Ta có: \(2011+5\left[300-\left(17-7\right)^2\right]\)

\(=2011+5\left[300-10^2\right]\)

\(=2011+1000=3011\)

\(2011+5.\left[300-\left(17-7\right)^2\right]\) 

\(=2011+5.\left[300-\left(10\right)^2\right]\) 

\(=2011+5.\left[300-100\right]\) 

\(=2011+5.200\) 

\(=2011+1000\) 

\(=3011\)

a=897

b=8668

c=7

d=3671

a,=29.(69+31)-2300

=29.100-2300

=2900-2300

=600

MK NÓI THẬT MẤY BÀI NÀY DỄ ỢT

a) 29 x( 69+31) -2300

=29X 100 -2300

=2900-2300

=600

c) 3^11:3^9 - 98: 7^2

=3^(11-9) - 98:49

=3^2-2

=9-2=7

d) 2011+5( 300-(17-7^2))

=2016 (300-(17-49)

=2016 (300-(-32)

= 2016 332

=134531712

2011 + 5 . 283² = 2011 + 5 . 80089

                        = 2011 + 400445  

                        = 402456

a) Ta có:

\(2^{300}=2^{3\cdot100}=\left(2^3\right)^{100}=8^{100}\)

\(3^{200}=3^{2\cdot100}=\left(3^2\right)^{100}=9^{100}\)

Mà: \(8< 9\)

\(\Rightarrow8^{100}< 9^{100}\)

\(\Rightarrow2^{300}< 3^{200}\)

b) Ta có:

\(3^{500}=3^{5\cdot100}=\left(3^5\right)^{100}=243^{100}\)

\(7^{300}=7^{3\cdot100}=\left(7^3\right)^{100}=343^{100}\)

Mà: \(243< 343\)

\(\Rightarrow243^{100}< 343^{100}\)

\(\Rightarrow3^{500}< 7^{300}\)

c) Ta có: 

\(8^5=\left(2^3\right)^5=2^{3\cdot5}=2^{15}=2\cdot2^{15}\)

\(3\cdot4^7=3\cdot\left(2^2\right)^7=3\cdot2^{2\cdot7}=3\cdot2^{14}\)

Mà: \(2< 3\)

\(\Rightarrow2\cdot2^{14}< 3\cdot2^{14}\)

\(\Rightarrow8^5< 3\cdot4^7\)

d) Ta có:

\(202^{303}=202^{3\cdot101}=\left(202^3\right)^{101}=8242408^{101}\)

\(303^{202}=303^{2\cdot101}=\left(303^2\right)^{101}=91809^{101}\)

Mà: \(8242408>91809\)

\(\Rightarrow8242408^{101}>91809^{101}\)

\(\Rightarrow202^{303}>303^{202}\)

1. 5³ = 5.5.5 = 125

2. 2⁷ = 2.2.2.2.2.2.2 = 128

3. 4⁴ = 4.4.4.4 = 256

4. 7³ = 7.7.7 = 343

6. 3⁵ = 243

7. 2⁶ =  64

8. 3⁴ =  81

9. 8³ =  512

11. 13² = 169

12. 11² = 121

13. 14² = 196

14. 15² = 225

16. 17² = 289

17. 18² = 324

18. 19² = 361

19. 20² = 400

21. 10⁴ = 10000

22. 10⁵ = 100000

23. 10⁶ = 1000000

24. 10⁷ = 10000000

bạn làm như bạn gia hân là đúng nhé

giải giúp mình bài 2 trên với ạ

a ) 2²⁰⁰<8³⁰⁰

b ) 25²⁰⁰>5³⁰⁰

c ) 4²¹<64⁷

a)\(8^{300}=\left(2^3\right)^{300}=2^{900}\)

Vì \(200< 900\Rightarrow2^{200}< 8^{300}\)

b)\(25^{200}=\left(5^2\right)^{200}=5^{400}\)

Vì \(400>300\Rightarrow25^{200}>5^{300}\)

c)\(64^7=\left(4^3\right)^7=4^{21}\)

Vì \(4^{21}=4^{21}\Rightarrow4^{21}=64^7\)

a) \(2^{200}=2^{200}\)

\(8^{300}=\left(2^3\right)^{300}=2^{900}\)

vi \(2^{200}< 2^{900}\)nen \(2^{200}< 8^{300}\)

b) \(25^{200}=\left(5^2\right)^{200}=5^{400}\)

\(5^{300}=5^{300}\)

vi \(5^{400}>5^{300}\)nen \(25^{200}>5^{300}\)

c) \(4^{21}=\left(2^2\right)^{21}=2^{42}\)

\(64^7=\left(2^6\right)^7=2^{42}\)

vi \(2^{42}=2^{42}\)nen \(4^{21}=64^7\)

a.117 - 35 + (-17) = 117 - 52 = 65

b. (-4) . 17 . (-25) = 1700

c. 47. 129 - 47. 29 +300

= 47.(129-29)+300

=47.100+300

=4700+300 = 5000

d. 25 - 5 . [ 49 - (6-3)² . 5 ] + 1²⁰²¹

= 25 - 5 . ( 49 - (2)² .5 ) + 1 

= 25-5 . ( 49 - 20 ) + 1

= 25-5 .29 + 1 

= 25 - 145 + 1

=-119