a)      \(x + y = 30;\dfrac{x}{2} = \dfrac{y}{3}\) áp dụng tính chất của tỉ lệ thức ra có :

\( \Rightarrow \dfrac{{x + y}}{{2 + 3}} = \dfrac{x}{2}\)

\( \Rightarrow \dfrac{{30}}{5} = \dfrac{x}{2}\)

\( \Rightarrow 30.2 = x.5\)

\(\begin{array}{l} \Rightarrow 60:5 = x\\ \Rightarrow x = 12\\ \Rightarrow 14 + y = 30\\ \Rightarrow y = 18\end{array}\)    ( thay x vừa tìm được = 12 vào x + y = 30 để tìm ra y )

Vậy x = 12 y = 18

b)      Ta có : \(\dfrac{x}{5} = \dfrac{y}{{ - 2}}\)= \(\dfrac{{x - y}}{{5 + 2}}\)( áp dụng tính chất tỉ lệ thức ) (1)

Mà theo đề bài x – y = -21

Thay -21 vào (1) ta có : \(\dfrac{{ - 21}}{7} =  - 3\) \( = \dfrac{x}{5}\)

\( \Rightarrow \)x = (-3).5

\( \Rightarrow \)x = -15

Thay x bằng -15 ta có -15 – y = -21

\( \Rightarrow \)y = -15 + 21

\( \Rightarrow \)y = 6

Vậy x = -15 và y = 6

a) 8 + 2x = 20

2x = 20 - 8

2x = 12

x = 12 : 2

x = 6

Vậy x = 6

b) 70 - 5(x - 3) = 45

5(x-3) = 70 - 45

5(x-3) = 25

x - 3 = 25 : 5

x - 3 = 5

x = 5 + 3

x = 8

Vậy x = 8

c) (3x - 2^4). 7^3 = 2. 7^4

(3x - 16) . 147 = 2 . 1029

(3x - 16) . 147 = 2058

3x - 16 = 2058 : 147

3x - 16 = 14

3x = 14 + 16

3x = 30

x = 30 : 3 

x = 10 

Vậy x = 10

a/ 8+2.x=20

    2x=20-8

    2x=12

   x=12:2=4

b/70-5.(x-3)=45

       5.(x-3)=70-45=25

          x-3=25:5=5

          x=5+3=8

c/(3.x-2⁴).7³=2.7⁴

  (3.x-2⁴).7³=4802

  3x-2⁴ =4802:7³=14

  3x=14+2⁴=30

  x=30:3=10

tk nhen

câu 1 là 6 nhé, mk nahaafm

a)=-1/35=2/70

=>x=2

vậy x= 2

b)ta chia thành 2 vế

vế 1):5/3+-14/3=-11/3=-55/15

vế 2):8/5+18/10=17/5=51/15

từ 2 vế ta có :-55/15<x<51/15

=>x\(\in\){\(\frac{-54}{15}\),.............,\(\frac{50}{15}\)}

vậy x\(\in\){\(\frac{-54}{15}\),.......,\(\frac{50}{15}\)}

      \(\frac{2}{5}+\left(\frac{-3}{7}\right)=\frac{x}{70}\)                     

=>\(\frac{-1}{35}\)                \(=\frac{x}{70}\)

=>\(\frac{-2}{70}\)                \(=\frac{x}{70}\)

VẬY x = -2

b/      \(\frac{5}{3}+\left(\frac{-14}{3}\right)< x< \frac{8}{5}+\frac{18}{10}\)

      =>                      \(-3< x< \frac{17}{5}\)

    =>                      \(-3< x< 3.4\)

    =>        \(x\left\{-2;-1;0;1;2;3\right\}\)

VẬY ............

`@` `\text {Ans}`

`\downarrow`

`a,`

`(x-1954) \times 5=50`

`x-1954 = 50 \div 5`

`x-1954 = 10`

`x=10 + 1954`

`x= 1964`

`B.`

`48 - 40 \times x=8`

`40 \times x=48-8`

`40 \times x = 40`

` x=40 \div 40`

`x=1`

`C.`

`2+70 \div x = 3`

`70 \div x = 3-2`

`70 \div x = 1`

`x=70 \div 1`

`x=70`

`D. [3 \times (x+2) \div 7]  \times  4=120`

`3 \times (x+2) \div 7 = 120 \div 4`

`3 \times (x+2) \div 7 =30`

`3 \times (x+2) = 30 \times 7`

`3 \times (x+2)=210`

`x+2=210 \div 3`

`x+2=70`

`x=70-2`

`x=68`

`E.`

`7,2 \div [ (0,6 \times x+8) \div 20 + 59] = 0,12?` Thiếu ngoặc bạn nhé._.

