Question

2011+5[300-(17-7)mũ 2]

Answer 1

Ta có: \(2011+5\left[300-\left(17-7\right)^2\right]\)

\(=2011+5\left[300-10^2\right]\)

\(=2011+1000=3011\)

Answer 2

\(2011+5.\left[300-\left(17-7\right)^2\right]\) 

\(=2011+5.\left[300-\left(10\right)^2\right]\) 

\(=2011+5.\left[300-100\right]\) 

\(=2011+5.200\) 

\(=2011+1000\) 

\(=3011\)