a) x - 7 = 5. 0 => x - 7 = 0 =>x = 7.

b) x: 3 = 47 +13 => x: 3 = 60 => x = 60.3 => x = 180.

c) x :  7 - 7 = 0 hoặc x : 12 - 12 = 0. Do đó x = 49 hoặc x = 144.

d) x : 2 = 150 - 135 => x: 2 = 15 => x = 15.2 => x = 30.

e) 100: x = 140 -120 => 100: x = 20 => x = 100:20 => x = 5.

g) x : 5 = 300 - 273 => x : 5 = 27 =>x = 27.5 => x = 135

a) x - 7 = 5. 0 => x - 7 = 0 =>x = 7.

b) x: 3 = 47 +13 => x: 3 = 60 => x = 60.3 => x = 180.

c) x :  7 - 7 = 0 hoặc x : 12 - 12 = 0. Do đó x = 49 hoặc x = 144.

d) x : 2 = 150 - 135 => x: 2 = 15 => x = 15.2 => x = 30.

e) 100: x = 140 -120 => 100: x = 20 => x = 100:20 => x = 5.

g) x : 5 = 300 - 273 => x : 5 = 27 =>x = 27.5 => x = 135

\(a,\left(x-7\right):5=0\)

\(\Rightarrow x-7=0\)

\(\Rightarrow x=7\)

\(b,\left(x:7-7\right)\left(x:12-12\right)=0\)

\(\Rightarrow\hept{\begin{cases}x:7=7\\x:12=12\end{cases}}\)

\(\Rightarrow x=1\)

\(c,300-x:5=273\)

\(\Rightarrow x:5=27\)

\(\Rightarrow x=27.5=135\)

\(d,135+x:2=150\)

\(\Rightarrow x:2=15\)

\(\Rightarrow x=30\)

a) \(\left(x-7\right):5=0\)

\(\Rightarrow x-7=0\times5\)

\(\Rightarrow x-7=0\)

\(\Rightarrow x=0+7\)

\(\Rightarrow x=7\)

Vậy x = 7

b) \(\left(x:7-7\right)\left(x:12-12\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x:7-7=0\\x:12-12=0\end{cases}}\Rightarrow\orbr{\begin{cases}x:7=7\\x:12=12\end{cases}}\Rightarrow\orbr{\begin{cases}x=49\\x=144\end{cases}}\)

Vậy x = 49 hoặc x = 144

c) \(300-x:5=273\)

\(\Rightarrow x:5=300-273\)

\(\Rightarrow x:5=27\)

\(\Rightarrow x=27\times5\)

\(\Rightarrow x=135\)

Vậy x = 135

d) \(135+x:2=150\)

\(\Rightarrow x:2=150-135\)

\(\Rightarrow x:2=15\)

\(\Rightarrow x=15\times2\)

\(\Rightarrow x=30\)

Vậy x = 30

_Chúc bạn học tốt_

a, x=5

b,x=20

c,x=1 hoặc x=-2

d, ko hiểu đề bài

e,x=2

f,x=80

\(a)\left(x-5\right).2=0\)

\(\Rightarrow x-5=0\)

\(\Rightarrow x=5\)

Vậy \(x=5\)

\(b)x.3-13=47\)

\(\Rightarrow x.3=47+13\)

\(\Rightarrow x.3=60\)

\(\Rightarrow x=60:3\)

\(\Rightarrow x=20\)

Vậy \(x=20\)

\(c)\left(x.7-7\right)\left(x.12+24\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x.7-7=0\Rightarrow x.7=7\Rightarrow x=1\\x.12+24=0\Rightarrow x.12=-24\Rightarrow x=-2\end{cases}}\)

Vậy\(x\in\left\{1;-2\right\}\)

\(e)140-10.x=120\)

\(\Rightarrow10.x=140-120\)

\(\Rightarrow10.x=20\)

\(\Rightarrow x=2\)

Vậy \(x=2\)

\(g)x.5-127=273\)

\(\Rightarrow x.5=273+127\)
\(\Rightarrow x.5=400\)

\(\Rightarrow x=400:5\)

\(\Rightarrow x=80\)

Vậy \(x=80\)

GHI RÕ CÁCH GIẢI CHO TỚ NHÉ

1) tính nhanh

Ta thấy các số cách nhau 2 đơn vị lên

Số số hạng là \(\left(51-3\right)\div2+1=25\) ( số hạng )

Tổng dãy số trên là \(\left(51+3\right)\times25\div2=675\) 

2) Tìm x

a) \(135+x\times2=151\) 

              \(x\times2=151-135=16\) 

                      \(x=16\div8\) 

b) \(x\times5-227=273\) 

             \(x\times5=273+227=500\) 

                    \(x=500\div5\) 

                    \(x=100\) 

c) \(\left(x-4\right)\times3+2=101\) 

           \(\left(x-4\right)\times3=101-2=99\) 

                    \(x-4=99\div3=33\) 

                           \(x=33+4\) 

                           \(x=37\) 

d) \(170-\left(4+5\times x\right)=101\) 

                 \(4+5\times x=170-101=69\) 

                         \(5\times x=69-4\) 

                         \(5\times x=65\) 

