374/11

tick mik nhé

=374/11 

=34

374/11 

tick nha 

C1: So sánh hai phân số \(\frac{-7}{11}\)và\(\frac{13}{-17}\)

    Đổi: \(\frac{13}{-17}\)=\(\frac{-13}{17}\)

 Ta có: BCNN (11;17) = 187

\(\Rightarrow\)\(\frac{-7}{11}\)= \(\frac{-7\times17}{11\times17}\)=\(\frac{-119}{187}\)                                              \(\Rightarrow\)\(\frac{-13}{17}\)= \(\frac{-13\times11}{17\times11}\)= \(\frac{-143}{187}\)

 Vì (-119) >(-143) nên \(\frac{-119}{187}\)>\(\frac{-143}{187}\)hay  \(\frac{-7}{11}\)>\(\frac{13}{-17}\)

 Mình chỉ giúp bạn được thế thôi, ko k cũng được, hoặc k càng tốt

1/ ( x-3) ²=16

\(\Rightarrow\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)

2/ (3x-1)³=8

\(\Rightarrow3x-1=2\\ \Rightarrow3x=3\\ \Rightarrow x=1\)

3/ (x-11)³=-27

\(\Rightarrow x-11=-3\\ \Rightarrow x=8\)

phần 4 mình ko rõ đề

4) \(x^3-3x^2+3x-1=-64\)

\(\Rightarrow x^3-3x^2+3x+63=0\\ \Rightarrow\left(x^3+3x^2\right)-\left(6x^2+18x\right)+\left(21x+63\right)=0\\ \Rightarrow x^2\left(x+3\right)+6x\left(x+3\right)+21\left(x+3\right)=0\\ \Rightarrow\left(x+3\right)\left(x^2+6x+21\right)=0\\ \Rightarrow\left[{}\begin{matrix}x+3=0\\x^2+6x+21=0\end{matrix}\right.\)

\(x+3=0\\ \Rightarrow x=-3\)

\(x^2+6x+21=0\\ \Rightarrow\left(x^2+6x+9\right)+12=0\\ \Rightarrow\left(x+3\right)^2+12=0\)

Vì \(\left(x+3\right)^2\ge0;12>0\Rightarrow\left(x+3\right)^2+12>0\Rightarrow x^2+6x+21vônghiệm\)

Vậy \(x=-3\)

a: =274+184=458

b: =29+132+868+237+163

=1000+400+29

=1429

f: =A*135*137(1001-1001)=0

e: =24*25+24*37+24*38

=24*100=2400

c: =31(98+2)=31*100=3100

A=50x11

A=550

Line 2: Who's => What's         Line 3: Mine => My   

Line 4: My => Mine                 Line 5: be => is

a, 2.x + 7 = 15

   2x         = 8

   x           = 4

b, 25 – 3.(6 – x) = 22

            3.(6-x)    = 3

               6-x      = 1

                  x      = 5

c, [(2x – 11) : 3 + 1].5 = 20

      (2x-11) : 3+1         = 4

       (2x-11):3              = 3

        2x-11                  = 1

        2x                       = 12

        x                         = 6

  e, 2 . 3x = 10 . 312 + 8 . 274

      6x      = 3120 + 2192

      6x      = 5312

        x      = 5312/6

g, x – 12 = (–8) + (–17)

    x  - 12 = -25

    x         = -13

Lần sau tách nhỏ nội dung câu hỏi ra nha em, chứ trả lời thế này biếng lắm '^^ Chị làm chỉ mang tính tham khảo kết quả thôi, còn cụ thể thì em tách từng bước một ra he :>

a, \(2\cdot x+7=15\)

\(\Leftrightarrow2\cdot x=8\)

\(\Leftrightarrow x=4\)

Vậy x = 4.

b, \(25-3\cdot\left(6-x\right)=22\)

\(\Leftrightarrow3\cdot\left(6-x\right)=3\)

\(\Leftrightarrow6-x=1\)

\(\Leftrightarrow x=5\)

Vậy x = 5.

c, \(\left[\left(2x-11\right):3+1\right]\cdot5=20\)

\(\Leftrightarrow\left(2x-11\right):3+1=4\)

\(\Leftrightarrow\left(2x-11\right):3=3\)

\(\Leftrightarrow2x-11=9\)

\(\Leftrightarrow2x=20\)

\(\Leftrightarrow x=10\)

Vậy x = 10.

d, \(\left(25-2x\right)\cdot3:5-32=42\)

\(\Leftrightarrow\)\(\frac{3\cdot\left(25-2x\right)}{5}=74\)

\(\Leftrightarrow3\cdot\left(25-2x\right)=370\)

\(\Leftrightarrow25-2x=\frac{370}{3}\)

\(\Leftrightarrow2x=-\frac{295}{3}\)

\(\Leftrightarrow x\approx49\)

Vậy \(x\approx49\) .

e, \(2\cdot3x=10\cdot312+8\cdot274\)

\(\Leftrightarrow6x=5312\)

\(\Leftrightarrow x=5312:6\approx885\)

Vậy \(x\approx885\) .

g, \(x-12=\left(-8\right)+\left(-17\right)\)

\(\Leftrightarrow x-12=-25\)

\(\Leftrightarrow x=-25+12=-13\)

Vậy x = -13.

h, \(7-2x=18-3x\)

\(\Leftrightarrow-2x+3x=18-7\)

\(\Leftrightarrow x=11\)

Vậy \(x=11\) .

i, \(3\cdot\left(x+5\right)-x-11=24\)

\(\Leftrightarrow3x+15-x-11=24\)

\(\Leftrightarrow2x=24+11-15\)

\(\Leftrightarrow2x=20\)

\(\Leftrightarrow x=10\)

Vậy \(x=10\) .

Thanks mn ^v^

    \(\left(\frac{75}{100}-\frac{60}{100}+\frac{3}{7}+\frac{3}{11}\right)+\left(\frac{275}{100}-\frac{220}{100}+\frac{11}{7}+\frac{11}{13}\right)\)\(=\frac{1311}{1540}+5\frac{331}{420}\)\(=6\frac{211}{330}\)

HỌC TỐT!!!

\(\left(\frac{75}{100}-\frac{60}{100}+\frac{3}{7}+\frac{3}{11}\right)+\left(\frac{275}{100}-\frac{220}{100}+\frac{11}{7}+\frac{11}{13}\right)\)

\(=\frac{3}{20}+\frac{3}{7}+\frac{3}{11}+\frac{11}{20}+\frac{11}{7}+\frac{11}{13}\)

\(=\frac{14}{20}+\frac{14}{7}+\frac{160}{143}=\frac{3231}{715}+\frac{14}{7}=\frac{4661}{715}\)