Question

1) (x+6)(3x-1)+x+6=0

2) (x+4)(5x+9)-x-4=0

3)(1-x)(5x+3)÷(3x-7)(x-1)

4)2x (2x-3)=(3-2x)(2-5x)

5)(2x-7)^2-6(2x-7)(x-3)=0

6)(x-2)(x+1)=x^2-4

7) x^2-5x+6=0

8)2x^3+6x^2=x^2+3x

9)(2x+5)^2=(x+2)^2

Answer 1

1) (x+6)(3x-1)+x+6=0

⇔(x+6)(3x-1)+(x+6)=0

⇔(x+6)(3x-1+1)=0

⇔3x(x+6)=0

2) (x+4)(5x+9)-x-4=0

⇔(x+4)(5x+9)-(x+4)=0

⇔(x+4)(5x+9-1)=0

⇔(x+4)(5x+8)=0

3)(1-x)(5x+3)÷(3x-7)(x-1)

=\(\frac{\left(1-x\right)\left(5x+3\right)}{\left(3x-7\right)\left(x-1\right)}=\frac{\left(1-x\right)\left(5x+3\right)}{\left(7-3x\right)\left(1-x\right)}=\frac{\left(5x+3\right)}{\left(7-3x\right)}\)