Question

`{(38/x + 64/y = 3),(19/x + 16/y = 1):}`

Answer 1

ĐKXĐ: x<>0 và y<>0

\(\left\{{}\begin{matrix}\dfrac{38}{x}+\dfrac{64}{y}=3\\\dfrac{19}{x}+\dfrac{16}{y}=1\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}\dfrac{38}{x}+\dfrac{64}{y}=3\\\dfrac{38}{x}+\dfrac{32}{y}=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{32}{y}=1\\\dfrac{19}{x}+\dfrac{16}{y}=1\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}y=32\\\dfrac{19}{x}=1-\dfrac{16}{32}=\dfrac{1}{2}\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}y=32\\x=38\end{matrix}\right.\left(nhận\right)\)