Tìm x biết
1,5x - 2 1/3x = 1,5 - 2/3
tìm x
x + 3^2 = 7 - x
[3x +1,5] :3 1/5= 5/8
2 /x-1/ -7 = -3
\(x+3^2=7-x\)
\(x+x=7-9\)
\(2x=-2\)
\(x=-1\)
\(2\left|x-1\right|-7=-3\)
\(2\left|x-1\right|=4\)
\(\left|x-1\right|=2\)
\(\orbr{\begin{cases}x-1=2\\x-1=-2\end{cases}}\)
\(\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)
1) x + 3^2 = 7 - x
<=> x + 9 = 7 + (-x)
<=> x + 9 = -x + 7
<=> x + 9 + x = 7
<=> 2x + 9 = 7
<=> 2x = 7 - 9
<=> 2x = -2
<=> x = (-2) : 2
<=> x = -1
3) 2|x - 1| - 7 = -3
<=> 2|x - 1| = -3 + 7
<=> 2|x - 1| = 4
<=> |x - 1| = 4 : 2
<=> |x - 1| = 2
<=> x - 1 = -+2
<=> x - 1 = 2 hoặc x - 1 = -2
x = 1 + 2 x = -2 + 1
x = 3 x = -1
=> x = 3 hoặc x = -1
Bài 9: Tìm x, biết:
a)|-2x+1,5|=1/4
b)3/2-|1 1/4+3x|=1/4
c)|4x-1| - |3x-1/2|=0
d)|x-1|-2x=1/2
Giúp mình với mình đang cần gấp
\(|-2x+1,5|=\dfrac{1}{4}\Rightarrow-2x+1,5=\pm\dfrac{1}{4}\)
\(-2x+1,5=\dfrac{1}{4}\Rightarrow-2x=1,5-0,25\Rightarrow-2x=1,25\Rightarrow x=1,25:\left(-2\right)\Rightarrow x=...\)
\(-2x+1,5=-\dfrac{1}{4}\Rightarrow-2x=-0,25-1,5\Rightarrow-2x=1,75\Rightarrow x=1,75:\left(-2\right)\Rightarrow x=...\)
\(\dfrac{3}{2}-|1.\dfrac{1}{4}+3x|=\dfrac{1}{4}\Rightarrow|1.\dfrac{1}{4}+3x|=\dfrac{3}{2}-\dfrac{1}{4}\Rightarrow|1.\dfrac{1}{4}+3x|=\dfrac{5}{4}\)
\(\Rightarrow1.\dfrac{1}{4}+3x=\pm\dfrac{5}{4}\)
\(1.\dfrac{1}{4}+3x=\dfrac{5}{4}\Rightarrow\dfrac{1}{4}+3x=\dfrac{5}{4}\Rightarrow3x=\dfrac{5}{4}-\dfrac{1}{4}\Rightarrow3x=1\Rightarrow x=3\)
\(1.\dfrac{1}{4}+3x=-\dfrac{5}{4}\Rightarrow\dfrac{1}{4}+3x=-\dfrac{5}{4}\Rightarrow3x=-\dfrac{5}{4}-\dfrac{1}{4}\Rightarrow3x=-\dfrac{3}{2}x=...\)
a: ta có: \(\left|-2x+\dfrac{3}{2}\right|=\dfrac{1}{4}\)
\(\Leftrightarrow\left[{}\begin{matrix}-2x+\dfrac{3}{2}=\dfrac{1}{4}\\-2x+\dfrac{3}{2}=-\dfrac{1}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-2x=-\dfrac{5}{4}\\-2x=-\dfrac{7}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{8}\\x=\dfrac{7}{8}\end{matrix}\right.\)
b: Ta có: \(\dfrac{3}{2}-\left|\dfrac{5}{4}+3x\right|=\dfrac{1}{4}\)
\(\Leftrightarrow\left|3x+\dfrac{5}{4}\right|=\dfrac{5}{4}\)
\(\Leftrightarrow\left[{}\begin{matrix}3x+\dfrac{5}{4}=\dfrac{5}{4}\\3x+\dfrac{5}{4}=-\dfrac{5}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=0\\3x=-\dfrac{5}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{5}{6}\end{matrix}\right.\)
Bài 1: Tìm x biết
1) |5x - 3| = |7 - x|
2) 2 |3 x - 1| - 3x = 7
3) |2x + 3| + 4 = -2x
4) |x + 3/4| - 1/3 = 0
5) 1,6 - |x + 1,5| = 0
6) |x - 1,5| + |2,5 - x| = 0
1) \(|5x-3|=|7-x|\)
\(\Leftrightarrow\orbr{\begin{cases}5x-3=7-x\\5x-3=x-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}6x=10\\4x=-4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{5}{3}\\x=-1\end{cases}}\)
Vậy...
2) \(2.|3x-1|-3x=7\)
\(\Leftrightarrow2.|3x-1|=7+3x\)
\(\Leftrightarrow\orbr{\begin{cases}2.\left(3x-1\right)=7+3x\\2.\left(3x-1\right)=-7-3x\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}6x-2=7+3x\\6x-2=-7-3x\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}3x=9\\9x=-5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=\frac{-5}{9}\end{cases}}\)
Vậy...
