thế mà cũng hỏi

`@` `\text {Ans}`

`\downarrow`

\(7\cdot35\cdot7\cdot25\)

`=`\(7^2\cdot7\cdot5\cdot5^2\)

`=`\(7^3\cdot5^3=\left(7\cdot5\right)^3=35^3\)

a) \(15^8\cdot2^4\)

\(=\left(15^2\right)^4\cdot2^4\)

\(=225^4\cdot2^4\)

\(=\left(225\cdot2\right)^4\)

\(=450^4\)

b) \(27^5:32^3\)

\(=\left(3^3\right)^5:\left(2^5\right)^3\)

\(=3^{15}:2^{15}\)

\(=\left(\dfrac{3}{2}\right)^{15}\)

Ta có:

12 . 12 . 12 . 2. 6 = 12 . 12 . 12 . 12 = 12⁴

25 . 5 . 4 . 2 . 10 =  25 . 4 . 2 . 10 . 5 = 100 . 100 = 100²

2. 10 . 10 . 3 . 5. 10 = 10 . 10 . 10 . 2 . 5 . 3 = 10 . 10 . 10 . 10 . 3 = 10⁴ . 3 

a,12.12.2.12.6=12.12.12.(2.6)=12.12.12.12=12⁴

b,25.5.4.2.10=(25.4)(5.2.10)=100.100=100²

c,2.10.10.3.5.10=10.10.10.2.5.3=10.10.10.10.3=10⁴.3

a, 2.2.4.4 =  2 . 2 . 2 2 . 2 2 = 2 1 + 1 + 2 + 2 =  2 6

b, 10.1000.100000 =  10 . 10 3 . 10 5 =  10 1 + 3 + 5 = 10 9

c,  4 5 . 2 7 =  2 2 . 2 7 = 2 2 . 5 . 2 7 = 2 10 . 2 7 = 2 10 + 7 = 2 7

d,  3 3 . 18 - 3 3 . 15 =  3 3 ( 18 - 15 ) = 3 3 . 3 = 3 3 + 1 = 3 4

e,  6 3 . 36 =  6 3 . 6 2 = 6 3 + 2 = 6 5

f,  49 3 . 7 4 =  7 2 3 . 7 4 = 7 2 . 3 . 7 4 = 7 6 . 7 4 =  7 6 + 4 = 7 10

g,  a 9 . a 7 = a 9 + 7 = a 16

h,  a . b 6 . b 6 =  a 6 . b 6 . b 6 = a 6 . b 6 . b 6 = a 6 . b 6 + 6 = a 6 . b 12

\(\begin{array}{l}a){15^8}{.2^4} = {15^{2.4}}{.2^4} = {({15^2})^4}{.2^4}\\ = {225^4}{.2^4} = {(225.2)^4} = {450^4}\\b){27^5}:{32^3} = {({3^3})^5}:{({2^5})^3}\\ = {3^{3.5}}:{2^{5.3}} = {3^{15}}:{2^{15}} = {\left( {\frac{3}{2}} \right)^{15}}\end{array}\)

a) \(15^8\cdot2^4=3^8\cdot5^8\cdot2^4=9^4\cdot25^4\cdot2^4=\left(9\cdot25\cdot2\right)^4=450^4\) 

b) \(27^5:32^3=\left(3^3\right)^5:\left(2^5\right)^3=3^{15}:2^{15}=\left(\dfrac{3}{2}\right)^{15}\)

b: \(3^4\cdot3^5:\dfrac{1}{27}==3^9\cdot3^3=3^{12}\)