\(\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}\left(\dfrac{1}{8}=0,125\right)\)
\(\dfrac{4}{7}x=1\)
->x=1:\(\dfrac{4}{7}\)
-> x= \(\dfrac{7}{4}\)
Ta có: \(\dfrac{4}{7}x=\dfrac{9}{8}-0.125\)
\(\Leftrightarrow\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}=1\)
hay \(x=\dfrac{7}{4}\)
Vậy: \(x=\dfrac{7}{4}\)