3 . |x + 4| - 2 . (x-1)= 7 - 2x
tìm x biết:
a) (x-3)2-4=0
b) x2-2x=24
c) (x+4)2-(x+1)(x-1)=16
d) (2x+1)2-4(x-1)2=9
e) (x+3)2-(x-4)(x+8)=1
f) (2x-1)2+(x+3)2-5(x+7)(x-7)=0
g) 3(x+2)2+(2x-1)2-7(x+3)(x-3)=36
- Gửi lẻ câu hỏi ra nha bạn 2 3 câu 1 lần thôi .
a) (x-3)2-4=0
⇒ (x-3)2=4
⇒ hoặc x-3=2⇒x=5
hoặc x-3=-2⇒x=1
c) (x+4)2-(x+1)(x-1)=16
⇒ x2+8x+16-x2+1=16
⇒ 8x+17=16
⇒ 8x=-1
⇒ x=-1/8
1) √(2x-1) <= 8-2x
2) √[(x+1)(4-x)] > x-2
3) √(x-2x^2+1) > 1-x
4) √(x+5) - √(x+4) > √(x+3)
5) √(5x-1) - √(x-1) > √(2x-4)
6) √(x+3) >= √(2x-8) + √(7-x)
7) √(x+2) - √(3-x) < √(5-2x)
8) √(x+1) > 3 - √(x+4)
9) √(5x-1) - √(4x-1)<= 3√x
10) { {√[2(x^2-16)]} / √(x-3) }+ √(x-3) > (7-x) / √(x-3)
Giúp mình 10 câu này với ạaa
Bạn nên viết đề bằng công thức toán và ghi đầy đủ yêu cầu đề để mọi người hiểu đề của bạn hơn nhé.
1) 2x – (3 – 5x) = 4( x +3)
2) 5(2x-3) - 4(5x-7) =19 - 2(x+11)
3) 5x - 4(6-x)(x + 3) = (4-2x)(3-2x) + 2
4) (x - 1)3 - (3x + 2)(-12) = (x2 + 1)(x - 2) - x2
5) (3x -1)2 - (x +3)(2x-1) = 7(x + 1)(x -2) -3x
mn giúp mình vs
1) 2x – (3 – 5x) = 4( x +3)
<=>2x-3+5x=4x+12
<=>2x-3+5x-4x-12=0
<=>3x-15=0
<=>x=5
2) 5(2x-3) - 4(5x-7) =19 - 2(x+11)
<=>10x-15-20x+28=19-2x-22
<=>10x-15-20x+28-19+2x+22=0
<=>-8x+16=0
<=>x=2
tham khảo
1) 2x – (3 – 5x) = 4( x +3)
<=>2x-3+5x=4x+12
<=>2x-3+5x-4x-12=0
<=>3x-15=0
<=>x=5
2) 5(2x-3) - 4(5x-7) =19 - 2(x+11)
<=>10x-15-20x+28=19-2x-22
<=>10x-15-20x+28-19+2x+22=0
<=>-8x+16=0
<=>x=2
1) (x+6)(3x-1)+x+6=0
2) (x+4)(5x+9)-x-4=0
3)(1-x)(5x+3)÷(3x-7)(x-1)
4)2x (2x-3)=(3-2x)(2-5x)
5)(2x-7)^2-6(2x-7)(x-3)=0
6)(x-2)(x+1)=x^2-4
7) x^2-5x+6=0
8)2x^3+6x^2=x^2+3x
9)(2x+5)^2=(x+2)^2
1) (x+6)(3x-1)+x+6=0
⇔(x+6)(3x-1)+(x+6)=0
⇔(x+6)(3x-1+1)=0
⇔3x(x+6)=0
2) (x+4)(5x+9)-x-4=0
⇔(x+4)(5x+9)-(x+4)=0
⇔(x+4)(5x+9-1)=0
⇔(x+4)(5x+8)=0
3)(1-x)(5x+3)÷(3x-7)(x-1)
=\(\frac{\left(1-x\right)\left(5x+3\right)}{\left(3x-7\right)\left(x-1\right)}=\frac{\left(1-x\right)\left(5x+3\right)}{\left(7-3x\right)\left(1-x\right)}=\frac{\left(5x+3\right)}{\left(7-3x\right)}\)
Bài 1: Giải các phương trình sau:
a) 2(x - 4) = x + 3.( 2x - 7) + 11
b) 7 - (x - 6) = 4(1 - 2x)
c) 11 - (x + 4) = -(2x + 4)
d) (1 - 5x)(x + 3) = (2x+3)(x-1)-7x2
e) x(x+2)-8x=(x-2)(x-4)
c)5^x+1-5^x=20 c)2^x+2^x+4=544 c)4^2x+1+4^2x=80 c)3^2x+2+3^2x+1=108 c)7^x+3-7^x+1=16464
1) \(5^{x+1}-5^x=20\Leftrightarrow5^x\left(5-1\right)=20\Leftrightarrow5^x=5\Leftrightarrow x=1\)
2) \(2^x+2^{x+4}=544\Leftrightarrow2^x\left(1+2^4\right)=544\Leftrightarrow2^x=32\Leftrightarrow x=5\)
3) \(4^{2x+1}+4^{2x}=80\Leftrightarrow4^{2x}\left(4+1\right)=80\Leftrightarrow16^x=16\Leftrightarrow x=1\)
4) \(3^{2x+2}+3^{2x+1}=108\Leftrightarrow3^{2x}\left(3^2+3\right)=108\Leftrightarrow9^x=9\Leftrightarrow x=1\)
5) \(7^{x+3}-7^{x+1}=16464\Leftrightarrow7^x\left(7^3-7\right)=16464\Leftrightarrow7^x=49\Leftrightarrow x=2\)
