gõ latex đi bn!

a. 2^x + 70 = 74

<=> 2^x = 4

<=> x = 2

b. 120 - \(\dfrac{4x}{2}\) = 80

<=> 120 - 2x = 80

<=> 120 - 80 = 2x

<=> 2x = 40

<=> x = 20

c. (3x + 5)² = 400

<=> \(|3x+5|=\sqrt{400}\)

<=> \(|3x+5|=20\)

<=> \(\left[{}\begin{matrix}3x+5=20\\3x+5=-20\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=\dfrac{-25}{3}\end{matrix}\right.\) 

a) 2x - 20 = x + 30

2x - x = 30 + 20

x = 50

b) 5x - 30 + 4x = 60

9x = 60 + 30

9x = 90

x = 90 : 9

x = 10

a) 2x - 20 = x + 30

2x - x = 30 + 20

x = 50

b) 5x - 30 + 4x = 60

9x = 60 + 30

9x = 90

x = 90 : 9

x = 10

\(2.x-20=x+30\)

\(2.x=x+30-20\)

\(2.x=x+10\)

\(x=10\)

a)1008

b)22530

c)1028,4

d)16900

a, 1008

b, 22530

c, 1028,4

d, 16900

a) 1008

b) 22530

c) 1028,4

d) 16900

a)13,2 - x = -4,3

=> x = 13,2 - ( -4,3)

=> x = 17,5

b)x phần 3 = 20 phần 15 

\(\dfrac{x}{3}=\dfrac{20}{15}=>20.3=x.15=>60=x.15=>x=60:15=>x=4\)

c) 2 phần 3 - 1 phần 3 x = -5 phần 3 + 1 phần 2

Mong bạn viết lại đề giúp mình

d) x - 3 phần 5 = -7 phần 10

\(\dfrac{x-3}{5}=\dfrac{-7}{10}=>5.-7=\left(x-3\right).10=>-35=\left(x-3\right).10=>x-3=-35:10=>x-3=\text{-3,5}=>x=\text{-3,5}+3=>x=6,5\)

`a)`

`13,2-x=-4,3`

`x=13,2-(-4,3)`

`x=17,5`

Vậy `x=17,5`

__________________________

`b)`

\(\dfrac{x}{3}=\dfrac{20}{15}\)

`=>x` `xx15=20xx3`

`x` `xx15=60`

`x=60:15`

`x=4`

Vậy `x=4`

__________________________

`c)`

\(\dfrac{2}{3}-\dfrac{1}{3x}=\dfrac{-5}{3}+\dfrac{1}{2}\\ \dfrac{2}{3}-\dfrac{1}{3x}=-\dfrac{7}{6}\\ \dfrac{1}{3x}=\dfrac{2}{3}-\left(-\dfrac{7}{6}\right)\\ \dfrac{1}{3x}=\dfrac{11}{6}\\ \Rightarrow1\times6=11\times3\times x\\ 6=33\times x\\ x=5,5\)

Vậy `x=5,5`

__________________________

`d)`

\(\dfrac{x-3}{5}=\dfrac{-7}{10}\)

`=>(x-3)xx10=5xx(-7)`

`(x-3)xx10=-35`

`x-3=-35:10`

`x-3=-3,5`

`x=-6,5`

Vậy `x=-6,5`

`@An`

a: \(x\cdot3\cdot5=2,7\)

=>\(x\cdot15=2,7\)

=>\(x=\dfrac{2,7}{15}=0,18\)

b: \(1,2:x\cdot4=20\)

=>\(1,2:x=20:4=5\)

=>\(x=1,2:5=0,24\)

a) (5 + x)(x - 5) - x(x + 5) = 10

x² - 25 - x² - 5x = 10

-5x = 10 + 25

-5x = 35

x = 35 : (-5)

x = -7

b) x.(2x + 3) - 2(x² + x) = 2

2x² + 3x - 2x² - 2x = 2

x = 2

a: \(\left(x+5\right)\left(x-5\right)-x\left(x+5\right)=10\)

=>\(x^2-25-x^2-5x=10\)

=>-5x-25=10

=>-5x=35

=>x=-7

b: \(x\left(2x+3\right)-2\left(x^2+x\right)=2\)

=>\(2x^2+3x-2x^2-2x=2\)

=>x=2

a. `4x^2-20x+25=0`

`<=>(2x)^2-2.2x.5 +5^2=0`

`<=>(2x-5)^2=0`

`<=>2x-5=0`

`<=>x=5/2`

b. `(x-5)(x+5)-(x-3)^2=2(x-7)`

`<=>x^2-25-x^2+6x-9=2x-14`

`<=>6x-34=2x-14`

`<=>4x=20`

`<=>x=5`

\(a,4x^2-20x+25=0\Leftrightarrow\left(2x\right)^2-2.2x.5+5^2=0\)

\(\Leftrightarrow\left(2x-5\right)^2=0\Leftrightarrow x=\dfrac{5}{2}\)

b, \(\left(x-5\right)\left(x+5\right)-\left(x-3\right)^2=2\left(x-7\right)\)

\(\Leftrightarrow x^2-25-x^2+6x-9=2x-14\Leftrightarrow4x=20\Leftrightarrow x=5\)

a) Có: (2x)² - 2.2.5.x + 5² = 0

          ⇒ (2x - 5)² = 0 ⇒ 2x - 5 = 0

          ⇒ 2x = 5 ⇒ x = \(\dfrac{5}{2}\)

b) Có: x² - 25 - x² + 6x - 9 = 2x - 14

           ⇒ 6x - 36 = 2x - 14

           ⇒ 4x = 22

           ⇒ x = \(\dfrac{11}{2}\)

\(-\dfrac{8}{11}.x=\dfrac{2}{5}.\dfrac{1}{4}\)

\(-\dfrac{8}{11}.x=\dfrac{2}{20}\)

\(-\dfrac{8}{11}.x=\dfrac{1}{10}\)

\(x=\dfrac{1}{10}:-\dfrac{8}{11}\)

\(x=-\dfrac{11}{81}\)

Chọn d

D nha