\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)

\(\Rightarrow\dfrac{10}{3}x+\dfrac{67}{4}=-\dfrac{53}{4}\)

\(\Rightarrow\dfrac{10}{3}x=-\dfrac{53}{4}-\dfrac{67}{4}\)

\(\Rightarrow\dfrac{10}{3}x=\dfrac{-120}{4}\)

\(\Rightarrow\dfrac{10}{3}x=-30\)

\(\Rightarrow x=-30:\dfrac{10}{3}\)

\(\Rightarrow x=-9\)

Vậy: ...

\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)

\(\Leftrightarrow\dfrac{10}{3}x+\dfrac{67}{4}=\dfrac{-53}{4}\)

\(\dfrac{10}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}\)

\(\dfrac{10}{3}x=\dfrac{-120}{4}=-30\)

\(x=-30.\dfrac{3}{10}\)

\(x=\dfrac{-90}{10}=-9\)

\(\dfrac{31}{3}x+16\dfrac{3}{4}=-13,25\)

\(\dfrac{31}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}\)

\(\dfrac{31}{3}x=-30\)

\(\Rightarrow x=-30:\dfrac{31}{3}\)

\(\Rightarrow x=\dfrac{-90}{31}\)

Đề bài thế này đúng ko: 3. 1/3y + 16. 3/4 = -13,25

3 . 1/3 y + 16.3/4=-13,25

y + 12 = -13,25

y = -13,25 -12

y= -25,25

Giải:

3 1/3y + 16 3/4 = -13,25

10/3y + 67/4 = -53/4

10/3y            = -53/4 - 67/4

10/3y            = -30

       y            = -30 : 10/3

       y            =-9

Chúc bạn học tốt!

=>10/3x=3,5

=>x=21/20

10/3 y + 67/4= -1325/100

10/3y= -1325/100 - 1675/100

10/3y = -3000/100

10/3y = 30

y= 30 : 10/3

y=9

10/3y+67/4=-1325/100

10/3y=-1235/100-67/4

10/3y=-30

y=-30:10/3

y=-9

Vậyy=-9

Mik làm giống với bạn "ko quan tâm" nhưng kết quả ra -1. Mik hỏi cô rồi, đúng đó. Chúc bạn học tốt !

a) (7x - 11)³ = 2⁵.5² + 200

(7x - 11)³ = 32.25 + 200

(7x - 11)³ = 800 + 200

(7x - 11)³ = 1000 = 10³

=> 7x - 11 = 10

=> 7x = 10 + 11 = 21

=> x = 21 : 7 = 3

b) \(1\frac{1}{3}x+16\frac{3}{4}=-13,25\)

=> \(\frac{4}{3}x+\frac{67}{4}=-\frac{53}{4}\)

=> \(\frac{4}{3}x=-\frac{53}{4}-\frac{67}{4}\)

=> \(\frac{4}{3}x=-30\)

=> \(x=-30:\frac{4}{3}\)

=> \(x=-30.\frac{3}{4}=-\frac{45}{2}\)

\(1\frac{1}{3}\cdot x+16\frac{3}{4}=13,25\)

\(\frac{4}{3}\cdot x=13,25-16\frac{3}{4}\)

\(\frac{4}{3}\cdot x=-3,5\)

\(x=-3,5:\frac{4}{3}\)

\(x=-2,625\)

\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)

\(=>\frac{10}{3}x+\frac{67}{4}=\frac{-53}{4}\)

\(\frac{10}{3}x=-30\)

x = -30 : \(\frac{10}{3}\)

= > x = -9

a) \(x-\dfrac{5}{6}=\dfrac{1}{2}\)

           \(x=\dfrac{1}{2}+\dfrac{5}{6}\)

           \(x=\dfrac{4}{3}\)

vậy x = ....

b) \(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)

    \(\dfrac{10}{3}\)\(x+\dfrac{67}{4}=-13,25\)

     \(\dfrac{10}{3}x=\left(-13,25\right)-\dfrac{67}{4}\)

      \(\dfrac{10}{3}x=-30\)

          \(x=\left(-30\right):\dfrac{10}{3}\)

         \(x=-9\)

vậy x =...

sai mog bn thông cảm!!!