\(16a^2b-16ab+4b=4b\left(4a^2-4a+1\right)=4b\left(2a-1\right)^2\\ 5a^3-10a=5a\left(a^2-2\right)=5a\left(a-\sqrt{2}\right)\left(a+\sqrt{2}\right)\\ 3x-3z+x^2-2xz+z^2\\ =3\left(x-z\right)+\left(x-z\right)^2=\left(x-z\right)\left(3+x-z\right)\)

\(16a^2b-16ab+4b=4b\left[\left(4a^2\right)-4a+1\right]=4b\left[\left(2a\right)^2-4a+1\right]=4b\left(2a-1\right)^2\)

\(5a^3-10a=5a\left(a^2-2\right)\)

\(3x-3z+x^2-2xz+z^2=\left(3x-3z\right)+\left(x^2-2xz+z^2\right)=3\left(x-z\right)+\left(x-z\right)^2=\left(x-z\right)\left[3+\left(x-z\right)\right]=\left(x-z\right)\left(3+x-z\right)\)

\(x^2-y^2+z^2-t^2-2xz+2yt=\)

\(=\left(x^2-2xz+z^2\right)-\left(y^2-2yt+t^2\right)=\)

\(=\left(x-z\right)^2-\left(y-t\right)^2=\)

\(=\left[\left(x-z\right)-\left(y-t\right)\right]\left[\left(x-z\right)+\left(y-t\right)\right]\)

   \(x^2-y^2+z^2-t^2-2xz+2yt\)

\(=\left(x^2-2xz+z^2\right)-\left(y^2+2yt+t^2\right)\)

\(=\left(x-z\right)^2-\left(y-t\right)^2\) 

\(=\left(x-z+y-t\right)\times\left(x-z-y+t\right)\)

\(x^2-y^2+z^2-t^2-2xz+2yt\)

\(=x^2-2xz+z^2-\left(y^2-2yt+t^2\right)\)

\(=\left(x-z\right)^2-\left(y-t\right)^2\)

\(=\left(x-z+y-t\right)\left(x-z-y+t\right)\)

\(A=\frac{x^2+y^2-z^2+2xy}{x^2-y^2+z^2+2xz}\)

       \(=\frac{\left(x^2+2xy+y^2\right)-z^2}{\left(x^2+2xz+z^2\right)-y^2}\)

         \(=\frac{\left(x+y\right)^2-z^2}{\left(x+z\right)^2-y^2}\)

           \(=\frac{\left(x+y+z\right)\left(x+y+z\right)}{\left(x+y+z\right)\left(x-y+z\right)}\)

               \(=\frac{x+y-z}{x-y+z}\)

Ta thay : \(x=0;y=2009;z=2010\) ta được :

\(A=\frac{0+2009-2010}{0-2009+2010}=-\frac{1}{1}=-1\)

Chúc bạn học tốt !!!

\(A=\frac{x^2+y^2-z^2+2xy}{x^2-y^2+z^2+2xz}=\frac{\left(x^2+2xy+y^2\right)-z^2}{\left(x^2+2xz+z^2\right)-y^2}=\frac{\left(x+y\right)^2-z^2}{\left(x+z\right)^2-y^2}\)

\(=\frac{\left(x+y+z\right)\left(x+y-z\right)}{\left(x+y+z\right)\left(x-y+z\right)}=\frac{x+y-z}{x-y+z}\)

Thay \(\hept{\begin{cases}x=0\\y=2009\\z=2010\end{cases}}\) vào biểu thức :

\(\Rightarrow A=\frac{0+2009-2010}{0-2009+2010}=-1\)

\(2^{x+1}-2^x=3^2\)

\(\Rightarrow2^x\cdot\left(2-1\right)=9\)

\(\Rightarrow2^x=9\)

\(\Rightarrow x\in\varnothing\)

\(2^{x+1}-2^x=3^2\)

=>2^x*2-2^x=9

=>2^x=9

=>\(x\in\varnothing\)

a: \(=-55x^3y^4z^5\)

Hệ số là -55

Bậc là 12

Phần biến là \(x^3;y^4;z^5\)

b: \(-6x^4y^4\cdot\dfrac{-2}{3}x^5y^3z^2=4x^9y^7z^2\)

Hệ số là 4

Bậc là 18

Phần biến là \(x^9;y^7;z^2\)