10³ + 2¹⁵

= 1000 + 32768

= 33768

Mà 33768 : 33 = 1023 (dư 9)

Em xem lại đề

Giúp mik vs mọi người đâu hết rùi😄😄😄

6:

Số tiền phải trả góp là:

350000*24=8400000(đồng)

Số tiền mua chiếc TV là:

8400000:60%=14000000(đồng)

     `(x + 1)(x - 3 ) - x^2 = 2 ( x - 2 )`

`<=>x^2 - 3x + x - 3 - x^2 = 2x - 4`

`<=> x^2 - x^2 - 3x + x - 2x = - 4 + 3`

`<=> -4x = -1`

`<=> x = 1 / 4`

Vậy `S = { 1 / 4 }`

Bổ sung `b` và `c`

`b) 3 / [ x + 3 ] + x / [ x - 3 ] = 1`      `ĐK: x \ne +-3`

`<=> [ 3 ( x - 3 ) + x ( x + 3 ) ] / [ ( x -  3 ) ( x + 3 ) ] = [ ( x - 3 ) ( x + 3 ) ] / [ ( x - 3 ) ( x + 3 ) ]`

   `=> 3x - 9 + x^2 + 3x = x^2 - 9`

`<=> x^2 - x^2 + 3x + 3x = -9 + 9`

`<=> 6x = 0`

`<=> x = 0` (t/m)

Vậy `S = { 0 }`

___________________________________________

`c) | x + 7 | = 3x + 1`

`@TH1: x + 7 >= 0 <=> x >= -7`

      `=> | x + 7 | = x + 7`

 `=> x + 7 = 3x + 1`

`<=> 2x = 6`

`<=> x = 3` (t/m)

`@TH2: x + 7 < 0 <=> x < -7`

      `=> | x + 7 | = -x - 7`

  `=> - x - 7 = 3x + 1`

`<=> 4x = -8`

`<=> x = -2` (ko t/m)

Vậy `S = {3}`

a.\(\left(x+1\right)\left(x-3\right)-x^2=2\left(x-2\right)\)

\(\Leftrightarrow x^2-3x+x-3-x^2=2x-4\)

\(\Leftrightarrow-4x=-1\)

\(\Leftrightarrow x=\dfrac{1}{4}\)

b.\(\dfrac{3}{x+3}+\dfrac{x}{x-3}=1\) ;\(ĐK:x\ne\pm3\)

\(\Leftrightarrow\dfrac{3\left(x-3\right)+x\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}=\dfrac{\left(x-3\right)\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}\)

\(\Leftrightarrow3\left(x-3\right)+x\left(x+3\right)=\left(x-3\right)\left(x+3\right)\)

\(\Leftrightarrow3x-9+x^2+3x=x^2-9\)

\(\Leftrightarrow6x=0\)

\(\Leftrightarrow x=0\left(tm\right)\)

c.\(\left|x+7\right|=3x+1\)

\(\Leftrightarrow\left[{}\begin{matrix}x+7=3x+1;x\ge-7\\-x-7=3x+1;x< 7\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=3\left(tm\right)\\x=-2\left(tm\right)\end{matrix}\right.\)

4*cos(pi/6-a)*sin(pi/3-a)

=4*(cospi/6*cosa+sinpi/6*sina)*(sinpi/3*cosa-sina*cospi/3)

=4*(căn 3/2*cosa+1/2*sina)*(căn 3/2*cosa-1/2*sina)

=4*(3/4*cos^2a-1/4*sin^2a)

=3cos^2a-sin^2a

=3(1-sin^2a)-sin^2a

=3-4sin^2a

=>m=3; n=-4

m^2-n^2=-7

Ta có:

\(\dfrac{1}{cos^2x-sin^2x}+\dfrac{2tanx}{1-tan^2x}=\dfrac{1}{cos2x}+tan2x=\dfrac{1}{cos2x}+\dfrac{sin2x}{cos2x}=\dfrac{1+sin2x}{cos2x}=\dfrac{cos2x}{1-sin2x}\)

\(\Rightarrow P=a+b=2+1=3\)