a) \(S=5+5^2+...+5^{2006}\)

\(5S=5^2+5^3+...+5^{2007}\)

\(5S-S=5^2+5^3+5^4+...+5^{2007}-5-5^2-5^3-...-5^{2006}\)

\(4S=5^{2007}-5\)

\(S=\dfrac{5^{2007}-5}{4}\)

b) \(S=5+5^2+5^3+...+5^{2006}\)

\(S=\left(5+5^4\right)+\left(5^2+5^5\right)+...+\left(5^{2003}+5^{2006}\right)\)

\(S=5\cdot\left(1+5^3\right)+5^2\cdot\left(1+5^3\right)+...+5^{2003}\cdot\left(1+5^3\right)\)

\(S=\left(1+5^3\right)\cdot\left(5+5^2+...+5^{2003}\right)\)

\(S=126\cdot\left(5+5^2+...+5^{2003}\right)\) ⋮ 126 

S=(5+52+53+54+55+56)+...+(591+592+593+594+595+596)S=(5+52+53+54+55+56)+...+(591+592+593+594+595+596)

=5(1+5+52+53+54+55)+...+591(1+52+53+54+55)=5.3906+...+591.3906=3906(5+...+596)=3.126(5+...+591)=5(1+5+52+53+54+55)+...+591(1+52+53+54+55)=5.3906+...+591.3906=3906(5+...+596)=3.126(5+...+591)

chia hết cho 126

S = 5 + 5² + 5³ + 5⁴ + ... + 5²⁰¹²

= (5 + 5² + 5³ + 5⁴) + (5⁵ + 5⁶ + 5⁷ + 5⁸) + ... + (5²⁰⁰⁹ + 5²⁰¹⁰ + 5²⁰¹¹ + 5²⁰¹²)

= 780 + 5⁴.(5 + 5² + 5³ + 5⁴) + ... + 5²⁰⁰⁸.(5 + 5² + 5³ + 5⁴)

= 780 + 5⁴.780 + ... + 5²⁰⁰⁸.780

= 65.12 + 5⁴.65.12 + ... + 5²⁰⁰⁸.65.12

= 65.12(1 + 5⁴ + ... + 5²⁰⁰⁸) ⋮ 65

Vậy S ⋮ 65

giúp minh với ạ

\(S=5\left(1+5+5^2+5^3\right)+5^5\left(1+5+5^2+5^3\right)+...+5^{2009}\left(1+5+5^2+5^3\right)\)

\(=156\left(5+5^5+...+5^{2009}\right)\)

\(=780\cdot\left(1+5^4+...+5^{2008}\right)⋮65\)

Câu hỏi của Phương Thảo Trần - Toán lớp 0 | Học trực tuyến

S =  5 + 5² + 5³ + ......... + 5²⁰⁰⁶

5S = 5² + 5³ + 5⁴ + .......... + 5²⁰⁰⁷

5S - S = ( 5² + 5³ + 5⁴ + .......... + 5²⁰⁰⁷) - (  5 + 5² + 5³ + ......... + 5²⁰⁰⁶ ) 

4S = 5²⁰⁰⁷ - 5

S = \(\frac{5^{2007}-5}{4}\)

a)\(S=5+5^2+5^3+.....+5^{2006}\Rightarrow5S=5^2+5^3+5^4+\)\(....+5^{2007}\)

\(\Rightarrow5S-S=\left(5^2+5^3+5^4+....+5^{2007}\right)-\left(5+5^2+5^3+.....+5^{2006}\right)\)

\(\Rightarrow4S=5^{2007}-5\Rightarrow S=\frac{5^{2007}-5}{4}\)

\(a.S=5+5^2+5^3+......+5^{2006}\)
\(S=\left(5+5^2+5^3+5^4+5^5+5^6\right)+.....+\left(5^{2001}+5^{2002}+.....+5^{2006}\right)\)

\(S=5.\left(1+5+5^2+5^3+5^4+5^5\right)+......+5^{2001}\left(1+5+5^2+5^3+5^4+5^5\right)\)

\(S=5.3906+........+5^{2001}.3906\)

\(S=3906\left(5+....+5^{2001}\right)\)

\(b.S=3906\left(5+....+5^{2001}\right)\)

\(S=126.3\left(5+....+5^{2001}\right)\)

\(\Rightarrow\text{S chia hết cho 126}\)

S =  5 + 5² + 5³ +....+5²⁰⁰⁶

 S= (5+5²+5³+5⁴+5⁵+5⁶) ^+.....+ ( 2²⁰⁰¹+5²⁰⁰²+5²⁰⁰³+5²⁰⁰⁴+5²⁰⁰⁵+5²⁰⁰⁶)

 S= 5 x ( 1+5+5²+5³+5⁴5⁵ ) +......+ 5²⁰⁰¹x (1+5+5 ²+5³+5⁴+5⁵)

 S= 5 x 3906+.........+ 5²⁰⁰¹ x 3906

 S = 3906x( 5+..+5²⁰⁰¹)

 S = 3906 x ( 5+...+5²⁰⁰¹)

   S = 126 x 3 x ( 5+...+5²⁰⁰¹)

=> S chia hết 126

0\(a.S=1-5+5^2-5^3+...+5^{98}-5^{99}\\ 5S=5-5^2+5^3-5^4+.....+5^{99}-5^{100}\\ 5S+S=\left(5-5^2+5^3-5^4+.....+5^{99}-5^{100}\right)+\left(1-5^{ }+5^2-5^3+.....+5^{98}-5^{99}\right)\\ 6S=1-5^{100}\\ S=\dfrac{1-5^{100}}{6}\\ \)

\(b,S6=1-5^{100}\\ 1-S6=5^{100}\) 

=> 5¹⁰⁰ chia 6 du 1

e đang cần gấp, có ai đến giúp e ko?

\(S=1-5+5^2-5^3+...+5^{98}-5^{99}\\ a,S=5^0.\left(1-5\right)+5^2.\left(1-5\right)+...+5^{98}.\left(1-5\right)=-4.\left(5^0+5^2+5^4+...+5^{98}\right)\)