\(a)\left(80\times96+40\times1808\right):1000\)

\(=\left(80\times96+40\times2\times904\right):1000\)

\(=\left(80\times96+80\times904\right):1000\)

\(=80\times\left(96+904\right):1000\)

\(=80\times1000:1000\)

\(=80\)

\(b)\) em xem lại đề xem có sai gì không em.

\(c)10\times12\times14\times16\times\left(88\times17-44\times34\right)\)

\(=10\times12\times14\times16\times\left(44\times2\times17-44\times2\times17\right)\)

\(=10\times12\times14\times16\times0\)

\(=0\)

\(a,A=\left(\dfrac{x+14\sqrt{x}-5}{x-25}+\dfrac{\sqrt{x}}{\sqrt{x}+5}\right):\dfrac{\sqrt{x}+2}{\sqrt{x}-5}\)

\(\Rightarrow A=\left(\dfrac{x+14\sqrt{x}-5}{\left(\sqrt{x}+5\right)\left(\sqrt{x}-5\right)}+\dfrac{\sqrt{x}\left(\sqrt{x}-5\right)}{\left(\sqrt{x}+5\right)\left(\sqrt{x}-5\right)}\right).\dfrac{\sqrt{x}-5}{\sqrt{x}+2}\)

\(\Rightarrow A=\left(\dfrac{x+14\sqrt{x}-5}{\left(\sqrt{x}+5\right)\left(\sqrt{x}-5\right)}+\dfrac{x-5\sqrt{x}}{\left(\sqrt{x}+5\right)\left(\sqrt{x}-5\right)}\right).\dfrac{\sqrt{x}-5}{\sqrt{x}+2}\)

\(\Rightarrow A=\dfrac{x+14\sqrt{x}-5+x-5\sqrt{x}}{\left(\sqrt{x}+5\right)\left(\sqrt{x}-5\right)}.\dfrac{\sqrt{x}-5}{\sqrt{x}+2}\)

\(\Rightarrow A=\dfrac{2x+9\sqrt{x}-5}{\left(\sqrt{x}+5\right)\left(\sqrt{x}-5\right)}.\dfrac{\sqrt{x}-5}{\sqrt{x}+2}\)

\(\Rightarrow A=\dfrac{2x+10\sqrt{x}-\sqrt{x}-5}{\left(\sqrt{x}+5\right)\left(\sqrt{x}+2\right)}\)

\(\Rightarrow A=\dfrac{2\sqrt{x}\left(\sqrt{x}+5\right)-\left(\sqrt{x}+5\right)}{\left(\sqrt{x}+5\right)\left(\sqrt{x}+2\right)}\)

\(\Rightarrow A=\dfrac{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+5\right)}{\left(\sqrt{x}+5\right)\left(\sqrt{x}+2\right)}\)

\(\Rightarrow A=\dfrac{2\sqrt{x}-1}{\sqrt{x}+2}\)

\(\frac{12}{99}\)x9+90/99

giải bình thường!

\(B=\left(4^5\cdot10\cdot5^6+25^5\cdot2^8\right):\left(2^8\cdot5^4+5^7\cdot2^5\right)\)

\(B=\dfrac{4^5\cdot10\cdot5^6+25^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)

\(B=\dfrac{\left(2^2\right)^5\cdot2\cdot5\cdot5^6+\left(5^2\right)^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)

\(B=\dfrac{2^{11}\cdot5^7+5^{10}\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)

\(B=\dfrac{2^8\cdot5^7\cdot\left(2^3\cdot1+5^3\cdot1\right)}{2^5\cdot5^4\cdot\left(2^3\cdot1+5^3\cdot1\right)}\)

\(B=\dfrac{2^8\cdot5^7}{2^5\cdot5^4}\)

\(B=\dfrac{2^3\cdot5^3}{1\cdot1}\)

\(B=\left(2\cdot5\right)^3\)

\(B=10^3\)

\(B=1000\)

=-42x100=-4200

=-42x100=-4200

=-42x100=-4200

a) 40 - x = 54

x = 40 - 54

x = -14

b) 36 - x = -11

x = 36 - (-11)

x = 47

c) 2.x - 3 = -14

2x = -14 + 3

2x = -11

x = -11/2

1. 3x - 36 = 12 . 75 + 25 . 12

    3x - 36 = 12 . (75+25)

    3x - 36 = 12 . 100

    3x - 36 = 1200

    3x = 1200 + 36

    3x = 1236

=>  x = 1236 : 3 = 412

câu 1 thôi nhá bạn

3x - 36 = 12 . 75 + 25 . 12

3x - 36 = 12 . (75 + 25)

3x - 36 = 1200

3x = 1164

x = 388

x : 2 - 12 = 33 . 40 + 33 . 59 + 33

x : 2 - 12 = 33 . 40 + 33 . 59 + 33 . 1

x : 2 - 12 = (40 + 59 + 1)

x : 2 - 12 = 3300

x : 2 = 3288

x = 1644

(x - 4) . (9 - x) = 0

Thỏa mãn điều kiện\(\hept{\begin{cases}x=4\\x=9\end{cases}}\)

(x - 6) . (2020 - x) = 0

Thỏa mãn điều kiện\(\hept{\begin{cases}x=6\\x=2020\end{cases}}\)

x . (6 - x) = 0

Thỏa mãn điều kiện 6 - x = 0 

x = 6

(x - 3 - 12) . (20 - x) = 0

Thỏa mãn điều kiện \(x\le20\); 20 - x = 0

x = 20

Mình làm câu khó thôi nhé.

2x chia hết cho 3

=>(2x+x-x) chia hết cho 3

=>(3x-x) chia hết cho 3

3x chia hết cho 3=>x chia hết cho 3

=>x thuộc B(3)={0;3;6;...}

Vậy x thuộc {0;3;6;...ư}

Bổ sung: vì 0<x<40=>x thuộc {3;6;9;...:39}

a) Các ước của -12: 1;-1;2;-2;3;-3;4;-4;6;-6;12;-12

Vậy x\(\in\left\{1;-1;2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)

b) (-300):20+5.(3x-1)=25

    (-15) + 5.(3x-1)     = 25

               5.(3x-1)      = 25-(-15)

               5.(3x-1)      = 40

                   3x-1        = 40:5                   

                   3x-1        = 8

                   3x           = 8+1

                   3x           = 9

                     x           = 9:3

                     x           = 3

Vậy x=3

c) 2x \(⋮\) 3

=>(2x+x-x) \(⋮\) 3

=>(3x-x) \(⋮\) 3

3x \(⋮\) 3=>x \(⋮\) 3

=>x \(\in\) B(3)={0;3;6;...}

Vậy x \(\in\) {0;3;6;...}

TICK VÀ LIKE NHA. CẢM ƠN