3.a

4.b

5.a

6.b

7.c

8.a

9.a

10.b

3A

4B

5A

6B

7C

8C

9A

10B

Chúc bn học giỏi

\(a,\Delta'=\left[-\left(m+1\right)\right]^2-\left(m^2-4m+3\right)\\ =m^2+2m+1-m^2+4m-3\\ =6m-2\)

Để pt vô nghiệm thì \(6m-2< 0\Leftrightarrow m< \dfrac{1}{3}\)

Để pt có nghiệm kép thì \(6m-2=0\Leftrightarrow m=\dfrac{1}{3}\)

Để pt có 2 nghiệm phân biệt thì \(6m-2>0\Leftrightarrow m>\dfrac{1}{3}\)

\(b,\Delta=\left(m-3\right)^2-4.\left(-3m\right)\\ =m^2-6m+9+12m\\ =m^2+6m+9\\ =\left(m+3\right)^2\ge0\)

Suy ra pt luôn không vô nghiệm với mọi m

PT có nghiệm kép khi \(\left(m+3\right)^2=0\Leftrightarrow m=-3\)

PT có 2 nghiệm phân biệt khi \(\left(m+3\right)^2>0\Leftrightarrow m\ne-3\)

a: =>x=13/52+8/52=21/52

b: =>x=1/36-27/36=-26/36=-13/18

c: =>x=24/60+15/60-20/60=19/60

d: =>x/15=9/15-10/15=-1/15

=>x=-1

a, x = 21/52 ; b x = -13/18 

c, x = 19/60 ; d, x = -1 

tui mới lớp 4

a, ta có A(x)=2x³+7x²+ax+b

                   =(2x³+2x²+2x)+(5x²+5x+5)+ax-7x+b-5

                   =2x(x²+x+1)+5(x²+x+1)+(a-7)x+(b-5)

                   =(x²+x+1)(2x+5)+(a-7)x+(b-5)

ta có: (x²+x+1)(2x+5)⋮B(x)

→để A(x)⋮B(x) thì (a-7)x+(b-5)=0

→\(\left\{{}\begin{matrix}a-7=0\\b-5=0\end{matrix}\right.\) ⇔\(\left\{{}\begin{matrix}a=7\\b=5\end{matrix}\right.\)

vậy ....

mk trình bày hơi tắt xíu 

bn cố gắng dịch nhé

a) \(A\left(x\right)=2x^3+7x^2+ax+b=\left(x^2+x-1\right)\left(2x+5\right)+\left(a-3\right)x+b+5\)

\(=\left(2x+5\right)B\left(x\right)+\left(a-3\right)x+b+5\)

Để \(A\left(x\right)\) chia hết cho \(B\left(x\right)\) thì 

\(\left(a-3\right)x+b+5=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}a-3=0\\b+5=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=3\\b=-5\end{matrix}\right.\)

b) \(A\left(x\right)=ax^3+bx-24=\left(ax-4a\right)\left(x^2+4x+3\right)+\left(b+13a\right)x+12a-24\)

\(=\left(ax-4a\right)\left(x^2+4x+3\right)+\left(b+13a\right)x+12a-24\)

Để \(A\left(x\right)\) chia hết cho \(B\left(x\right)\) thì 

\(\left(b+13a\right)x+12a-24=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}b+13a=0\\12a-24=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=2\\b=-26\end{matrix}\right.\)

c) Tương tự. 

1. you be quiet, you'll hear the sound.

2. I am short, I can't become a model.

3. you don't run quickly, you can't catch the bus.

4. Jack doesn't pass the exam, his parents will be sad.

5. you don't be hurry, you'll be late.

6. they don't tell the truth, we can't know about this.

7. you speak slowly, I'll understand you.

Từ giả thiết, suy ra: \(\hat{M}=\dfrac{3}{2}\hat{P}\).

Ta có: \(\hat{D}+\hat{M}+\hat{P}=180^o\) (tổng 3 góc trong một tam giác)

\(\Leftrightarrow55^o+\dfrac{3}{2}\hat{P}+\hat{P}=180^o\Leftrightarrow\hat{P}=50^o\)

\(\Rightarrow\hat{M}=\dfrac{3}{2}\hat{P}=\dfrac{3}{2}\cdot50^o=75^o\)

vcl