5) \(\text{1,6 - |x + 1,5| = 0}\)
\(|x + 1,5| = 1,6-0\)
\(\text{|x + 1,5| = 1,6}\)
\( |x | = 1,6-1,5\)
\(|x|=0,1\)
Tìm x:
2x^3+3x^2+2x+3=0
x^3-4x-14x(x-2)
(x-1,5)+2(15-x)^2=0
9(x-3)^2-4(x+1)^2
Tìm x:
a) 2/3 + 1/3 : x= 3/5
b) ( 2x/3 - 3 ) : (-10) = 2/5
c) | 2x + 1 | = 4
d) | 2x - 1 | +1 = 4
e ) 8 - | 1 - 3x | = 1/81
f) 1,5 x - 7/3 * x = 1,5 - 2/3
g) (1/2)^2x-1 = 1/8
h) ( -1/3 )^x-3 = 1/81
Bài 1: Tìm min (max) nếu có:
A= /3x-9/+1,5 C= -/\(\dfrac{1}{2}\).x-4/+13
B= /x-7/-14 D= -/1,5-x/-14
a: \(A=\left|3x-9\right|+1.5\ge1.5\forall x\)
Dấu '=' xảy ra khi x=3
b: \(B=\left|x-7\right|-14\ge-14\forall x\)
Dấu '=' xảy ra khi x=7
a, Ta có \(A=\left|3x-9\right|+1,5\)
Ta thấy: \(\left|3x-9\right|\ge0\Rightarrow\left|3x-9\right|+1,5\ge1,5\Rightarrow A\ge1,5\)
Dấy"=" xảy ra \(\Leftrightarrow3x-9=0\Leftrightarrow3x=9\Leftrightarrow x=3\)
Vậy \(A_{min}=1,5\Leftrightarrow x=0\)
b, Ta có \(B=\left|x-7\right|-14\)
Ta thấy: \(\left|x-7\right|\ge0\Rightarrow\left|x-7\right|-14\ge-14\Rightarrow B\ge-14\)
Dấu "=" xảy ra \(\Leftrightarrow x-7=0\Leftrightarrow x=7\)
Vậy \(B_{min}=-14\Leftrightarrow x=7\)
c, Ta có: \(C=-\left|\dfrac{1}{2}x-4\right|+13\Rightarrow C=13-\left|\dfrac{1}{2}x-4\right|\)
Ta thấy: \(\left|\dfrac{1}{2}x-4\right|\ge0\Rightarrow13-\left|\dfrac{1}{2}x-4\right|\le13\Rightarrow C\le13\)
Dấu "=" xảy ra \(\Leftrightarrow\dfrac{1}{2}x-4=0\Leftrightarrow\dfrac{1}{2}x=4\Leftrightarrow x=8\)
Vậy \(C_{max}=13\Leftrightarrow x=8\)
d, Ta có: \(D=-\left|1,5-x\right|-14\Rightarrow D=-14-\left|1,5-x\right|\)
Ta thấy: \(\left|1,5-x\right|\ge0\Rightarrow-14-\left|1,5-x\right|\le-14\Rightarrow D\le-14\)
Dấu "=" xảy ra\(\Leftrightarrow1,5-x=0\Rightarrow x=1,5\)
Vậy \(D_{max}=-14\Leftrightarrow x=1,5\)
Hoctot
Bài 2:Tìm x,biết:
1, 4/5-x=1/3
2, 2/3+5/3x=5/7
3, -12/13x+5=5 1/13
4, x:(-2 1/4)+1,5=-3/4
5,GTTĐ của x -3/4 - 1/4=0
6, 6-GTTĐ của 1/2-x = 2/3
7, (x-1)2=4/9
1) x = 4/5 - 1/3
x = 7/15
2) 5/3.x=1/21
x=1/35
3) -12/13.x = 1/13
x=-1/12
7) th1: x-1=2/3
x = 5/3
Th2: x - 1 = -2/3
x=1/3
Tìm x biết:
c) x3-18x2+108x-216=0
d) (x-1)3-x.(x2+3x)=2
e) (x+1)3+(x-2)3-2x2.(x-1,5)=3
Giải chi tiết giúp mình nha.Mình cần gấp.Cảm ơn
c)
\(x^3-3.x^2.6+3.x.6^2-6^3=0\)
\(\left(x-6\right)^3=0\)
x-6=0
x=6
d)
\(x^3-3.x^2.1+3.x.1^2-1-x^3-3x-2=0\)
\(x^3-3x^2+3x-1-x^3-3x^2-2=0\)
\(-6x^2-3=0\)
\(-3\left(2x^2+1\right)=0\)
\(2x^2+1=0\)
2x2=-1
x2=1/2
x=\(\dfrac{\sqrt{2}}{2}\)
Bài 1 (1,5 điểm). Tính bằng cách hợp lý.
a) 42. 53 + 47. 156 – 47. 114
b) 1152 – (374 + 1152) + (-65 + 374)
c) 1 – 2 + 3 – 4 + 5 – 6 + …- 210 + 211
Bài 2 (1,5 điểm). Tìm số nguyên x biết.
a) 5x + 3 – 5x + 2 = 12 500
b) (3x – 7) – (2x + 2) = - 15
Bài 3 (1,5 điểm). Chứng tỏ rằng:
a) 1 + 3 + 32 + 33 + … + 311 13
b) 4n + 3 và 6n + 5 nguyên tố cùng nhau với mọi n thuộc N
Bài 1:
a: =42x53+47x42
=42x100
=4200
b: =1152-374-1152-65+374=-65
c: =(-1)+(-1)+...+(-1)+211
=211-105
=106