(24+x)-(32-x)=16

TH1: 

24+x = 16

x= 40

TH2:

32-x = 16

x= 16

(24+x)-(32-x)=16

24+x-32+x=16

2x-8=16

2x=24

x=12

1) 2016 +x = 169x

<=> 2016 = 168x

<=> x=12

2) (26 - 3x) : 5= 4

<=> 26 - 3x = 20

<=> 3x =6

<=> x=2

3) x + 32 - 17 = 21

<=> x + 15 = 21

<=> x= 6

hơi lạ

Thay x = -1 vào biểu thức đã cho ta được:

(-1) + ( -1)3 + (-1)5 + (-1)7 +...+ (-1)101

= (-1) + (-1) + (-1) + (-1) +(- 1)+ ... + (-1) (51 số -1)

= -51.

Chọn đáp án C

1. \(x-8+32=68\)

\(x-8=68-32\)

\(x-8=36\)

\(x=36+8\)

\(x=44\)

_____

2. \(x+8+32=68\)

\(x+8=68-32\)

\(x+8=36\)

\(x=36-8\)

\(x=28\)

_____

3. \(98-x+34=43\)

\(98-x=43-34\)

\(98-x=9\)

\(x=98-9\)

\(x=89\)

_____

4. \(98+x-34=43\)

\(98+x=43+34\)

\(98+x=77\)

\(x=77-98\)

\(x=-21\)

_____

5. \(x:5:4=800\)

\(x:5=800.4\)

\(x:5=3200\)

\(x=3200.5\)

\(x=16000\)

_____

6. \(18+x=384:8\)

\(18+x=48\)

\(x=48-18\)

\(x=30\)

_____

7. \(\left(84,6-2\times x\right):3,02=5,1\)

\(84,6-2.x=5,1.3,02\)

\(84,6-2.x=15,402\)

\(2.x=84,6-15,402\)

\(2.x=69,198\)

\(x=69,198:2\)

\(x=34,599\)

_____

8. \(x\times5=120:6\)

\(x.5=20\)

\(x=20:5\)

\(x=4\)

_____

9. \(\left(15\times24-x\right):0,25=100:0,25\)

\(\left(15.24-x\right):0,25=400\)

\(15.24-x=400.0,25\)

\(15.24-x=100\)

\(360-x=100\)

\(x=360-100\)

\(x=260\)

1,x-8+32=68

=>x-8=68-32=36

=>x=36+8=42

2,x+8+32=68

=>x+8=68-32=36

=>x=36-8=28

3,98-x+34=43

=>98-x=43-34=9

=>x=98-9=89

4,98+x-34=43

=>98+x=43+34=77

=>x=77-98=-21

5,x:5:4=800

=>x:20=800

=>x=800x20=16000

6,18+x=384:8=48

=>x=48-18=30

7,(84,6-2x):3,02=5,1

=>84,6-2x=5,1x3,02=15,402

=>2x=84,6-15,402=69,198

=>x=69,198:2=34,599

8,5x=120:6=20

=>x=20:5=4

9,(15x24-x):0,25=100:0,25=400

=>360-x=400x0,25=100

=>x=360-100=260.

1. \(...\Rightarrow x+24=68\Rightarrow x=68-24=44\)

2. \(...\Rightarrow x+40=68\Rightarrow x=68-40=28\)

3. \(...\Rightarrow3^{2\left(8+x\right)}=9=3^2\Rightarrow2\left(8+x\right)=2\Rightarrow8+x=1\Rightarrow x=-7\)

4. \(...\Rightarrow3^{2\left(8+x\right)}=77\) (bạn xem lại đề)

5. \(...\Rightarrow x:5=800.4\Rightarrow x:5=3200\Rightarrow x=3200.5=16000\)

6. \(...\Rightarrow18+x=48\Rightarrow x=48-18=30\)

7. \(...\Rightarrow84,6-2x=5,1.3,02=15,402\Rightarrow2x=84,6-15,402\Rightarrow2x=69,198\Rightarrow x=34,599\)

8. \(...\Rightarrow5.x=20\Rightarrow x=20:5=4\)

9. \(\left(360-x\right):0,25=400\Rightarrow360-x=400.0,25=100\Rightarrow x=400-100=300\)

