-52 + \(\frac{2}{3}\)x X = -46

\(\frac{2}{3}\)X = \(-46+52\)

\(\frac{2}{3}x=6\)

\(x=6:\frac{2}{3}=9\)

2 / 3 x X = -46 -- 52

2/3 xX = 6

X = 6 : 2/3

X = 9

\(-52+\frac{2}{3}x=-46\)

\(\frac{2}{3}x=-46-\left(-52\right)\)

\(\frac{2}{3}x=6\)

\(x=6:\frac{2}{3}\)

\(x=9\)

\(\frac{2}{3}\)X=-46-(-52)

\(\frac{2}{3}\)X=6

X=6chia \(\frac{2}{3}\)

X=9

- 52 + 2/3x = - 46

          2/3x = - 46 + 52 = 6

              x  =  6 : 2/3

              x  =  9

a: Sai

b: S

c: Đ

d: S

a,S

b,S

c,Đ

d,S

a) S

b) S

c) Đ

d) S

a)\(x=52-25=27\)

b)\(x=\left(46-8\right)+34=38+34=72\)

a/ X= 27

b/ X= 72

a/ X= 27

b/ X= 72

a) 25 + 5 x 5 = 25 + 25

                  = 50

b) 160 – 48 : 4 = 160 - 12

                  = 148

c) 732 + 46 : 2 = 732 + 23

                  = 755

d) 974 – 52 x 3 = 974 – 156

                  = 818

kt bn hok

\(-52+\frac{2}{3}x=-46\)

\(\frac{2}{3}x=-46+52\)

\(\frac{2}{3}x=6\)

\(x=6:\frac{2}{3}\)

\(x=9\)

x=9 nha bn

đúng nha

Happy new year!!

\(-52+\frac{2}{3}x=-46\)

\(\Rightarrow\frac{2}{3}x=-46-\left(-52\right)\)

\(\Rightarrow\frac{2}{3}x=6\)

\(\Rightarrow x=9\)

A,B,D,E :Sai

C,G,Y :Đúng

A: Đ

B: Đ 

C: S

D: Đ

E: Đ

G: S

Y: S

_HT_  NHAAAAA

A,B,D,E :đúng

C,G,Y :sai

a) \(\frac{x+1}{9}+\frac{x+2}{8}=\frac{x+3}{7}+\frac{x+4}{6}\)

\(\Rightarrow\left(\frac{x+1}{9}+1\right)+\left(\frac{x+2}{8}+2\right)=\left(\frac{x+3}{7}+1\right)+\left(\frac{x+4}{6}+1\right)\)

\(\Rightarrow\frac{x+10}{9}+\frac{x+10}{8}-\frac{x+10}{7}-\frac{x+10}{6}=0\)

\(\Rightarrow\left(x+10\right)\left(\frac{1}{9}+\frac{1}{8}-\frac{1}{7}-\frac{1}{6}\right)=0\)

Mà \(\frac{1}{9}+\frac{1}{8}-\frac{1}{7}-\frac{1}{6}\ne0\)

\(\Rightarrow x+10=0\)

\(\Rightarrow x=-10\)

Vậy x = -10

b) \(\frac{x+43}{57}+\frac{x+46}{54}=\frac{x+49}{51}+\frac{x+52}{48}\)

\(\Rightarrow\left(\frac{x+43}{57}+1\right)+\left(\frac{x+46}{54}+1\right)=\left(\frac{x+49}{51}+1\right)+\left(\frac{x+52}{48}+1\right)\)

\(\Rightarrow\frac{x+100}{57}+\frac{x+100}{54}=\frac{x+100}{51}+\frac{x+100}{48}\)

\(\Rightarrow\frac{x+100}{57}+\frac{x+100}{54}-\frac{x+100}{51}-\frac{x+100}{48}=0\)

\(\Rightarrow\left(x+100\right)\left(\frac{1}{57}+\frac{1}{54}-\frac{1}{51}-\frac{1}{48}\right)=0\)

Mà \(\frac{1}{57}+\frac{1}{54}-\frac{1}{51}-\frac{1}{48}\ne0\)

\(\Rightarrow x+100=0\)

\(\Rightarrow x=-100\)

Vậy x = -100

a.\(\frac{x+1}{9}+\frac{x+2}{8}=\frac{x+3}{7}+\frac{x+4}{6}\)

=>\(\frac{x+1}{9}+1+\frac{x+2}{8}+1=\frac{x+3}{7}+1+\frac{x+4}{6}+1\)

<=> \(\frac{x+1+9}{9}+\frac{x+2+8}{8}=\frac{x+3+7}{7}+\frac{x+4+6}{6}\)

<=>\(\frac{x+10}{9}+\frac{x+10}{8}=\frac{x+10}{7}+\frac{x+10}{6}\)

<=> \(\frac{x+10}{9}+\frac{x+10}{8}-\frac{x+10}{7}-\frac{x+10}{6}=0\)

<=> \(\left(x+10\right)\left(\frac{1}{9}+\frac{1}{8}-\frac{1}{7}-\frac{1}{6}\right)=0\)

<=> x+10=0

<=> x=-10

Vậy tập nghiệm của phương trình trên là S=\(\left\{-10\right\}\)

b. \(\frac{x+43}{57}+\frac{x+46}{54}=\frac{x+49}{51}+\frac{x+52}{48}\)

=> \(\frac{x+43}{57}+1+\frac{x+46}{54}+1=\frac{x+49}{51}+1+\frac{x+52}{48}+1\)<=>\(\frac{x+43+57}{57}+\frac{x+46+54}{54}=\frac{x+49+51}{51}+\frac{x+52+48}{48}\)​

<=>\(\frac{x+100}{57}+\frac{x+100}{54}=\frac{x+100}{51}+\frac{x+100}{48}\)

<=>\(\frac{x+100}{57}+\frac{x+100}{54}-\frac{x+100}{51}-\frac{x+100}{48}=0\)

<=>(x+100)\(\left(\frac{1}{57}+\frac{1}{54}-\frac{1}{51}-\frac{1}{48}\right)\)=0

<=>x+100=0

<=>x= -100

Vậy tập nghiệm của phương trình trên là S=\(\left\{-100\right\}\)

\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)

\(\frac{x}{27}=\frac{6}{18}-\frac{2}{9}\)

\(\frac{x}{27}=\frac{3}{9}-\frac{2}{9}\)

\(\frac{x}{27}=\frac{1}{9}\)

\(\frac{x}{27}=\frac{3}{27}\)

\(x=3\)

Ấy nhầm, làm lại nha:

\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)

\(\frac{x}{27}=\frac{6}{18}+\frac{2}{9}\)

\(\frac{x}{27}=\frac{3}{9}+\frac{2}{9}\)

\(\frac{x}{27}=\frac{5}{9}\)

\(\frac{x}{27}=\frac{15}{27}\)

\(x=15\)

\(\frac{15}{26}+\frac{x}{13}=\frac{46}{52}\)

\(\frac{x}{13}=\frac{46}{52}-\frac{15}{26}\)

\(\frac{x}{13}=\frac{23}{26}-\frac{15}{26}\)

\(\frac{x}{13}=\frac{8}{26}\)

\(\frac{x}{13}=\frac{4}{13}\)

\(x=4\)