1: \(x-9=\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)\)

2: \(x-16=\left(\sqrt{x}-4\right)\left(\sqrt{x}+4\right)\)

3: \(9x-1=\left(3\sqrt{x}-1\right)\left(3\sqrt{x}+1\right)\)

4: \(x\sqrt{x}+1=\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)\)

\(1,x-9=\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)\\ 2,x-16=\left(\sqrt{x}-4\right)\left(\sqrt{x}+4\right)\\ 3,9x-1=\left(3\sqrt{x}-1\right)\left(3\sqrt{x}+1\right)\\ 4,x\sqrt{x}+1=\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)\)

 1,x−9=(√x−3)(√x+3)

2,x−16=(√x−4)(√x+4)

3,9x−1=(3√x−1)(3√x+1)

4,x√x+1=(√x+1)(x−√x+1

Biểu thức không thể phân tích nhân tử với các số hữu tỉ

Nguyễn Nhật Nguyên :được nhé bạn ! hệ số khủng quá,đại ý là thế này:

Mọi đa thức dạng \(x^{3m+1}+x^{3n+2}+1\) đều có nhân tử là \(x^2+x+1\)

\(x^{16}+x^{14}+1\)

\(=\left(x^{16}-x\right)+\left(x^{14}-x^2\right)+x^2+x+1\)

\(=x\left(x^{15}-1\right)+x^2\left(x^{12}-1\right)+x^2+x+1\) 

\(=x\left[\left(x^3\right)^5-1\right]+x^2\left[\left(x^3\right)^4-1\right]+x^2+x+1\)

Đến đây bạn rảnh bạn làm mik nốt nha,khá là dài

\(x^2\left(x-1\right)+16\left(1-x\right)\)

\(=x^2\left(x-1\right)-16\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2-4^2\right)\)

\(=\left(x-1\right)\left(x-4\right)\left(x-4\right)\)

=x²(x-1)-16(x-1)

=(x-1) (x²-16)

=(x-1)(x-4)(x+4)

\(x^2\left(x-1\right)+16\left(1-x\right)\)

\(=x^2\left(x-1\right)-16\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2-4^2\right)\)

\(=\left(x-1\right)\left(x-4\right)\left(x-4\right)\)

\(\left(x+2\right)^2-16\\ \backslash=\left(x+2-4\right)\left(x+2+4\right)\\ =\left(x-2\right)\left(x+6\right)\)

(x+2)²-4²=(x+2-4)(x+2+4)

 ( x + 2) ² - 16

= (x+2)² -  4²

= (x+2-4) . (x+2+4)

= (x -2) . (x+6) 

\(a,5x^3y-10x^2y^2\\=5x^2y(x-2y)\\b,x^4-y^4\\=(x^2)^2-(y^2)^2\\=(x^2-y^2)(x^2+y^2)\\=(x-y)(x+y)(x^2+y^2)\)

\(c,(x+5)^2-16\\=(x+5)^2-4^2\\=(x+5-4)(x+5+4)\\=(x+1)(x+9)\\d,7x(y-3)-14(3-y)\\=7x(y-3)+14(y-3)\\=(7x+14)(y-3)\\=7(x+2)(y-3)\\Toru\)

A

D bạn nhé

x 16 + x 8 − 2 = ( x 8 ) 2 + x 8 − 2 = ( x 8 − 1 ) ( x 8 + 2 ) = ( x 4 − 1 ) ( x 4 + 1 ) ( x 8 + 2 ) = ( x 2 − 1 ) ( x 2 + 1 ) ( x 4 + 1 ) ( x 8 + 2 ) = ( x − 1 ) ( x + 1 ) ( x 2 + 1 ) ( x 4 + 1 ) ( x 8 + 2 )

\(=\left(x-4\right)\left(x+4\right)\)

x²-16=x²-4²=(x-4)(x+4)

Cho xin 1 tick

= x^2 - 4^2

= ( x - 4 )(x + 4 )

56.B

57.B

58.B

56B

57B

58B

\(\left(x+y\right)^2-16\)

\(=\left(x+y\right)^2-4^2\)

\(=\left[\left(x+y\right)-4\right]\left[\left(x+y\right)+4\right]\)

\(=\left(x+y-4\right)\left(x+y+4\right)\)