=>5(7x-1)+60x=6(16-x)
=>35x-5+60x-96+6x=0
=>101x=101
hay x=1
\(\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\)
\(\Leftrightarrow\dfrac{5\left(7x-1\right)}{30}+\dfrac{60x}{30}=\dfrac{6\left(16-x\right)}{30}\)
\(\Leftrightarrow5\left(7x-1\right)+60x=6\left(16-x\right)\)
\(\Leftrightarrow35x-5+60x=96-6x\)
\(\Leftrightarrow95x-5-96+6x=0\)
\(\Leftrightarrow101x-101=0\\ \Leftrightarrow101x=101\\ \Leftrightarrow x=1\)
\(\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\)
\(\Leftrightarrow\dfrac{5\left(7x-1\right)}{30}+\dfrac{60x}{30}=\dfrac{6\left(16-x\right)}{30}\)
\(\Leftrightarrow5\left(7x-1\right)+60x=6\left(16-x\right)\)
\(\Leftrightarrow35x-5+60x=96-6x\)
\(\Leftrightarrow101x=101\)
\(\Leftrightarrow x=1\)
Vậy: Phương trình có tập nghiệm \(S=\left\{1\right\}\)