\(a,\left(x-1954\right)\times5=50\\ x-1954=50:5\\ x-1954=10\\ x=1954+10\\ x=1964\\b.48-40\times x=8\\40\times x=48-8\\40\times x=40\\ x=40:40\\ x=1 \\ c.2+70:X=3\\ 70:x=3-2\\ 70:x=1\\ x=70:1\\ x=70\\ d,\left[3\times\left(x+2\right):7\right]\times4=120\\ 3\times\left(x+2\right):7-120:4\\ 3\times\left(x+2\right):7=30\\ \left(x+2\right):7=30:3\\ \left(x+2\right):7=10\\ x+2=10\times7\\ x+2=70\\ x=70-2\\ x=68\)

a) \(\dfrac{x}{-6}=\dfrac{-15}{45}\)

    \(\dfrac{-x}{6}=\dfrac{-15}{45}\)

    \(\dfrac{x}{6}=\dfrac{15}{45}\)

    \(x=\dfrac{\left(15\cdot6\right)}{45}\)

    \(x=2\)

b) \(\dfrac{x}{5}=\dfrac{16}{25}\)

    \(x=\dfrac{\left(16\cdot5\right)}{25}\)

    \(x=\dfrac{80}{25}\)

   \(x=\dfrac{16}{5}\)

c) \(\dfrac{5}{x-3}=\dfrac{20}{-12}\)

  \(x-3=\dfrac{\left(5\cdot-12\right)}{20}\)

 \(x-3=-3\)

 \(x=\left(-3\right)+3\)

\(x=0\)

d) \(\dfrac{2}{5}\cdot x=\dfrac{6}{35}\)

         \(x=\dfrac{6}{35}\div\dfrac{2}{5}\)

        \(x=\dfrac{3}{7}\)

a) \(-28-7|-3x+15|=-70\)

\(\Rightarrow7|-3x+15|=42\)

\(\Rightarrow|-3x+15|=6\)

\(\Rightarrow|3\left(5-x\right)|=6\)

\(\Rightarrow|3|.|5-x|=6\)

\(\Rightarrow3|5-x|=6\)

\(\Rightarrow|5-x|=2\)

\(\Rightarrow\orbr{\begin{cases}5-x=2\\5-x=-2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=3\\x=7\end{cases}}\)

Vậy \(x\in\left\{3;7\right\}\)

b) \(|18-2|-x+5||=12\)

\(\Rightarrow\orbr{\begin{cases}18-2|-x+5|=12\\18-2|-x+5|=-12\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}2|5-x|=6\\2|5-x|=30\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}|5-x|=3\left(1\right)\\|5-x|=15\left(2\right)\end{cases}}\)

Từ \(\left(1\right):\Rightarrow\orbr{\begin{cases}5-x=3\\5-x=-3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=2\\x=8\end{cases}}\)

Từ \(\left(2\right):\Rightarrow\orbr{\begin{cases}5-x=15\\5-x=-15\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-10\\x=20\end{cases}}\)

Vậy \(x\in\left\{2;8;-10;20\right\}\)

c) \(12-2\left(-x+3\right)^2=-38\)

\(\Rightarrow2\left(3-x\right)^2=50\)

\(\Rightarrow\left(3-x\right)^2=100\)

\(\Rightarrow\orbr{\begin{cases}3-x=10\\3-x=-10\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-7\\x=13\end{cases}}\)

Vậy \(x\in\left\{-7;13\right\}\)

d) \(-20+3\left(2x+1\right)^3=-101\)

\(\Rightarrow3\left(2x+1\right)^3=-81\)

\(\Rightarrow\left(2x+1\right)^3=-27\)

\(\Rightarrow2x+1=-3\)

\(\Rightarrow2x=-4\)

\(\Rightarrow x=-2\)

Vậy \(x=-2\)

Trả lời:

a, -28 - 7| -3x + 15 | = -70

=> 7| -3x + 15 | = 42

=> | -3x + 15 | = 6

=> -3x + 15 = 6 hoặc -3x + 15 = -6

=>   -3x = -9                    -3x = -21

=>  x = 3                            x = 7

Vậy x = 3; x = 7

b, | 18 - 2 | -x + 5 || = 12

=> 18 - 2| -x + 5 | = 12 hoặc 18 -  2| -x + 5 | = -12

=> 2 | -x + 5 | = 6   hoặc    2 | -x + 5 | = 30

=> | -x + 5 | = 3    hoặc      | -x + 5 | = 15

=>  -x + 5 = 3 hoặc -x + 5 = -3 hoặc -x + 5 = 15 hoặc -x + 5 = -15

=>  x = 2                     x = 8                  x = -10               x = 20

Vậy x \(\in\){ 2; 8; -10; 20 }

c, 12 - 2.( -x + 3 )² = -38

=> 2.( -x + 3 )² = 50

=> ( -x + 3 )² = 25

=> -x + 3 = 5 hoặc -x + 3 = -5

=>   x = -2                x = 8

Vậy x = -2; x = 8

d, -20 + 3.( 2x + 1 )³ = -101

=> 3.( 2x + 1)³ = -81

=> ( 2x + 1 )³ = -27

=> 2x + 1 = -3 

=> 2x = -4

=> x = -2

Vậy x = -2

=> x = 1

a, x=-2

b, -3<x<3,4 ,vậy các giá trị nguyên của x là -2;-1;0;1;2;3

a )