                               \(x=65\div5\) 

                               \(x=13\)

c ơn cou nha

a: \(\left(\dfrac{1}{4}-x\right)\left(x+\dfrac{2}{5}\right)=0\)

=>\(\left[{}\begin{matrix}\dfrac{1}{4}-x=0\\x+\dfrac{2}{5}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=-\dfrac{2}{5}\end{matrix}\right.\)

b: \(\left|2x+1\right|+\dfrac{3}{2}=2\)

=>\(\left|2x+1\right|=\dfrac{1}{2}\)

=>\(\left[{}\begin{matrix}2x+1=\dfrac{1}{2}\\2x+1=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=-\dfrac{1}{2}\\2x=-\dfrac{3}{2}\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=-\dfrac{1}{4}\\x=-\dfrac{3}{4}\end{matrix}\right.\)

c: (2x-3)²=36

=>\(\left[{}\begin{matrix}2x-3=6\\2x-3=-6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=9\\2x=-3\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=\dfrac{9}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)

d: \(7^{x+2}+2\cdot7^x=357\)

=>\(7^x\cdot49+7^x\cdot2=357\)

=>\(7^x=7\)

=>x=1

a) \(\left(\dfrac{1}{4}-x\right)\left(x+\dfrac{2}{5}\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}\dfrac{1}{4}-x=0\\x+\dfrac{2}{5}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=-\dfrac{2}{5}\end{matrix}\right.\)

\(---\)

b) \(\left|2x+1\right| +\dfrac{2}{3}=2\)

\( \Rightarrow\left|2x+1\right|=2-\dfrac{2}{3}\)

\(\Rightarrow\left|2x+1\right|=\dfrac{4}{3}\)

\(\Rightarrow\left[{}\begin{matrix}2x+1=\dfrac{4}{3}\\2x+1=-\dfrac{4}{3}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=\dfrac{1}{3}\\2x=-\dfrac{7}{3}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{6}\\x=-\dfrac{7}{6}\end{matrix}\right.\)

\(---\)

c) \(\left(2x-3\right)^2=36\)

\(\Rightarrow\left(2x-3\right)^2=\left(\pm6\right)^2\)

\(\Rightarrow\left[{}\begin{matrix}2x-3=6\\2x-3=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=9\\2x=-3\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{9}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)

\(---\)

d) \(7^{x+2}+2\cdot7^x=357\)

\(\Rightarrow7^x\cdot7^2+2\cdot7^x=357\)

\(\Rightarrow7^x\cdot\left(7^2+2\right)=357\)

\(\Rightarrow7^x\cdot\left(49+2\right)=357\)

\(\Rightarrow7^x\cdot51=357\)

\(\Rightarrow7^x=357:51\)

\(\Rightarrow7^x=7\)

\(\Rightarrow x=1\)

a) Ta có: \(x^2-x-12=0\)

\(\Leftrightarrow\left(x-4\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-3\end{matrix}\right.\)

b) Ta có: \(x^2+3x-18=0\)

\(\Leftrightarrow\left(x+6\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-6\\x=3\end{matrix}\right.\)

a) 135 - 35 : 5 = 100 : 5 = 20 

b) 246 + 54 x 2 = 246 + 108 = 354

c) 135 - 35 : 5 = 135 - 7= 128 

d) 246 + 54 x 2 = 300 x 2= 600

a) (x + 3)^2 - 4x - 12 = 0

<=> (x + 3)^2 - 4(x + 3) = 0

<=> (x + 3)(x - 1) = 0

<=> x = -3 hoặc x = 1

b) x(x + 5)(x- 5) - (x - 3)(x^2 + 3x + 9) = 7

<=> x^3 - 25x - x^3 + 27 = 7

<=> -25x + 27 = 7

<=> x = 4/5

a/ \(\left(x+3\right)^2-4x-12=0\)

\(\left(x+3\right)^2-4\left(x+3\right)=0\)

\(\left(x+3\right)\left(x+3-4\right)=0\)

\(\left[{}\begin{matrix}x+3=0\Rightarrow x=-3\\x+3-4=0\Rightarrow x=1\end{matrix}\right.\)

---

b/ \(x\left(x+5\right)\left(x-5\right)-\left(x-3\right)\left(x^2+3x+9\right)=7\)

\(x\left(x^2-25\right)-\left(x^3-27\right)=7\)

\(x^3-25x-x^3+27=7\)

\(-25x=-20\)

\(x=\dfrac{20}{25}=\dfrac{4}{5}\)

a, <=>x² +6x+9-4x-12=0

<=> x² +2x -3=0

<=> x² +3x -x-3=0

<=> x.(x+3) - (x+3) =0

<=> (x-1)(x+3)=0

<=> x=1 hoặc x=-3

b, <=> x(x² -25) - (x-3)(x+3)² -7=0 

<=> x³ -25x + (9-x²) (x+3) -7=0

<=> x³ -25x+ 9x+27-x³ -3x² -7=0

<=> -3x² -16x +20=0

<=>(3x-10)(x-2) =0 (đoạn này tự phân tích nha ^ ^)

<=> x= 10/3 hoặc x=2

Chúc bạn học tốt nha!