Tính:
a) \(\dfrac{9}{5}+\dfrac{2}{5}\times\dfrac{4}{6}\)
b) \(\dfrac{3}{8}\times2-\dfrac{6}{7}\times\dfrac{1}{3}\)
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SGK Kết nối tri thức với cuộc sống - Trang 87
24 tháng 8 2023 lúc 11:49
Tính (theo mẫu).Mẫu: 5timesdfrac{2}{9}dfrac{5}{1}timesdfrac{2}{9}dfrac{5times2}{1times9}dfrac{10}{9}Ta có thể viết gọn như sau:5timesdfrac{2}{9}dfrac{5times2}{9}dfrac{10}{9} a) 3timesdfrac{4}{11} b) 1timesdfrac{5}{4} c) 0timesdfrac{2}{5}
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Tính (theo mẫu).
Mẫu: \(5\times\dfrac{2}{9}=\dfrac{5}{1}\times\dfrac{2}{9}=\dfrac{5\times2}{1\times9}=\dfrac{10}{9}\) Ta có thể viết gọn như sau: \(5\times\dfrac{2}{9}=\dfrac{5\times2}{9}=\dfrac{10}{9}\) |
a) \(3\times\dfrac{4}{11}\) b) \(1\times\dfrac{5}{4}\) c) \(0\times\dfrac{2}{5}\)
a) \(3\times\dfrac{4}{11}=\dfrac{3\times4}{11}=\dfrac{12}{11}\)
b) \(1\times\dfrac{5}{4}=\dfrac{1\times5}{4}=\dfrac{5}{4}\)
c) \(0\times\dfrac{2}{5}=\dfrac{0\times2}{5}=\dfrac{0}{5}=0\)
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a: \(=\dfrac{3\cdot4}{11}=\dfrac{12}{11}\)
b: \(=\dfrac{1\cdot5}{4}=\dfrac{5}{4}\)
c: \(=\dfrac{0\cdot2}{5}=0\)
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SGK Cánh Diều - Tập 2 - Trang 72
31 tháng 10 2023 lúc 22:15
Tính:
a) \(\dfrac{2}{5}\times\dfrac{3}{8}\times\dfrac{3}{4}\) b) \(\dfrac{1}{3}\times\dfrac{1}{6}\times\dfrac{1}{9}\)
c) \(\dfrac{3}{4}:\dfrac{1}{5}:\dfrac{7}{8}\) d) \(\dfrac{3}{5}:\dfrac{1}{5}:\dfrac{1}{8}\)
a) $\frac{2}{5} \times \frac{3}{8} \times \frac{3}{4} = \frac{{2 \times 3 \times 3}}{{5 \times 8 \times 4}} = \frac{{18}}{{160}} = \frac{9}{{80}}$
b) $\frac{1}{3} \times \frac{1}{6} \times \frac{1}{9} = \frac{{1 \times 1 \times 1}}{{3 \times 6 \times 9}} = \frac{1}{{162}}$
c) $\frac{3}{4}:\frac{1}{5}:\frac{7}{8} = \frac{3}{4} \times \frac{5}{1} \times \frac{8}{7} = \frac{{3 \times 5 \times 8}}{{4 \times 1 \times 7}} = \frac{{120}}{{28}} = \frac{{30}}{7}$
d) $\frac{3}{5}:\frac{1}{5}:\frac{3}{8} = \frac{3}{5} \times \frac{5}{1} \times \frac{8}{3} = \frac{{3 \times 5 \times 8}}{{5 \times 1 \times 3}} = 8$
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Tính
a, 4timesleft(-dfrac{1}{2}right)^3-2timesleft(-dfrac{1}{2}right)^2+3timesleft(-dfrac{1}{2}right)+1
b, dfrac{4^6times9^5+6^9times120}{-8^4times3^{12}+6^{11}}
c, dfrac{155-dfrac{10}{7}-dfrac{5}{11}+dfrac{5}{23}}{403-dfrac{26}{7}-dfrac{13}{11}+dfrac{12}{23}}+dfrac{dfrac{3}{5}+dfrac{3}{13}-0,9}{dfrac{7}{91}+0,2-dfrac{3}{10}}
d,dfrac{30times4^7times3^{29}-5times14^5times2^{12}}{54times6^{14}times9^7-12times8^5times7^5}
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Tính
a, 4\(\times\left(-\dfrac{1}{2}\right)^3-2\times\left(-\dfrac{1}{2}\right)^2+3\times\left(-\dfrac{1}{2}\right)+1\)