c:Ta có: \(5^{x+1}-5^x=20\)
\(\Leftrightarrow5^x\cdot5-5^x=20\)
\(\Leftrightarrow5^x\cdot4=20\)
\(\Leftrightarrow5^x=5\)
hay x=1
c: Ta có: \(2^x+2^{x+4}=544\)
\(\Leftrightarrow2^x+2^x\cdot16=544\)
\(\Leftrightarrow2^x\cdot17=544\)
\(\Leftrightarrow2^x=32\)
hay x=5
c: Ta có: \(4^{2x+1}+4^{2x}=80\)
\(\Leftrightarrow16^x\cdot4+16^x=80\)
\(\Leftrightarrow16^x\cdot5=80\)
\(\Leftrightarrow16^x=16\)
hay x=1
c: Ta có: \(3^{2x+2}+3^{2x+1}=108\)
\(\Leftrightarrow9^x\cdot9+9^x\cdot3=108\)
\(\Leftrightarrow9^x\cdot12=108\)
\(\Leftrightarrow9^x=9\)
hay x=1
c: Ta có: \(7^{x+3}-7^{x+1}=16464\)
\(\Leftrightarrow7^x\cdot343-7^x\cdot7=16464\)
\(\Leftrightarrow7^x\cdot336=16464\)
\(\Leftrightarrow7^x=49\)
hay x=2
1.giải phương trình :
1)1 + 2/x-1 + 1/x+3=x^2+2x-7/x^2+2x-3
2)x/x^2+5x+6=2/x^2+3x+2 (x=3)
3)1/x^2+9x+20 - 1/x^2+8x+12=x^2-2x-33/x^2+8x+15 (x=-5,7)
4)x+5/3x-6 - 1/2=2x-3/2x-4 (x=25/7)
5)x-1/x^3+1 + 2x+3/x^2-x+1=2x+4/x+1 - 2(x=0)
1/ \(1+\frac{2}{x-1}+\frac{1}{x+3}=\frac{x^2+2x-7}{x^2+2x-3}\)
ĐKXĐ: \(\hept{\begin{cases}x-1\ne0\\x+3\ne0\end{cases}}\Leftrightarrow\hept{\begin{cases}x\ne1\\x\ne-3\end{cases}}\)
<=> \(1+\frac{2\left(x+3\right)+x-1}{\left(x-1\right)\left(x+3\right)}=\frac{x^2+2x-3-5}{x^2+2x-3}\)
<=> \(1+\frac{2x+6+x-1}{x^2+2x-3}=1-\frac{5}{x^2+2x-3}\)
<=> \(\frac{3x+5}{x^2+2x-3}+\frac{5}{x^2+2x-3}=1-1\)
<=> \(\frac{3x+5}{x^2+2x-3}+\frac{5}{x^2+2x-3}=0\)
<=> \(\frac{3x+10}{x^2+2x-3}=0\)
<=> \(3x+10=0\)
<=> \(x=-\frac{10}{3}\)
(1 –x)(5x+3) = (3x -7)(x - 1)
5x - 4(6-x)(x + 3) = (4-2x)(3-2x) + 2
(3x -1)2 - (x +3)(2x-1) = 7(x + 1)(x -2) -3x
(2x - 3)(x-5) + (3-2x)(3x-4) = 0
Thực hiện phép tính:
a.(2x^2 + 2x - 4) : (x + 2)
b. ( 2x^3 - 5x^2 - x +1 ) : (2x + 1 )
c. (x^3 - 2x + 4)/(x + 2)
d. (x^3- 3x^2): (x - 3)
e. (x^4- x- 14): (x- 2)
f. (x^4- x- 14): (x- 2)
g. (17x^2- 6x^4+ 5x^3- 23x+ 7): (7- 3x^2- 2x)
giúp mik đi ạ mik đang cần gấp T-T
a: \(=\dfrac{2\left(x+2\right)\left(x-1\right)}{x+2}=2x-2\)
b: \(=\dfrac{2x^3+x^2-6x^2-3x+2x+1}{2x+1}=x^2-3x+1\)
c: \(=\dfrac{x^3+2x^2-2x^2-4x+2x+4}{x+2}=x^2-2x+2\)
d: \(=\dfrac{x^2\left(x-3\right)}{x-3}=x^2\)
`@` `\text {Ans}`
`\downarrow`
Tìm x:
a, -1/3. (15x-9)+ 2/7. (-x-34)= 1- 3/4. (-16x+4)
b, -1/3. (x-5)+ 1/2. (2x-1/3) = -4.(x+1/2) -7
c, 3.(-2x+7) -6. (1/2x) =1.(x-3)
a; - \(\dfrac{1}{3}\).(15\(x-9\)) + \(\dfrac{2}{7}\).(- \(x-34\)) = 1 - \(\dfrac{3}{4}\).(-16\(x+4\))
- 5\(x\) + 3 - \(\dfrac{2}{7}\)\(x\) - \(\dfrac{68}{7}\) = 1 + 12\(x\) - 3
12\(x\) + 5\(x\) + \(\dfrac{2}{7}x\) = 3 - \(\dfrac{68}{7}\) - 1 + 3
17\(x\) + \(\dfrac{2}{7}x\) = (3 - 1 + 3) - \(\dfrac{68}{7}\)
\(\dfrac{121}{7}\)\(x\) = 5 - \(\dfrac{68}{7}\)
\(\dfrac{121}{7}\) \(x\) = - \(\dfrac{33}{7}\)
\(x\) = - \(\dfrac{33}{7}\): \(\dfrac{121}{7}\)
\(x\) = - \(\dfrac{3}{11}\)
Vậy \(x\) = - \(\dfrac{3}{11}\)