\(\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}\left(\dfrac{1}{8}=0,125\right)\)

\(\dfrac{4}{7}x=1\)

->x=1:\(\dfrac{4}{7}\)

-> x= \(\dfrac{7}{4}\)

Ta có: \(\dfrac{4}{7}x=\dfrac{9}{8}-0.125\)

\(\Leftrightarrow\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}=1\)

hay \(x=\dfrac{7}{4}\)

Vậy: \(x=\dfrac{7}{4}\)

\(\dfrac{4}{7}x=1\)

=>x=\(\dfrac{7}{4}\)

4/7x=9/8-1/8

4/7x=1

⇒x=7/4

a)\(\frac{3}{4}\cdot x=1\)

   \(x=1:\frac{3}{4}=\frac{4}{3}\)

b) \(2\frac{4}{7}\cdot x=\frac{9}{8}-0,125\)

   \(\frac{18}{7}\cdot x=\frac{9}{8}-\frac{1}{8}\)

   \(\frac{18}{7}\cdot x=1\)

    \(x=1:\frac{18}{7}=\frac{7}{18}\)

Bài 1:

    \(\left(-0,125\right)\times7,9\times80\)

\(=\left(-0,9875\right)\times80\)

\(=79.\)

    \(\left(0,125\right)\times1\times0,25\times8\times\left(-4\right)\)

\(=0,125\times0,25\times8\times\left(-4\right)\)

\(=0,03125\times8\times\left(-4\right)\)

\(=0,25\times\left(-4\right)\)

\(=\left(-1\right).\)

Bài 2:

\(x+\frac{8}{3}^2=\frac{1}{9}\)

\(x+16=\frac{1}{9}\)

           \(x=\frac{1}{9}-16.MSC=9\)

           \(x=\frac{1}{9}-\frac{144}{9}\)

           \(x=\frac{-143}{9}.\)

a.\(\frac{61}{210}\)

b.\(\frac{7}{5}\)

a, \(\left(\dfrac{7}{2}-2x\right).\dfrac{10}{3}=\dfrac{22}{3}\Leftrightarrow\dfrac{7}{2}-2x=\dfrac{22}{10}=\dfrac{11}{5}\)

\(\Leftrightarrow2x=\dfrac{13}{10}\Leftrightarrow x=\dfrac{13}{20}\)

b, \(\dfrac{4x}{9}=\dfrac{9}{8}-\dfrac{125}{1000}=1\Leftrightarrow x=\dfrac{9}{4}\)

c, \(-\dfrac{x}{21}=\dfrac{60}{21}\Rightarrow x=-60\)

4/9x=9/8-0,125

4/9x=1

x=1:4/9

x=2,25

a) x=7

b)x=2/3

c)x=-13

d)x=3

e)x=-1

A)=1

a =1

a) -114.3 - 65.7 +181 

= 1

b) \(\dfrac{-7}{8}+\dfrac{3}{10}+\dfrac{4}{13}-\dfrac{1}{8}-\dfrac{-9}{13}\)

\(=\left(\dfrac{-7}{8}-\dfrac{1}{8}\right)+\left(\dfrac{4}{13}-\dfrac{-9}{13}\right)+\dfrac{3}{10}\)

\(=-1+1+\dfrac{3}{10}\)

\(=\dfrac{3}{10}\)