b, \(\dfrac{4^6\times9^5+6^9\times120}{-8^4\times3^{12}+6^{11}}\)
c, \(\dfrac{155-\dfrac{10}{7}-\dfrac{5}{11}+\dfrac{5}{23}}{403-\dfrac{26}{7}-\dfrac{13}{11}+\dfrac{12}{23}}+\dfrac{\dfrac{3}{5}+\dfrac{3}{13}-0,9}{\dfrac{7}{91}+0,2-\dfrac{3}{10}}\)
d,\(\dfrac{30\times4^7\times3^{29}-5\times14^5\times2^{12}}{54\times6^{14}\times9^7-12\times8^5\times7^5}\)
a, \(4\times\left(-\dfrac{1}{2}\right)^3-2\times\left(-\dfrac{1}{2}\right)^2+3\times\left(-\dfrac{1}{2}\right)+1\)
\(=\left(-\dfrac{1}{2}\right)\left[\left(4\times-\dfrac{1}{2}\right)-\left(2\times-\dfrac{1}{2}\right)+3\right]+1\)
\(=\left(-\dfrac{1}{2}\right)\left(-2+1+3\right)+1\)
\(=\left(-\dfrac{1}{2}\right)2+1\)
\(=-1+1\)
\(=0\)
@Trịnh Thị Thảo Nhi
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a, 4×(−12)3−2×(−12)2+3×(−12)+14×(−12)3−2×(−12)2+3×(−12)+1
=(−12)[(4×−12)−(2×−12)+3]+1=(−12)[(4×−12)−(2×−12)+3]+1
=(−12)(−2+1+3)+1=(−12)(−2+1+3)+1
=(−12)2+1=(−12)2+1
=−1+1=−1+1
=0=0
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17 tháng 5 2022 lúc 19:22
Đặt tính rồi tính :
\(a.\dfrac{5}{6}+\dfrac{2}{5}\)
\(b.\dfrac{6}{5}-\dfrac{3}{4}\)
\(c.\dfrac{9}{16}\times\dfrac{4}{3}\)
\(d.\dfrac{8}{17}:6\)
a: =25/30+12/30=37/30
b: =24/20-15/20=9/20
c: =36/48=3/4
d: =8/17x1/6=8/102=4/51
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a) \(\dfrac{25}{30}+\dfrac{12}{30}=\dfrac{37}{30}\)
b) \(\dfrac{24}{20}-\dfrac{15}{20}=\dfrac{9}{20}\)
c) \(\dfrac{36}{48}=\dfrac{3}{4}\)
d) \(\dfrac{8}{17}\times\dfrac{1}{6}=\dfrac{8}{102}=\dfrac{4}{51}\)
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\(\dfrac{5}{6}+\dfrac{2}{5}=\dfrac{25}{30}+\dfrac{12}{30}=\dfrac{37}{30}\)
\(\dfrac{6}{5}-\dfrac{3}{4}=\dfrac{24}{20}-\dfrac{15}{20}=\dfrac{9}{20}\)
\(\dfrac{9}{16}\times\dfrac{4}{3}=\dfrac{36}{48}\)
\(\dfrac{8}{17}:6=\dfrac{8}{102}\)
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SGK Kết nối tri thức với cuộc sống - Trang 57
23 tháng 8 2023 lúc 22:54
Số?
a) \(\dfrac{2}{5}=\dfrac{2\times?}{5\times?}=\dfrac{10}{25}\) \(\dfrac{4}{7}=\dfrac{4\times2}{7\times?}=\dfrac{?}{?}\)
b) \(\dfrac{36}{40}=\dfrac{36:?}{40:?}=\dfrac{9}{10}\) \(\dfrac{24}{32}=\dfrac{24:?}{32:8}=\dfrac{?}{?}\)
a) \(\dfrac{2}{5}=\dfrac{2\times5}{5\times2}=\dfrac{10}{25}\)
\(\dfrac{4}{7}=\dfrac{4\times2}{7\times2}=\dfrac{8}{14}\)
b) \(\dfrac{36}{40}=\dfrac{36:4}{40:4}=\dfrac{9}{10}\)
\(\dfrac{24}{32}=\dfrac{24:8}{32:8}=\dfrac{3}{4}\)
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SGK Cánh diều - Tập 2 - Trang 92
2 tháng 11 2023 lúc 17:17
Tính:
a) \(\dfrac{2}{3}\times\dfrac{5}{8}+\dfrac{7}{4}\) b) \(\dfrac{8}{5}:\left(\dfrac{4}{3}-\dfrac{5}{6}\right)\) c) \(\dfrac{3}{4}\times\dfrac{1}{5}-\dfrac{1}{10}\)
