35 : 8 = 4 ( dư 3 )

X = 8

b: Ta có: \(\dfrac{12}{5}:x+\dfrac{4}{3}=3+\dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{12}{5}:x=3-\dfrac{2}{3}=\dfrac{7}{3}\)

hay \(x=\dfrac{12}{5}:\dfrac{7}{3}=\dfrac{36}{35}\)

a. x + \(\dfrac{3}{7}\)= \(\dfrac{2}{5}:\dfrac{18}{25}=>x+\dfrac{3}{7}=\dfrac{2}{5}\)x\(\dfrac{35}{18}=>x+\dfrac{3}{7}=\dfrac{7}{9}\)

=> x = \(\dfrac{7}{9}-\dfrac{3}{7}=\dfrac{49}{63}-\dfrac{27}{63}=\dfrac{22}{63}\)

b. \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{4}{5}-\dfrac{1}{3}\)

=> \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{12}{15}-\dfrac{5}{15}=>x\) x \(\dfrac{5}{9}\)= \(\dfrac{7}{15}\)

=> x = \(\dfrac{7}{15}:\dfrac{5}{9}\)

=> x = \(\dfrac{21}{25}\)

a,x + 3/7 = 2/5 : 18/35

   x + 3/7 = 7/9

   x          = 7/9 - 3/7

   x          = 22/63

vậy x = ...

b, X x 5/9 = 4/5 - 1/3

    X x 5/9 = 7/15

            X  = 7/15 : 5/9

            X  = 21/25

vậy X = ...

\(a.x+\dfrac{3}{7}=\dfrac{2}{5}:\dfrac{18}{35}\\x+\dfrac{3}{7}=\dfrac{2}{5}\times\dfrac{35}{18} \\ x+\dfrac{3}{7}=\dfrac{7}{9}\\ x=\dfrac{7}{9}-\dfrac{3}{7}\\ x=\dfrac{22}{63}\)

\(b.x\times\dfrac{5}{9}=\dfrac{4}{5}-\dfrac{1}{3}\\x\times\dfrac{5}{9}=\dfrac{7}{15}\\ x=\dfrac{7}{15}:\dfrac{5}{9}\\ x= \dfrac{21}{25}\)

mk đã giải cho bạn rồi nhé! bạn xem lại phần thông báo ạ!

\(x:\left(-2\right)^5=\left(-2\right)^3\\ \Rightarrow x=\left(-2\right)^3.\left(-2\right)^5\\ \Rightarrow x=\left(-2\right)^8\\ \Rightarrow x=2^8\)

sorry ạ

?

mình ghi lộn

\(\Leftrightarrow x=-8\cdot32=-256\)

`a)37/9-y=6/5xx15/16`

`37/9-y=9/8`

`y=37/9-9/8`

`y=296/72-81/72=215/72`

`b)y xx3/15=4/5-2/3`

`y xx3/15=12/15-10/15`

`y xx3/15=2/15`

`y=2/15:3/15`

`y=2/15xx15/3=2/3`

a, 37/9 - Y = 6/5 x 15/16

37/9 - Y = 9/8

Y = 37/9 - 9/8

Y = 296/72 - 81/72

Y = 215/72

b, Y x 3/15 = 4/5 - 2/3

 Y x 3/15 =  2/15

Y = 2/15 : 3/15

Y = 2/15 x 15/3

Y = 2/3

1/2.x = 2/3 - (-1)/2

1/2.x = 7/6

      x = 7/6 : 1/2

      x = 7/3

vậy x=...

\(\dfrac{-1}{2}+\dfrac{1}{2}.x=\dfrac{2}{3}\)

\(\dfrac{1}{2}.x=\dfrac{2}{3}-\dfrac{-1}{2}\)

\(\dfrac{1}{2}.x=\dfrac{7}{6}\)

\(x=\dfrac{7}{6}\div\dfrac{1}{2}\)

\(x=\dfrac{7}{6}\times\dfrac{2}{1}\)

\(x=\dfrac{7}{3}\)

\(\Leftrightarrow\left(x+3\right)^2-48x^2=\left(x-3\right)^2\)

\(\Leftrightarrow48x^2=x^2+6x+9-x^2+6x-9\)

\(\Leftrightarrow48x^2-12x=0\)

=>12x(4x-1)=0

=>x=0(nhận) hoặc x=1/4(nhận)