(x³+x²y+xy²+y³)(x-y)

=x(x³+x²y+xy²+y³)-y(x³+x²y+xy²+y³)

=x⁴+x³y+x²y²+xy³-x³y-x²y²+xy³+y⁴

= x⁴+y⁴

đề sai bạn xem lại đề

`a)(x-1)(x^2+x+1)`

`=x^3+x^2+x-x^2-x-1`

`=x^3-1`

`b)(x^3+x^2y+xy^2+y^3)(x-y)`

`=x^4+x^3y+x^2y^2+xy^3-x^3y-x^2y^2-xy^3-y^4`

`=x^4-y^4`

a) VT`=(x-1)(x^2+x+1)`

`=x^3 +x^2 +x -x^2-x-1 `

`=x^3-1=` VP.

b) VT `=(x^3+x^2y+xy^2+y^3)(x-y)`

`=x^4+x^3y+x^2y^2+xy^3-x^3y-x^2y^2-xy^3-y^4`

`=x^4-y^4=` VP.

Ta có: \(\left(x^3-x^2y+xy^2-y^3\right)\left(x+y\right)\)

\(=\left[x^2\left(x-y\right)+y^2\left(x-y\right)\right]\left(x+y\right)\)

\(=\left(x^2-y^2\right)\left(x^2+y^2\right)\)

\(=x^4-y^4=2^4-\left(\dfrac{1}{2}\right)^4=16-\dfrac{1}{16}=\dfrac{255}{16}\)

D   =   ( x 3   +   y 3 )   –   x y ( x   +   y )     =   ( x   +   y ) ( x 2   –   x y   +   y 2 )   –   x y ( x   +   y )     =   ( x   +   y ) ( x 2   –   x y   +   y 2   –   x y )     =   ( x   +   y ) [ x ( x   –   y )   –   y ( x   –   y ) ]     =   ( x   +   y ) ( x   –   y ) 2

Vì x = y ó x – y = 0 nên D   =   ( x   +   y ) ( x   –   y ) 2   =   0

Đáp án cần chọn là: D

Ta có

B   =   x 3   +   x 2 y   –   x y 2   –   y 3     =   x 2 ( x   +   y )   –   y 2 ( x   +   y )   =   ( x 2   –   y 2 ) ( x   +   y )     =   ( x   –   y ) ( x   +   y ) ( x   +   y )   =   ( x   –   y ) ( x   +   y ) 2

Thay x = 3,25 ; y = 6,57 ta được

B   =   ( 3 , 25   –   6 , 75 ) ( 3 , 25   +   6 , 75 ) 2     =   - 3 , 5 . 10 2   =   - 350

Đáp án cần chọn là: B

a)\(\left(x-y\right)\left(x^3+x^2y+xy^2+y^3\right)=x^4+x^3y+x^2y^2+xy^3-x^3y-x^2y^2-xy^3-y^4=x^4-y^4\)

b) \(x\left(3x-18\right)-3\left(x-4\right)\left(x-2\right)+8=3x^2-18x-3x^2+18x-24+8=-16\)