16 x ( 38 - 2 ) - 38 x ( 16-1 )
Bài 1: Tính:
a) -25 . 63 - 25 . 3
Bài 2: Tìm x, biết:
c) ( x + 1 )2 = 16 d) ( -38 ) - ( x - 2 ) = -16
Bài 1
a, -25 . 63 - 25 . 3
= 25 . (-63) - 25 . 3
= 25 . [(-63) - 3]
= 25 . (-66) = -1650
Bài 2
c, (x + 1)2 = 16
=> (x + 1)2 = 42
=> x + 1 = 4
=> x = 3
d, (-38) - (x - 2) = -16
=> (x - 2) = -38 - (-16)
=> x - 2 = -38 + 16 = -22
=> x = 2 + (-22)
=> x = -20
Bài 1 Tính Bằng cách hợp lý
a, 16 x ( 38-2 ) - 38
( -41) x ( 59+2+59x41-2 )
16.(38-2)-38(16-1)
\(16\cdot\left(38-2\right)-38\cdot\left(16-1\right)\)
\(=16\cdot38-16\cdot2-38\cdot16+38\cdot1\)
\(=\left(16\cdot38-38\cdot16\right)-\left(16\cdot2\right)+38.1\)
\(=-32+38=6\)
1/2 x 1/4 + 3/4
3/4 x 5/6 x 8/15
12/19 : 17/38 x 16/9
(dấu chấm là dấu nhân nha e)
*\(\dfrac{1}{2}\). \(\dfrac{1}{4}\)+\(\dfrac{3}{4}\)
= \(\dfrac{1}{8}\)+\(\dfrac{3}{4}\)
= \(\dfrac{1}{8}\)+\(\dfrac{6}{8}\)= \(\dfrac{7}{8}\)
*\(\dfrac{3}{4}\).\(\dfrac{5}{6}\).\(\dfrac{8}{15}\)
= \(\left(\dfrac{3}{4}.\dfrac{8}{15}\right)\).\(\dfrac{5}{6}\)
= \(\dfrac{2}{5}\).\(\dfrac{5}{6}\)
= \(\dfrac{1}{3}\)
*\(\dfrac{12}{19}\): \(\dfrac{17}{38}\).\(\dfrac{16}{9}\)
= \(\dfrac{12}{19}\). \(\dfrac{38}{17}\).\(\dfrac{16}{9}\)= 2,5
1/2 x 1/4 + 3/4
3/4 x 5/6 x 8/15
12/19 : 17/38 x 16/9
1/2x1/4+3/4=7/8
3/4x5/6x8/15=1/3
12/19:17/38x16/9=128/51
1/8+3/4=7/8
5/8x8/15=1/3
24/17x16/9=128/51
giúp vs mai nộp rồi
Bài 1.
a) -x+8=-17
b) 35-x=37
c) x-45=-17
d) |x+1|=20
e) |x-3|-16=-4
Bài 2.
a) (144-97)-144
b) (-145)-(18-145)
c) (27+514)-(486-73
d) (38-29+43)-(43+38)
Bài 1:
a) −x + 8 = −17
−x = −17 − 8
−x = −25
⇒ x = 25
Vậy x = 25
b) 35 − x = 37
x = 35 − 37
x = −2
Vậy x = −2
c) x − 45 = −17
x = −17 + 45
x = 28
Vậy x = 28
d) |x + 1| = 20 (>0)
TH1: x + 1 = 20 TH2: x + 1 = −20
x = 20 − 1 x = −20 − 1
x = 19 x = −21
Vậy x∈\(\left\{-21;19\right\}\)
e) |x − 3| − 16 = −4
|x − 3| = −4 + 16
|x − 3| = 12 (>0)
TH1: x − 3 = 12 TH2: x − 3 = −12
x = 12+3 x = −12 + 3
x = 15 x = −9
Vậy x∈\(\left\{-9;15\right\}\)
b) 35 − x = 37
x = 35 − 37
x = −2
Vậy x = −2
Bài 2:
a) (144 − 97) − 144
= 144 − 97 − 144
= (144 − 144) − 97
= − 97
b) (−145) − (18 − 145)
= −145 − 18 + 145
= (−145 + 145) − 18
= −18
c) (27 + 514) − (486 − 73)
= 27 + 514 − 486 + 73
= (27 + 73) + (514 − 486)
= 100 + 28
= 128
d) (38 − 29 + 43) − (43 + 38)
= 38 − 29 + 43 − 43 − 38
= (−38 + 38) + (−43 + 43) − 29
= 0 + 0 − 29
= −29
`{(38/x + 64/y = 3),(19/x + 16/y = 1):}`
ĐKXĐ: x<>0 và y<>0
\(\left\{{}\begin{matrix}\dfrac{38}{x}+\dfrac{64}{y}=3\\\dfrac{19}{x}+\dfrac{16}{y}=1\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\dfrac{38}{x}+\dfrac{64}{y}=3\\\dfrac{38}{x}+\dfrac{32}{y}=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{32}{y}=1\\\dfrac{19}{x}+\dfrac{16}{y}=1\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=32\\\dfrac{19}{x}=1-\dfrac{16}{32}=\dfrac{1}{2}\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=32\\x=38\end{matrix}\right.\left(nhận\right)\)
Tìm x ∈ ℕ , biết:
a ) 1 2 + − 1 3 + − 2 3 ≤ x < − 3 5 + 1 6 + − 2 5 + 3 2 b ) − 3 8 + − 18 21 + − 1 7 < x ≤ − 1 6 + 8 17 + 5 − 6 + 9 17 + 1
a ) − 1 2 ≤ x < 2 3 = > x = 0. b ) − 1 < x ≤ 1 = > x ∈ {0;1}
Bài 1: Tính
d: 16.(38-2)- 38.(16-1)
\(16.\left(38-2\right)-38.\left(16-1\right)\\ =16.36-38.15\\ =576-570\\ =6\)
=16*38-16*2-38*16+38
=-16*2+38
=38-32=6