x=36

=>\(x=\dfrac{36}{3}=12\)

b: \(2x-138=2^3\cdot3^2\)

=>\(2x-138=8\cdot9=72\)

=>2x=72+138=210

=>x=105

c: \(4x^3+12=120\)

=>\(4x^3=120-12=108\)

=>\(x^3=27=3^3\)

=>x=3

Answer 2

Lời giải:

a.

$3x+21=57$

$3x=57-21=36$

$x=36:3=12$

b.

$2x-138=2^3.3^2=8.9=72$

$2x=72+138=210$

$x=210:2=105$

c.

$4x^3+12=120$

$4x^3=120-12=108$

$x^3=108:4=27=3^3$

$x=3$

Answer 3

\(a)3x+21=57\\ \Leftrightarrow3x=57-21\\ \Leftrightarrow3x=36\\ \Leftrightarrow x=\dfrac{36}{3}\\ \Leftrightarrow x=12\\ b)2x-138=2^3\cdot3^2\\ \Leftrightarrow2x-138=72\\ \Leftrightarrow2x=72+138\\ \Leftrightarrow2x=210\\ \Leftrightarrow x=\dfrac{210}{2}\\ \Leftrightarrow x=105\\ c)4x^3+12=120\\ \Leftrightarrow4x^3=120-12\\ \Leftrightarrow4x^3=108\\ \Leftrightarrow x^3=\dfrac{108}{4}\\ \Leftrightarrow x^3=27\\ \Leftrightarrow x^3=3^3\\ \Leftrightarrow x=3.\)