\(A\left(x\right)=x^5+3x^3-x^5+x-1=3x^3+x-1\)

Bậc : 4

\(B\left(x\right)=3x^3-2x^2-1\)

Bậc : 5

\(A\left(x\right)+B\left(x\right)=3x^3+x-1+3x^3-2x^2-1\)

\(=6x^3-2x^2+x-2\)

\(\left(x+32\right):12=51\)

\(=>x+32=612\)

\(=>x=580\)

Mik nhanh nhât nha

(x+32):12=51

x+32 = 51.12

x+32 = 612

x = 612 - 32

x = 580

(x+32):12 =51

x+32 = .51.12=612

x = 612-32=580

O_O ... Sửa lại đề -.- : \(\frac{x}{7}=\frac{y}{5}\)và \(x+2y=51\)

ADTC dãy tỉ số bằng nhau ta có 

\(\frac{x}{7}=\frac{y}{5}=\frac{x+2y}{7+2.5}=\frac{51}{17}=3\)

\(\Rightarrow\hept{\begin{cases}\frac{x}{7}=3\\\frac{y}{5}=3\end{cases}\Rightarrow\hept{\begin{cases}x=3.7=21\\y=3.5=15\end{cases}}}\)

Sửa đề \(\frac{x}{7}=y5\)và \(x+2y=51\)

Theo bài ra ta có 

\(\frac{x}{7}=y5\Rightarrow\frac{x}{7}=\frac{y}{5}\)

ADTC dãy tỉ số bằng nhau ta có 

\(\frac{x}{7}=\frac{y}{5}=\frac{x+2y}{7+2.5}=\frac{51}{17}=3\)

\(\Rightarrow\hept{\begin{cases}\frac{x}{7}=3\\\frac{y}{5}=3\end{cases}\Rightarrow\hept{\begin{cases}x=3.7=21\\y=3.5=15\end{cases}}}\)

hình như ... 

Tú ơi! Sao \(\frac{x}{7}=y5\Rightarrow\frac{x}{7}=\frac{y}{5}\)

Bài 1:

a) \(2\cdot3\cdot2\cdot3\cdot2\cdot3=2^3\cdot3^3=6^3\)

b) \(100\cdot100\cdot100=100^3=\left(10^2\right)^3=10^6\)

c) \(2x\cdot2x\cdot2x=\left(2x\right)^3=8x^3\)

d) \(2\cdot2^3\cdot2^5=2^{1+3+5}=2^9\)

e) \(3^{10}\cdot3^5\cdot3^4=3^{10+5+4}=3^{19}\)

Bài 2:

\(40-x=2^6\cdot2^2\)

\(\Rightarrow40-x=2^8\)

\(\Rightarrow40-x=256\)

\(\Rightarrow x=40-256\)

\(\Rightarrow x=-216\)

b) \(3^2\cdot3^x=81\)

\(\Rightarrow3^{2+x}=3^4\)

\(\Rightarrow2+x=4\)

\(\Rightarrow x=4-2=2\)

c) \(2^x=512\)

\(\Rightarrow2^x=2^9\)

\(\Rightarrow x=9\)

d) \(x^5=243\)

\(\Rightarrow x^5=3^5\)

\(\Rightarrow x=3\)

Bài 3:

a) \(3^6=3\cdot3\cdot3\cdot3\cdot3\cdot3=729\)

b) \(8^3=\left(2^3\right)^3=2^9=512\)

c) \(3^3\cdot75+3^3\cdot25=3^3\cdot\left(75+25\right)=3^3\cdot100=27\cdot100=2700\)

d) \(2^3\cdot3-\left(1^{10}+8\right):3=2^3\cdot3-9:3=2^3\cdot3-3\cdot3:3=3\cdot\left(2^3-3:3\right)=3\cdot\left(8-1\right)=21\)

e) \(32-\left[4+\left(5\cdot3^2-42\right)\right]-14=18-\left[4+\left(45-42\right)\right]\)

\(=18-\left(4+3\right)\)

\(=18-7=11\)

2:

a: =>40-x=256

=>x=40-256=-216

b: =>x+2=4

=>x=2

c: =>2^x=2^9

=>x=9

d; =>x^5=3^5

=>x=3