P=2010 - (x+1)2008
Những câu hỏi liên quan
- Giải phương trình: \(\frac{x-2009-2010}{2008}+\frac{x-2008-2010}{2009}+\frac{x-2008-2009}{2010}=3\)
\(\frac{x-2009-2010}{2008}+\frac{x-2008-2010}{2009}+\frac{x-2008-2009}{2010}=3\)
\(\Leftrightarrow\frac{x-2008-2009-2010}{2008}+\frac{x-2008-2009-2010}{2009}+\frac{x-2008-2009-2010}{2010}=0\)
\(\Leftrightarrow\left(x-2008-2009-2010\right)\left(\frac{1}{2008}-\frac{1}{2009}-\frac{1}{2010}\right)=0\)
\(\Leftrightarrow x-6027=0\Leftrightarrow x=6027\)
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Bài 5:1/2+1/3+...+1/2008).x=2009/1+2010/2+2011/3+5016/2008-2008
\(\dfrac{x+1}{2010}+\dfrac{x+2}{2009}+\dfrac{x-3}{2008}+...+\dfrac{x-2009}{2}+\dfrac{x-2010}{1}=-2010\)
\(\Leftrightarrow\dfrac{x+1}{2010}+1+\dfrac{x+2}{2009}+1+...+\dfrac{x+2009}{2}+1+\dfrac{x+2010}{1}+1=0\)
=>x+2011=0
hay x=-2011
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Tìm x thỏa mãn: x + (x + 1) + (x + 2) + … + 2009 + 2010 = 2010 A.-2010 B.-2008 C.0 D.-2009
(1+1/2+1/3+...+1/2008).X=2009/1+2010/2+2011/3+...+5016/2008-2008)
giúp mình vs mình đag cần gấp
\(\frac{2009}{1}+\frac{2010}{2}+...+\frac{5016}{2008-2008}\)
\(=\frac{2009}{1}+\frac{2010}{2}+...+\frac{5016}{0}\)
Sau đó QĐM(bạn tự QĐ nha)
\(=\frac{0}{0}+\frac{0}{0}+...+\frac{5016}{0}\)
\(=\frac{5016}{0}=0\)
\(\Rightarrow\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2008}\right).x=0\)
Mà \(\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2008}\right)\ne0\)
\(\Rightarrow x=0\)
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Câu 1: So sánh các số hữu tỉ:
A = 2006/2007 - 2007/2008 + 2008/2009 - 2009/2010 với B = -1/2006 x 2007 - (-1)/2007 x 2008
2-x/2008 - 1 = 1-x/2009 - x/2010
So sánh: x = 2006/2007 - 2007/2008 + 2008/2009 - 2009/2010.
y = - 1/(2006 × 2007) - 1/(2007 × 2008).
Ta có:
\(x=\dfrac{2006}{2007}-\dfrac{2007}{2008}+\dfrac{2008}{2009}-\dfrac{2009}{2010}\)
\(=\dfrac{2006.2008-2007^2}{2007.2008}+\dfrac{2008.2010-2009^2}{2009.2010}\)
\(=\dfrac{2006.2007+2006-2007^2}{2007.2008}+\dfrac{2008.2009+2008-2009^2}{2009.2010}\)
\(=\dfrac{2007\left(2006-2007\right)+2006}{2007.2008}+\dfrac{2009\left(2008-2009\right)+2008}{2009.2010}\)
\(=\dfrac{-1}{2007.2008}+\dfrac{-1}{2008.2010}< \dfrac{-1}{2006.2007}+\dfrac{1}{2007.2008}\)
\(\Rightarrow x< y\)
Vậy x < y
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a) 2010/1+2009/2+2008/3+ ... +1/2010+2010 : 1+1/2+1/3+ ... +1/2010=
b) 1/2011+1/2010+1/2009+ ... +1/3+1/2 : 2010/1+2009/2+2008/3+ ... +1/2010=
so sánh A và B
biết A=2010^2008+1/ 2010^2009+1
B=2010^2007+1/ 2010^2008+1
A =\(\frac{2010^{2008}+1}{2010^{2009}+1}\)\(\Rightarrow2010A=\frac{2010^{2009}+2010}{2010^{2009}+1}=1+\frac{2009}{2010^{2009}+1}\)
\(B=\frac{2010^{2007}+1}{2010^{2008}+1}\Rightarrow2010B=\frac{2010^{2008}+2010}{2010^{2008}+1}=1+\frac{2009}{2010^{2008}+1}\)
Vì 2009 = 2009( tử số bằng nhau); \(2010^{2009}+1>2010^{2008}+1\)( mẫu số của A>B)
=> \(\frac{2010^{2008}+1}{2010^{2009}+1}< \frac{2010^{2007}+1}{2010^{2008}+1}\)
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