a) $\frac{3}{2} \times \frac{5}{8} + \frac{7}{4} = \frac{{15}}{{16}} + \frac{7}{4} = \frac{{15}}{{16}} + \frac{{28}}{{16}} = \frac{{43}}{{16}}$
b) $\frac{8}{5}:\left( {\frac{4}{3} - \frac{5}{6}} \right) = \frac{8}{5}:\left( {\frac{8}{6} - \frac{5}{6}} \right) = \frac{8}{5}:\frac{1}{2} = \frac{8}{5} \times 2 = \frac{{16}}{5}$
c) $\frac{3}{4} \times \frac{1}{5} - \frac{1}{{10}} = \frac{3}{{20}} - \frac{1}{{10}} = \frac{3}{{20}} - \frac{2}{{20}} = \frac{1}{{20}}$
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26 tháng 1 2022 lúc 20:28
A = \(\dfrac{-19}{9}\times\dfrac{1}{2}-\dfrac{4}{11}\times\dfrac{-11}{9}+\left(-\dfrac{2}{3}\right)\)
B = \(\left(-\dfrac{15}{6}\right)\div\dfrac{-1}{2}+\dfrac{7}{-12}-\dfrac{1}{3}\times\dfrac{-11}{2}\)
C = \(\dfrac{3}{4}\times\left(-8\right)-\dfrac{1}{3}\times\dfrac{-7}{2}-\dfrac{5}{18}\)
\(A=\dfrac{-19}{9}.\dfrac{1}{2}-\dfrac{4}{11}.\dfrac{-11}{9}+\left(-\dfrac{2}{3}\right)=-\dfrac{23}{18}\)
\(B=\left(-\dfrac{15}{6}\right):\dfrac{-1}{2}+\dfrac{7}{-12}-\dfrac{1}{3}.\dfrac{-11}{2}=\dfrac{25}{4}\)
\(C=\dfrac{3}{4}.\left(-8\right)-\dfrac{1}{3}.\dfrac{-7}{2}-\dfrac{5}{18}=-\dfrac{46}{9}\)
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\(A=\dfrac{-19}{18}+\dfrac{4}{9}-\dfrac{2}{3}=\dfrac{-19}{18}+\dfrac{8}{18}-\dfrac{12}{18}=\dfrac{-23}{18}\)
\(B=\dfrac{-5}{2}\cdot\dfrac{-2}{1}-\dfrac{7}{12}+\dfrac{11}{6}=\dfrac{5\cdot12-7+22}{12}=\dfrac{75}{12}=\dfrac{25}{4}\)
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SGK Kết nối tri thức với cuộc sống - Trang 87
24 tháng 8 2023 lúc 11:34
Tính.
a) \(\dfrac{4}{7}\times\dfrac{3}{5}\) b) \(\dfrac{1}{3}\times\dfrac{9}{10}\) c) \(\dfrac{1}{6}\times\dfrac{1}{4}\)
a) \(\dfrac{4}{7}\times\dfrac{3}{5}=\dfrac{4\times3}{7\times5}=\dfrac{12}{35}\)
b) \(\dfrac{1}{3}\times\dfrac{9}{10}=\dfrac{1\times9}{3\times10}=\dfrac{9}{30}=\dfrac{3}{10}\)
c) \(\dfrac{1}{6}\times\dfrac{1}{4}=\dfrac{1}{4\times6}=\dfrac{1}{24}\)
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SGK Kết nối tri thức với cuộc sống - Trang 87
24 tháng 8 2023 lúc 11:36
Rút gọn rồi tính.
a) \(\dfrac{2}{4}\times\dfrac{9}{5}\) b) \(\dfrac{13}{8}\times\dfrac{5}{15}\) c) \(\dfrac{3}{9}\times\dfrac{6}{12}\)
a) \(\dfrac{2}{4}\times\dfrac{9}{5}=\dfrac{1}{2}\times\dfrac{9}{5}=\dfrac{1\times9}{2\times5}=\dfrac{9}{10}\)
b) \(\dfrac{13}{8}\times\dfrac{5}{15}=\dfrac{13}{8}\times\dfrac{1}{3}=\dfrac{13}{24}\)
c) \(\dfrac{3}{9}\times\dfrac{6}{12}=\dfrac{1}{3}\times\dfrac{1}{2}=\dfrac{1}{3\times2}=\dfrac{1}{6}\)
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a: =18/20=9/10
b: \(=\dfrac{13\cdot5}{8\cdot15}=\dfrac{13}{8}\cdot\dfrac{1}{3}=\dfrac{13}{24}\)
c: \(=\dfrac{1}{3}\cdot\dfrac{1}{2}=\dfrac{1}{6}\)
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