Literature is my favorite subject.

I like literature the most

\(a,A=0,2\left(5x-1\right)-\dfrac{1}{2}\left(\dfrac{2}{3}x+4\right)+\dfrac{2}{3}\left(3-x\right)\)

\(=x-0,2-\dfrac{1}{3}x-2+2-\dfrac{2}{3}x\)

\(=\left(-0,2-2+2\right)+\left(x-\dfrac{1}{3}x-\dfrac{2}{3}x\right)\)

\(=-0,2\)

\(b,B=\left(x-2y\right)\left(x^2+2xy+4y^2\right)-\left(x^3-8y^3+10\right)\)

\(=x^3-8y^3-x^3+8y^3-10\)

\(=-10\)

\(c,C=4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x-1\right)\left(x+1\right)-4x\)

\(=4\left(x^2+2x+1\right)+\left(4x^2-4x+1\right)-8\left(x^2-1\right)-4x\)

\(=4x^2+8x+4+4x^2-4x+1-8x^2+8-4x\)

\(=13\)

a) \(A=0,2\left(5x-1\right)-\dfrac{1}{2}\left(\dfrac{2}{3}x+4\right)+\dfrac{2}{3}\left(3-x\right)\)

\(A=x-\dfrac{1}{5}-\dfrac{1}{3}x-2+2-\dfrac{2}{3}x\)

\(A=\left(x-\dfrac{1}{3}x-\dfrac{2}{3}x\right)-\left(\dfrac{1}{5}+2-2\right)\)

\(A=-\dfrac{1}{5}\)

Vậy: ...

b) \(B=\left(x-2y\right)\left(x^2+2xy+4y^2\right)-\left(x^3-8y^3+10\right)\)

\(B=\left[x^3-\left(2y\right)^3\right]-\left[x^3-\left(2y\right)^3\right]-10\)

\(B=-10\)

Vậy: ...

c) \(4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x+1\right)\left(x-1\right)-4x\)

\(=4\left(x^2+2x+4\right)+\left(4x^2-4x+1\right)-8\left(x^2-1\right)-4x\)

\(=4x^2+8x+4+4x^2-4x+1-8x^2+8-4x\)

\(=\left(4x^2+4x^2-8x^2\right)+\left(8x-4x-4x\right)+\left(4+1+8\right)\)

\(=13\)

Vậy:...

=x−0,2−13x−2+2−23x=�−0,2−13�−2+2−23�

đề bài đâu bạn

e: \(=\left|3-\sqrt{2}\right|=3-\sqrt{2}\)

h: \(=3-\sqrt{2}+3+\sqrt{2}=6\)

g: \(=\left|0.1-\sqrt{0.1}\right|=0.1-\sqrt{0.1}\)

i: \(=\left|2\sqrt{2}-3\right|=3-2\sqrt{2}\)

c: \(=\left|2+5\right|=7\)

o: \(=5-2\sqrt{6}-5-2\sqrt{6}=-4\sqrt{6}\)

n: \(=4-2\sqrt{3}+4+2\sqrt{3}=8\)

m: \(=7+2\sqrt{10}-7-2\sqrt{10}=0\)

Bài 2: 

a: \(f\left(x\right)=-9x^3-2x^2+6x-3\)

\(G\left(x\right)=9x^3-6x+53\)

b: \(H\left(x\right)=9x^3-6x+53-9x^3-2x^2+6x-3=-2x^2+50\)

c: Đặt H(x)=0

=>2x²-50=0

=>x=5 hoặc x=-5

\(\left(7\dfrac{4}{9}+4\dfrac{7}{11}\right)-3\dfrac{4}{9}\)

\(=\dfrac{67}{9}+\dfrac{51}{11}-\dfrac{31}{9}\)

\(=\dfrac{67}{9}-\dfrac{31}{9}+\dfrac{51}{11}\)

\(=4+\dfrac{51}{11}\)

\(=\dfrac{95}{11}\)

Chúc bạn học tốt

\(\Delta=\left(-73\right)^2-4.6.123=5329-2952=2377\)

\(\Rightarrow\left\{{}\begin{matrix}x_1=\dfrac{73+\sqrt{2377}}{12}\\x_2=\dfrac{73-\sqrt{2377}}{12}\end{matrix}\right.\)

6x² - 73x + 123 = 0

\(\rightarrow\)vô nghiệm

Để giải phương trình bậc 2 một ẩn, em có thể theo dõi video bài giảng sau trên OLM nhé: Công thức nghiệm của phương trình bậc hai