có dấu  mk vik bị lộn nha

a) \(\dfrac{2x+3}{-4}\)≥\(\dfrac{4-x}{-3}\)

=> 3(2x+3)≥4(4-x)

<=> 6x+9≥16-4x

<=> 10x ≥ 7

<=> x ≥\(\dfrac{7}{10}\)

=>5(7x-1)+60x=6(16-x)

=>35x-5+60x-96+6x=0

=>101x=101

hay x=1

\(\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\)

\(\Leftrightarrow\dfrac{5\left(7x-1\right)}{30}+\dfrac{60x}{30}=\dfrac{6\left(16-x\right)}{30}\)

\(\Leftrightarrow5\left(7x-1\right)+60x=6\left(16-x\right)\)

\(\Leftrightarrow35x-5+60x=96-6x\)

\(\Leftrightarrow95x-5-96+6x=0\)

\(\Leftrightarrow101x-101=0\\ \Leftrightarrow101x=101\\ \Leftrightarrow x=1\)

\(\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\)

\(\Leftrightarrow\dfrac{5\left(7x-1\right)}{30}+\dfrac{60x}{30}=\dfrac{6\left(16-x\right)}{30}\)

\(\Leftrightarrow5\left(7x-1\right)+60x=6\left(16-x\right)\)

\(\Leftrightarrow35x-5+60x=96-6x\)

\(\Leftrightarrow101x=101\)

\(\Leftrightarrow x=1\)

Vậy: Phương trình có tập nghiệm \(S=\left\{1\right\}\)

a: \(\Leftrightarrow x-5-2\left(2x-1\right)< 12\)

=>x-5-4x+2<12

=>-3x-3<12

=>-3x<15

hay x>-5

b: \(\Leftrightarrow4\left(5x^2-3\right)+5\left(3x-1\right)>10x\left(2x+3\right)-100\)

\(\Leftrightarrow20x^2-12+15x-5-20x^2-30x+100>0\)

=>-15x+83>0

hay x<83/15

Đáp án: 

\(\dfrac{\left(7x-1\right).5}{6.5}+\dfrac{2x.30}{30}=\dfrac{\left(16-x\right).6}{5.6}\)

khử mẫu

=>(7x-1).5+60x=(16-x).6

=>35x-5+60x=96-6x

=>35x-5+60x-96+6x=0

=>101x-101=0

=>x=1

=>

a.\(\dfrac{3}{2\left(x+3\right)}-\dfrac{x-6}{2x\left(x+3\right)}=\dfrac{3x-x+6}{2x\left(x+3\right)}=\dfrac{2x+6}{2x\left(x+3\right)}=\dfrac{1}{x}\)

=>5(7x-1)+60x=6(16-x)

=>35x-5+60x=96-6x

=>95x-5=96-6x

=>101x=101

=>x=1

a: =>10x-14=15-9x

=>19x=29

hay x=29/19

b: \(\Leftrightarrow3\left(10x+3\right)=36+4\left(8x+6\right)\)

=>30x+9=36+32x+24

=>30x+9=32x+60

=>-2x=51

hay x=-51/2

c: \(\Leftrightarrow5\left(7x-1\right)+60x=6\left(16-x\right)\)

=>35x-5+60x=96-6x

=>101x=101

hay x=1

d: \(\Leftrightarrow12\left(\dfrac{1}{2}-\dfrac{3}{2}x\right)=-5x+6\)

\(\Leftrightarrow6-18x+5x-6=0\)

=>-13x=0

hay x=0

\(a,\dfrac{5x-7}{3}=\dfrac{5-3x}{2}\\ \Leftrightarrow2\left(5x-7\right)=3\left(5-3x\right)\\ \Leftrightarrow10x-14=15-9x\\ \Leftrightarrow10x-14-15+9x=0\\ \Leftrightarrow19x-19=0\\ \Leftrightarrow x=1\)

\(b,\dfrac{10x+3}{12}=1+\dfrac{6+8x}{9}\\ \Leftrightarrow\dfrac{3\left(10x+3\right)}{36}=\dfrac{36}{36}+\dfrac{4\left(6+8x\right)}{36}\\ \Leftrightarrow30x+9=36+24+32x\\ \Leftrightarrow36+24+32x-30x-9=0\\ \Leftrightarrow2x+51=0\\ \Leftrightarrow x=-\dfrac{51}{2}\)

\(c,\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\\ \Leftrightarrow\dfrac{7x-1+12x}{6}=\dfrac{16-x}{5}\\ \Leftrightarrow5\left(19x-1\right)=6\left(16-x\right)\\ \Leftrightarrow95x-5=96-6x\\ \Leftrightarrow95x-5-96+6x=0\\ \Leftrightarrow101x-101=0\\ \Leftrightarrow x=1\)

\(d,4\left(0,5-1,5x\right)=-\dfrac{5x-6}{3}\\ \Leftrightarrow12\left(0,5-1,5x\right)=6-5x\\ \Leftrightarrow6-18x=6-5x\\ \Leftrightarrow6-5x-6+18x=0\\ \Leftrightarrow13x=0\\ \Leftrightarrow x=0\)

\(\dfrac{3x-2}{4}-x< \dfrac{x+2}{5}\\ \Leftrightarrow\dfrac{5\left(3x-2\right)}{20}-\dfrac{20x}{20}-\dfrac{4\left(x+2\right)}{20}< 0\\ \Leftrightarrow15x-10-20x-4x-8< 0\\ \Leftrightarrow-9x-18< 0\\ \Leftrightarrow-9x< 18\\ \Leftrightarrow x>-2\)