a) x−(−15)=−13−(−85−13)

=> x+15=85

=>x=70

b) (−9−x)+(x−14)=17−(−8+x)

=>-9-x+x-14=17+8-x

=>-23=25-x

=>x=48

a, x=70

b,x=48

kick nha

a) x−(−15)=−13−(−85−13)

=> x+15=85

=>x=70

b) (−9−x)+(x−14)=17−(−8+x)

=>-9-x+x-14=17+8-x

=>-23=25-x

=>x=48

[ chúc bạn học tốt ]

b: \(\Leftrightarrow x-15-27-x+x-13=-1\)

\(\Leftrightarrow x-55=-1\)

hay x=54

\(a,159-\left(25-x\right)=43\)

\(\Leftrightarrow25-x=195-43\)

\(\Leftrightarrow25-x=152\)

\(\Leftrightarrow x=25-152\)

\(\Leftrightarrow x=-127\)

\(b,\left(79-x\right)-43=-\left(17-25\right)\)

\(\Leftrightarrow\left(79-x\right)-43=8\)

\(\Leftrightarrow79-x=8+43\)

\(\Leftrightarrow79-x=51\)

\(\Leftrightarrow x=79-51\Rightarrow x=28\)

\(-\left(-x+13-142\right)+18=55\)

\(\Leftrightarrow-\left(-x+13-142\right)=55-18\)

\(\Leftrightarrow-\left(-x+13-142\right)=37\)

\(\Leftrightarrow x+13-142=37\)

\(\Leftrightarrow x=37+142-13\)

\(\Leftrightarrow x=166\)

\(d,\left(102-15\right)-\left(15-x\right)=6\)

\(\Leftrightarrow87-\left(15-x\right)=6\)

\(\Leftrightarrow15-x=87-6\)

\(\Leftrightarrow15-x=81\Rightarrow x=15-81\)

\(\Leftrightarrow x=-66\)

\(e,/x+3/=10\)

\(TH1:x+3=10\)                                      \(TH2:x+3=-10\)

\(x=7\)                                                                               \(x=-13\)

Vậy x = 7 hoặc -13

a, 2.3^\(x+1\) + 38  = 2³.5²

   2.3\(^{x+1}\) + 38    = 200

   2.3\(^{x+1}\)            = 200 - 38

  2.3\(^{x+1}\)             = 162

    3\(^{x+1}\)            = 162 : 2

    3\(^{x+1}\)           = 81

    3\(^{x+1}\)           = 3⁴

     \(x+1\)        = 4

      \(x\)             = 3 

b, 2\(^{x+1}\)  + 4.2\(^x\) = 3.2⁵

   2\(^x\).(2 + 4) = 96

  2\(^x\).6         = 96

  2\(^x\)            = 96 : 6

  2\(^x\)            = 16

 2\(^x\)             = 2⁴

   \(x\)             = 4

d) (2x + 15) + 18 = 5⁵ : 5³

(2x + 15) + 18 = 5²

(2x + 15) + 18 = 25

2x + 15 = 25 - 18

2x + 15 = 7

2x = 7 - 15

2x = -8

x = -8 : 2

x = -4

\(a,\left(x-8\right)\left(x^3+8\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-8=0\\x^3+8=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x^3=-8\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x=-2\end{matrix}\right.\)

\(b,\left(4x-3\right)-\left(x+5\right)=3\left(10-x\right)\\ \Leftrightarrow4x-3-x-5=30-3x\\ \Leftrightarrow3x-8-30+3x=0\\ \Leftrightarrow6x-38=0\\ \Leftrightarrow x=\dfrac{19}{3}\)

TK

`a.(x-8)(x+8)=0`

`⇔³{x−8=0x³+8=2 `

`⇔³³{x=8x³=−2³ `

`⇔{x=8x=−2`

Vậy ` x = 8;-2`

`b. ( 4 x − 3 ) − ( x + 5 ) = 3 . ( 10 − x )`

`⇔ 4 x − 3 − x − 5 = 30 − 3 x`

`⇔ 3 x − 8 = 30 − 3 x`

`⇔ 3 x + 3 x = 30 + 8`

`⇔ 6 x = 38`

`⇔ x = 19/ 3`

Vậy ` x = 19/ 3`

\(a.\left(x-8\right)\left(x^3+8\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-8=0\\x^3+8=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=8\\\left(x+2\right)\left(x^2-2x+4\right)=0\end{matrix}\right.\)

Ta có: \(x^2-2x+4=x^2-2x+1+3=\left(x-1\right)^2+3\ge3>0\)
\(\Rightarrow x=-2\)

Vậy \(S=\left\{-2;8\right\}\)

b.\(\left(4x-3\right)-\left(x+5\right)=3\left(10-x\right)\)

\(\Leftrightarrow4x-3-x-5=30-3x\)

\(\Leftrightarrow6x=38\)

\(\Leftrightarrow x=\dfrac{19}{3}\)

Vậy \(S=\left\{\dfrac{19}{3}\right\}\)