     2/5 + -3/7   =   x/70

14/35 + -15/35 = x/70

-1/35                = x/70

=> x = 70x ( -1 ) / 35 = 2

Vậy x = 2

tk mk nha 

cảm ơn mọi người nhiều lắm ạ ! hihi

a) \(xy+x+y=2\)

\(xy+x+y+1=2+1\)

\(\left(xy+x\right)+\left(y+1\right)=3\)

\(x\left(y+1\right)+\left(y+1\right)=3\)

\(\left(y+1\right)\left(x+1\right)=3\)

\(\Rightarrow\left\{{}\begin{matrix}x+1\in\left\{-3;-1;1;3\right\}\\y+1\in\left\{-1;-3;3;1\right\}\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x\in\left\{-4;-2;0;2\right\}\\y\in\left\{-2;-4;2;0\right\}\end{matrix}\right.\)

Vậy ta tìm được các cặp giá trị \(\left(x;y\right)\) thỏa mãn yêu cầu:

\(\left(-4;-2\right);\left(-2;-4\right);\left(0;2\right);\left(2;0\right)\)

b) \(\left(x+1\right).y+2=-5\)

\(\left(x+1\right).y=-5-2\)

\(\left(x+1\right).y=-7\)

\(\Rightarrow\left\{{}\begin{matrix}x+1\in\left\{-7;-1;1;7\right\}\\y\in\left\{1;7;-7;-1\right\}\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x\in\left\{-8;-2;0;6\right\}\\y\in\left\{1;7;-7;-1\right\}\end{matrix}\right.\)

Mà \(x< y\)

\(\Rightarrow\left\{{}\begin{matrix}x\in\left\{-8;-2\right\}\\y\in\left\{1;7\right\}\end{matrix}\right.\)

Vậy ta tìm được các cặp giá trị \(\left(x;y\right)\) thỏa mãn yêu cầu:

\(\left(-8;1\right);\left(-2;7\right)\)

giúp mình với, mình đang vội!

a ) \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{4}{35}-\frac{\left(-11\right)}{70}\right|\)

=> \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{4}{35}+\frac{11}{70}\right|\)

=> \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{19}{70}\right|\)

=> \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\frac{19}{70}=\frac{3}{35}\)

=> \(\frac{2}{5}+x+\frac{3}{2}=\frac{3}{7}-\frac{3}{35}=\frac{12}{35}\)

=> \(\frac{2}{5}+x=\frac{12}{35}-\frac{3}{2}=-\frac{81}{70}\)

=> \(x=-\frac{81}{70}-\frac{2}{5}=-\frac{109}{70}\)

b) \(\frac{3}{4}\left(x-8\right)=\frac{5}{7}\left(4-\frac{1}{2}\right)\)

=> \(\frac{3}{4}x-6=\frac{5}{2}\)

=> \(\frac{3}{4}x=\frac{17}{2}\)

=> \(x=\frac{17}{2}:\frac{3}{4}=\frac{34}{3}\)

Câu c,d tự làm nhé

a. \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{4}{35}-\frac{-11}{70}\right|\)

\(\Rightarrow\frac{3}{7}-\left(\frac{19}{10}+x\right)=\frac{5}{14}-\left|\frac{4}{35}+\frac{11}{70}\right|\)

\(\Rightarrow\frac{3}{7}-\frac{19}{10}-x=\frac{5}{14}-\left|\frac{19}{70}\right|=\frac{5}{14}-\frac{19}{70}\)

\(\Rightarrow-\frac{103}{70}-x=\frac{3}{35}\)

\(\Rightarrow x=-\frac{103}{70}-\frac{3}{35}\)

\(\Rightarrow x=-\frac{109}{70}\)

b. \(\frac{3}{4}\left(x-8\right)=\frac{5}{7}\left(4-\frac{1}{2}\right)\)

\(\Rightarrow\frac{3}{4}\left(x-8\right)=\frac{5}{7}.\frac{7}{2}=\frac{5}{2}\)

\(\Rightarrow x-8=\frac{10}{3}\)

\(\Rightarrow x=\frac{34}{3}\)

c.  \(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)

\(\Rightarrow\frac{3}{2}-1+4x=\frac{2}{3}-7x\)

\(\Rightarrow\frac{1}{2}=\frac{2}{3}-7x-4x=\frac{2}{3}-11x\)

\(\Rightarrow11x=\frac{2}{3}-\frac{1}{2}=\frac{1}{6}\)

\(\Rightarrow x=\frac{1}{66}\)

d. \(4\left(\frac{1}{2}-x\right)-5\left(x-\frac{3}{10}\right)=\frac{7}{4}\)

\(\Rightarrow2-4x-5x+\frac{3}{2}=\frac{7}{4}\)

\(\Rightarrow2-9x=\frac{1}{4}\)

\(\Rightarrow9x=\frac{7}{4}\)

\(\Rightarrow x=\frac{7}{36}\)